What type of energy does a spinning turbine have?a. electrical energy
b. nuclear energy
c. thermal energy
d. mechanical energy

Answers

Answer 1
Answer:

The type of energy of a spinning turbine is mechanical energy. The answer is letter D. There are two types of modern wind turbines. In a Verical-axis wind turbines (VAWTs), the shaft is mounted on a vertical axis perpendicular to the ground. They are aligned with the wind so there’s no adjustment necessary when the wind direction changes. It can’t start moving on itself that is why it needs a boost from its electrical system to get started. It uses wires for support so the rotor elevation is lower. They are less efficient than HAWTs due to its lower elevation. Lower elevation means slower wind due to ground interferences. The other type is Horizontal-axis wind turbines (HAWTs), the shaft s mounted horizontally parallel to the ground. It is constantly aligned with the wind using a yaw-adjustment mechanism. This mechanism moves the entire rotor left or right in small increments. It uses a tower to lift the turbine components to an optimum elevation for wind speed and take up very little ground space. It is much more efficient than VAWT. 

Answer 2
Answer:

Answer: A ITS A BTW

Explanation:


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What kind of energy do most electric inventions give off?

Answers

Answer:

Electricity?

Explanation:

On a sky coaster (human pendulum) that reaches 20 meters from it's equilibrium position, a man of 70 kg is able to reach a maximum speed of

Answers

Answer:

Explanation:

Using the principle of conservation of energy, the potential energy is converted to kinetic energy, assuming any losses.

Kinetic energy is given by ½mv²

Potential energy is given by mgh

Where m is the mass, v is the velocity, g is acceleration due to gravity and h is the height.

Equating kinetic energy to be equal to potential energy then

½mv²=mgh

V

Making v the subject of the formula

v=√(2gh)

Substituting 9.81 m/s² for g and 20 m for h then

v=√(2*9.81*20)=19.799 m/s

Rounding off, v is approximately 20 m/s

Answer:

19.8 m/s

Explanation:

During the motion of a pemdulum bob, it casually converts kinetic energy to potential energy and vice versa.

A pendulum bob reaches its maximum speed at a position closest to its equilibrium position and has its lowest when it is farthest from the equilibrium position.

The maximum speed of a pendulum bob based on the mass involved and the maximum displacement from the equilibrium position is obtained from

Maximum kinetic energy = Maximum potential energy

Maximum potential energy occurs at the farthest point from equilibrium, that is,

P.E(max) = mgh

Maximum kinetic energy = ½mv²

½mv² = mgh

v = √2gh

g = acceleration due to gravity = 9.8 m/s²

h = farthest height from equilibrium position = 20 m

v = √(2×9.8×20) = 19.8 m/s

Hope this Helps!!!

A photon with a wavelength of 2.29 × 10^–7 meter strikes a mercury atom in the ground state.Calculate the energy, in joules, of this photon. [Show all work, including the equation and
substitution with units.]

Answers

Answer:

Energy of photon, E=8.64* 10^(-19)\ J

Explanation:

It is given that,

Wavelength of photon, \lambda=2.29* 10^(-7)\ m

It strikes a mercury atom in the ground state. We have to find the energy of this photon. It can be calculated using below relation as :

E=(hc)/(\lambda)

Where

h is the Planck's  constant

c is the speed of light

So, E=(6.6* 10^(-34)\ J-s* 3* 10^8\ m/s)/(2.29* 10^(-7)\ m)

E=8.64* 10^(-19)\ J

Hence, the above value is the energy of this photon.

detailed solution is attached

Monochromatic coherent light shines through a pair of slits. If the wavelength of the light is decreased, which of the following statements are true of the resulting interference pattern? (There could be more than one correct choice.) Check all that apply. Check all that apply. The distance between the maxima decreases.
The distance between the minima decreases.
The distance between the maxima stays the same.
The distance between the minima increases.
The distance between the minima stays the same.

Answers

The right answer for the question that is being asked and shown above is that: "The distance between the maxima stays the same; The distance between the minima stays the same.; . The distance between the maxima decreases."

What if the bird sitting on tansmission wire touches both terminal's wire ?why

Answers

There are no terminals on the wire where the bird is sitting.  If the bird wants terminals,
he must move to one end of the wire, but he will find only one terminal there.  The
other terminal is at the other end of the wire, conceivably hundreds of miles away. 
No species of bird extant in the modern world can accomplish such a span. 
Because the electrical current is activated

Explain how an EVEN PARITY Circuit would be created and show the EVEN PARITY TRUTH table. Please do this in multisim

Answers

Answer:

Explanation:

Creating an even parity circuit in Multisim involves designing a digital logic circuit that checks if the number of '1's in a binary input is even. If the input has an even number of '1's, the circuit should output '1' (indicating even parity); otherwise, it should output '0' (indicating odd parity).

Here's how to create an even parity circuit in Multisim, along with the truth table:

**Creating the Even Parity Circuit:**

1. Open Multisim and create a new blank schematic.

2. Add the following components to your schematic:

  - Input pins (for binary input bits)

  - XOR gates

  - An AND gate

  - An inverter (NOT gate)

  - Output display (LED or probe)

3. Connect the input pins to the XOR gates. Each input pin corresponds to one bit of the binary input.

4. Connect the outputs of the XOR gates to the inputs of the AND gate.

5. Connect the output of the AND gate to the input of the inverter (NOT gate).

6. Connect the output of the inverter to the output display.

7. Label your input pins for clarity (e.g., A0, A1, A2, ...).

**Designing the Even Parity Truth Table:**

To create the truth table for even parity, you'll need to list all possible input combinations (binary numbers) along with the corresponding output (even or odd).

Assuming you have a 3-bit input (A2, A1, A0), here's the truth table:

| A2 | A1 | A0 | Output (Even Parity) |

|----|----|----|-----------------------|

| 0  | 0  | 0  | 1 (Even)              |

| 0  | 0  | 1  | 0 (Odd)               |

| 0  | 1  | 0  | 0 (Odd)               |

| 0  | 1  | 1  | 1 (Even)              |

| 1  | 0  | 0  | 0 (Odd)               |

| 1  | 0  | 1  | 1 (Even)              |

| 1  | 1  | 0  | 1 (Even)              |

| 1  | 1  | 1  | 0 (Odd)               |

Each row in the truth table represents a unique combination of input bits (A2, A1, A0) and specifies whether the output is '1' (Even) or '0' (Odd).

Once you have created the circuit in Multisim and designed the truth table, you can simulate the circuit to verify its functionality. Ensure that the circuit produces the expected output (even parity) based on the input values.