classify these compounds by whether they behave as strong acids, weak acids, strong bases, or weak bases in aqueous solution.
Answers
For number one, the reaction is the neutralization of a strong acid and a strong base to yield a salt and water. The strong acid is the HCl and the strong base is NaOH. The salt is NaCl.
For number two, the equation is balanced. Na in the reactant side has one atom and also in the product side. O has only one atom in the product and in the reactant. There are 2H’s in the reactant and in the product side (present in H2O, the 2 in H stands for 2 atoms of H). One atom of Cl is present in the reactant and product side.
For number three, the reactants are NaOH-sodium hydroxide and HCl-hydrogen chloride(hydrochloric acid). The products are NaCl-sodium chloride and H2O-water.
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This reaction is best described as
(1) addition involving a saturated hydrocarbon
(2) addition involving an unsaturated hydrocarbon
(3) substitution involving a saturated hydrocarbon
(4) substitution involving an unsaturated hydrocarbon
Answers
This reaction is best described as substitution involving a saturated hydrocarbon. Therefore, the correct option is option C.
When one atom or group of atoms in a molecule is replaced by another atom or group of atoms, the chemical reaction is known as a substitution reaction. Usually, a reactant molecule and a reagent molecule, which supplies the replacing atom or group, engage in this reaction. Nucleophilic substitution and electrophilic substitution are the two primary categories of substitution processes. A nucleophile (a substance rich in electrons) can replace another atom or group in a molecule in nucleophilic substitution processes. A nucleophile combines with an electrophile (an electron-deficient species) in organic chemistry regularly to produce this kind of reaction, which results in the formation of a new molecule.
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involving a saturated hydrocarbon. You
have substitued a chlorine atom for one of the hydrogen atoms, and the hydrocarbon you start with (ethane) is fully saturated.
In chemistry we like the number of atoms or molecules in moles.
If one mole is equal to 6.02*10^23 atoms and you have 9.00 *10^23 atoms then how many moles do you have?
Answers
Answer;
= 1.495 moles
Explanation;
-One mole contains 6.02 ×10^23 particles
Therefore;
1 mole = 6.02 ×10^23 atoms
Thus; 9.00 ×10^23 atoms will have;
= 9.00 ×10^23 atoms / 6.02 ×10^23 atoms
= 1.495 moles
Answer:
2.49
⋅
10
−
12
moles Pb
Explanation:
Before doing any calculations, it's worth noting that atoms do not contain moles, it's the other way around.
A mole is simply a collection of atoms. More specifically, you need to have exactly
6.022
⋅
10
23
atoms of an element in order to have one mole of that element - this is known as Avogadro's number.
In your case, you must determine how many moles of lead would contain
1.50
⋅
10
12
atoms of lead.
Well, if you know that one mole of lead must contain
6.022
⋅
10
23
atoms of lead, it follows that you get
1.50
⋅
10
12
atoms of lead in
1.50
⋅
10
12
atoms of Pb
⋅
1 mole Pb
6.022
⋅
10
23
atoms of Pb
=
2.49
⋅
10
−
12
moles Pb
Answers
To change 1.34 kg of ice at 0°C to water, you would need to add approximately 448 kJ of heat.
To calculate the amount of heat needed to convert ice at 0°C to water, we use the formula Q = m * Lf. Where Q is the Heat Transfer, m is the mass of the substance (ice in this case), and Lf is the heat of fusion for ice, which is 334 kJ/kg.
Plugging in the values we have: Q = 1.34 kg * 334 kJ/kg = 447.56 kJ.
Therefore, you would need to add approximately 448 kJ of heat to convert 1.34 kg of ice at 0°C to water at the same temperature.
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The heat required to convert 1.34 kg of ice at 0°C to water at 0°C is approximately 450.24 kJ.
When the substance freezes (changes from liquid to solid), the same amount of energy is released back into the surroundings. When a substance changes its phase (solid to liquid or liquid to gas) at a constant temperature, the heat required for this process is known as the heat of fusion.
For ice at its meltingpoint (0°C), the heat of fusion is approximately 336 kJ/kg. Thus for 1.34 kg of ice, we can calculate the heat required by using the formula below:
Heat = mass × heat of fusion
Heat = 1.34 kg × 336 kJ/kg
Heat = 450.24 kJ.
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The complete question is -
How much heat (in kJ) must be added to 1.34 kg of ice at 0°C to convert it to water at 0°C
_Fe + _H₂SO₄ -> Fe₂ (SO₄)₃ _ H₂
Answers
hope this helps!
B) Cl < Cr < Ce
C) Ce < Cl < Co
D) Ca < Cu < Cl
Answers
b. the number of electrons
c. period 3
d. the third sub level e. Li
Answers
Answer: b. the number of electrons
Explanation:
1. 4 is the principal quantum number which describes the size of the orbital. It is represented by n.
2. The electrons are present in p sub shell also called as azimuthal quantum Number:This quantum number describes the shape of the orbital. It is represented as 'l'. The value of l ranges from 0 to (n-1). For p orbital, l=1.
3. The p subshell contains 3 electrons.