A soccer player kicks the ball down the field to a teammate. The height of the soccer ball above the ground, h, in relation to the time in seconds, t, is represented by the quadratic function shown in the table.Time (seconds) Height (feet)
0 0
0.5 12
1 16
1.5 12
Use the table to complete the statements.

The height of the soccer ball above the ground is symmetric about the line t =
second(s).

The ball landed on the ground at t =
second(s).

Answers

Answer 1
Answer:

you can see that the height is the same at 0.5sec and 1.5 sec (12ft)

so therefore the height is symmetric about the line t=(midpoint of 0.5 and 1.5)

(0.5+1.5)/2=2/2=1

so the height is symmetric about the line t=1


the ball lands on the ground when height=0

since it is symmetric about t=1, and at t=0, the height is 0

1-0=1, so the difference between symmetry and desired height is 1

we must go in the oposite direction to find the next 0 height

so from symmetry to 0 height is 1+1=2, so at t=2 seconds

Answer 2
Answer:

Answer:

6,12

Step-by-step explanation:


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How to solve 9x+5=28
-3x-10y=-26 by Elimination

Answers

so elimination
I assume that you meant to write
9x+5y=28 and not 9x+5=28
so

elimination is basically eliminating values

9x+5y=28
-3x-10y=-26
we can either cancel out the x terms or the y terms, I will cancel out the y terms

9x+5y=28
multipy both sides by 2
18x+10y=56
add to other equation


18x+10y=56
-3x-10y=-26  +
15x+0y=30
15x=30
divide both sides by 15
x=2

subsitute

9x+5y=28
9(2)+5y=28
18+5y=28
subtract 10 from both sides
5y=10
divide both sides by 5
y=2


x=2
y=2

9x + 5 = 28
      - 5   - 5
      9x = 23
       9      9
        x = 2⁵/₉

-3(2⁵/₉) - 10y = -26
    -7²/₃ - 10y = -26
  + 7²/₃             + 7²/₃
            -10y = -18¹/₃
             -10      -10
                 y = 1⁵/₆
           (x, y) = (2⁵/₉, 1⁵/₆)

Mary bought 25/50/50 policy with a $100 deductible on collision and $500 deductible on comprehensive coverage. If the base premiums are $220, $245, $215, and $85, respectively, how much is his total base premium if her rating factor is 1.20?

Answers

Answer: 918

Step-by-step explanation:

add 220+245+215+85 together and you get $765 and you multiply this with the 1.20 to get your solution/answer Plz rate and <3

Answer: Option D: $918

Step-by-step explanation: Took The test! This is the correct answer

How can I do this exercice (n+1)!/(n+2)! ?

Answers

(n+1)! is equal to (n+1)*n*(n-1)*(n-2)...*3*2*1.  Basically, it multiplies together every positive integer that is at most n+1.  This is the definition of the !, or the factorial function.

(n+2)! is equal to (n+2)*(n+1)*n*(n-1)*(n-2)...*3*2*1, using the same definition.  This thus is equal to (n+1)!*(n+2), so we have:

(n+1)!/(n+1)!(n+2), or:

1/(n+2)

This is our final simplification.

Find the surface area of polyhedra
Pls!! show how you got the surface area ​​

Answers

Answer:

52.48

Step-by-step explanation:

find the cross sectional area which is the triangle

triangle = 1/2 x 8.2 x 6.4 = 26.24

then, use the area to multiply by the extended length of 2

26.24 x 2 = 52.48

A ball is thrown into the air from the top of a building. The height, h(1), of the ball above ground, t seconds after it isthrown, can be madeled by the function h(t) = -16t2 + 64t + 80. Based on the function, the "80"
represents what?
a. The time when the ball hits the ground
b. The distance the ball travels.
C. The speed of the ball
d. The initial height of the ball

Answers

Answer:

d

Step-by-step explanation:

dddddddddddddddddddd

The is d, the initial height of the ball

Joe solved this linear system correctly.6x+3y=6


y=−2x+2


These are the last two steps of his work.


6x−6x+6=6


6=6


Which statement about this linear system must be true?


a) x must equal 6

b) y must equal 6

c) there is no solution to this system

d) there are infinitely many solutions to this system

Answers

There are infinitely many solutions because the first two equations are actually the same just arranged differently so there's not enough information to know what x or y are in other words they could be anything.