What is the half-life of sodium-25 if 1.00 gram of a 16.00-gram sample of sodium-25 remains unchanged after 237 seconds?(1) 47.4 s (3) 79.0 s
(2) 59.3 s (4) 118 s

Answers

Answer 1

Answer: Given,
1 gram remain out of 16 grams after 237 seconds.

So,
1g -> 2g -> 4g -> 8g -> 16g
So, 4 half lives have taken palce.

So,
we divide 237 by 4 and we get our answer.

So,
234 / 4 = 59.25 ≈ 59.3

So, the answer is (2) 59.3 seconds

Answer 2

Answer:

Final answer:

The half-life of sodium-25, when 1.00 gram of a 16.00-gram sample remains unchanged after 237 seconds, is approximately 59.3 seconds. This solution was found by calculating the number of times the sample halved and dividing the total time by this figure.

Explanation:

The question asks for the half-life of sodium-25 if 1.00 gram of a 16.00-gram sample remains unchanged after 237 seconds. In nuclear physics and nuclear chemistry, the half-life is the amount of time it takes for half of a sample of a radioactive substance to undergo decay.

Given that sodium-25 has gone from 16 grams to 1 gram, we can see that 1/16th of the original amount is left after 237 seconds. In other words, the quantity of sodium-25 has halved approximately 4 times. Therefore, the half-life will be the total time divided by the number of half-lives.

By dividing 237 seconds by 4, we get 59.25 seconds. So, the closest accurate answer is (2) 59.3s.

Learn more about Half-life here:

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