The events A and B are mutually exclusive. If ​P(A)=0.1 and ​P(B)=0.4​, what is​ P(A or​ B)? ASAP

Answers

Answer 1
Answer:

Answer:

Given that the events A and B are mutually exclusive.

P(A) = 0.1

P(B) = 0.4

Mutually Exclusive Events: When two events are Mutually Exclusive it is impossible for them to happen together i.e

If A and B are two events then; P(A and B) = 0

then;

P(A or B) = P(A) +P(B)

By the definition of mutually exclusive events;

P(A or B) = P(A) +P(B)                     ......[1]

Substitute the values of P(A) = 0.1 and P(B) = 0.4 in [1] we have;

P(A or B) = P(A) +P(B) = 0.1+0.4 = 0.5





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Bruuuuuuuuu + bruh - brooo x π to the pawer of 420 = what please answer this seriously with evidence and reasoning

need help asap please help me if i get rong i will cry

Answers

Answer:

= bruv

Step-by-step explanation:

you spelt power wrong too

A publisher reports that 42%42% of their readers own a particular make of car. A marketing executive wants to test the claim that the percentage is actually different from the reported percentage. A random sample of 250250 found that 35%35% of the readers owned a particular make of car. Find the value of the test statistic. Round your answer to two decimal places.

Answers

Answer:

z=\frac{0.35 -0.42}{\sqrt{(0.42(1-0.42))/(250)}}=-2.24  

Step-by-step explanation:

Data given and notation  

n=250 represent the random sample taken

\hat p=0.35 estimated proportion of readers owned a particular make of car

p_o=0.42 is the value that we want to test

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that that the percentage is actually different from the reported percentage.:  

Null hypothesis:p=0.42  

Alternative hypothesis:p \neq 0.42  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{(p_o (1-p_o))/(n)}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.35 -0.42}{\sqrt{(0.42(1-0.42))/(250)}}=-2.24  

In the past, 44% of those taking a public accounting qualifying exam have passed the exam on their first try. Latterly, the availability of exam preparation books and tutoring sessions may have improved the likelihood of an individual’s passing on his first try. In a sample of 250 recent applicants, 130 passed on their first attempt. At the 0.05 level of significance, what is the calculated value of test statistic? (Specify your answer to the 2nd decimal.)

Answers

Answer:

The calculated value of test statistic is z=2.48.

This has a P-value of P=0.00657.

If we state the null hypothesis H_0: \pi\leq0.44 at a significance level of \alpha=0.05, we would reject this null hypothesis as P-value<\alpha.

Step-by-step explanation:

We have in this problem, a hypothesis test of proportions.

The test statistic for this is the z-value, and is calculated like that:

z=(p-\pi-0.5/N)/(\sigma)

Where the term 0.5/N is the correction for continuity and is negative in the cases that p>π.

p: proportion of the sample; π: proportion of the population; σ: standard deviation of the population.

The standard deviation of the population has to be calculated as:

\sigma=\sqrt{(\pi(1-\pi))/(N) } =\sqrt{(0.44(1-0.44))/(250) }=√(0.0009856)=0.0314

The proportion of the sample (p) is p=130/250=0.52.

Then, the test statistic z is

z=(p-\pi-0.5/N)/(\sigma)=(0.52-0.44-0.5/250)/(0.0314) =(0.078)/(0.0314) =2.48

The P-value of this statistic is P(z>2.48)=0.00657

If we state the null hypothesis H_0: \pi\leq0.44 at a significance level of \alpha=0.05, we would reject this null hypothesis as P-value<\alpha.

How does the quotient compare to the dividend when the divisor is less than 1

Answers

Final answer:

When a dividend is divided by a divisor that is less than 1, the resulting quotient is greater than the original dividend. This is equivalent to multiplying the dividend by the reciprocal of the divisor.

Explanation:

In mathematics, when we divide any number (the dividend) by a number that is less than 1 (the divisor), the quotient will be greater than the dividend. This is because dividing by a number less than 1 is equivalent to multiplying by its reciprocate which is more than 1. For example, let's consider 10 divided by 0.5 (which is less than 1); the quotient is 20, which is greater than the dividend (10). Therefore, in relation to your question, the quotient is larger than the dividend when the divisor is less than 1.

Learn more about Division here:

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Answer:

Greater provided the divisor is positive.

It would be more accurate and clearer to say that when dividing a number which is greater than zero by a number between 0 and 1, then the quotient is greater than the dividend.

If the divisor is negative and the dividend is positive, then the quotient is negative (and so less than the dividend).

Julia wrote 20 letters each month for y months in a row. Write an expression to show how many total letters Julia wrote.

Answers

20+y = 80 this is the answer to the expression

You read that a study is planned for which a test of hypothesis will be done at significance level α = 0.10. Statisticians have calculated that for a certain effect size, the power is 0.7. What are the probabilities of Type I and Type II errors for this test?

Answers

Answer:

The probabilities of Type I is 0.10.

The probability of type II error is 0.3

Step-by-step explanation:

Consider the provided information.

Type I error: If we reject the null hypothesis when null hypothesis is true then it is called type I error.

The type I error is denoted by α.

Type II error: If we fail to reject the null hypothesis when null hypothesis is false then it is called type II error.

The type II error is denoted by β.

It is given that significance level α = 0.10.

Thus, the probabilities of Type I is 0.10.

The power of the test is: Power=1-\beta

It is given that power is 0.7.

Therefore,

0.7=1-\beta

\beta=1-0.7=0.3

Hence, the probability of type II error is 0.3