Consider the equation below. Zn + H2SO4 mc010-1.jpg ZnSO4 + H2 The mole ratio of zinc to zinc sulfate is

Answers

Answer 1

Answer:

Answer: The mole ratio of zinc to zinc sulfate is 1:1.

Explanation:

$Zn+ H_2SO_4\rightarrow ZnSO_4+H_2$

According to reaction,1 mole of zinc reacts with 1 mole of sulfuric acid to give 1 mole zinc sulfate and 1 mole of hydrogen gas .

So, the mole ratio of zinc to zinc sulfate is:

$\text{moles of}Zn:\text{moles of}ZnSO_4=1 mol:1 mol=1:1$

Hence, the mole ratio of zinc to zinc sulfate is 1:1.

Answer 2

Answer: Zn=65 grams/mole
20 grams/ (65 grams/mole)=0.31 moles of zinc
The molar ratio of Zn and H2 is 1 to 1, so 0.31 moles of H2 are also produced. The ratio is the same for the sulfuric acid. H2SO4=2*1+32+16*4=98 grams/mole
(98 grams/mole)*0.31 moles=30.4 grams of H2SO4.

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A solution is made by dissolving 10.20 grams of glucose (C6H12O6) in 355 grams of water. What is the freezing-point depression of the solvent if the freezing point constant is -1.86 °C/m? Show all of the work needed to solve this problem.

Answers

The freezing point constant means that the temperature depression when adding one mole of the solute. The mole number of the solute is 10.20/180=0.0567 mol. So the answer is 1.86*0.0567=0.105 ℃.

10.20 g C6H12O6 x (1 mole C6H12O6 / 180 g C6H12O6) = 0.0567 mole C6H12O6

Then convert grams of water to kilograms of water by dividing by 1000.

355 g / 1000 = .355 Kg of H2O

molality (m) = (0.0567 mole C6H12O6 / .355 Kg of H2O) = 0.160 m

Then plug it in to the formula Δtf = Kfm

Δtf = (-1.86 °C/m) x (0.160 m)

Δtf = -0.298 °C

What is the chemical formula for sodium sulfate?(1) Na2SO3 (3) NaSO3
(2) Na2SO4 (4) NaSO4

Answers

The chemical formula for Sodium Sulfate is Na2SO4.

The decayed organic material that gives soil its dark brown or black color is calledA) clay.
B) humus.
Eliminate
C) loam.
D) silt.

Answers

Option B. Humus. Its dark color is due to the high content of carbon.

Answer:

Answer is Humus

Explanation:

Which statement about one atom of an element identifies the element?(1) The atom has 1 proton. (2) The atom has 2 neutrons.(3) The sum of the number of protons and neutrons in the atom is 3.(4) The difference between the number of neutrons and protons in the atom is 1.

Answers

the atom has one proton

Calculate the percent by mass of the solute in each of the following aqueous solutions: (a) 5.50 g of NaBr in 78.2 g of solution, (b) 31.0 g of KCl in 152 g of water, (c) 4.5 g of toluene in 29 g of benzene.

Answers

Answer:

For a: The mass percent of NaBr is 7.03 %

For b: The mass percent of KCl is 16.94 %

For c: The mass percent of toluene is 13.43 %

Explanation:

To calculate the mass percentage of solute in solution, we use the equation:

$\text{Mass percent of solute}=\frac{\text{Mass of solute}}{\text{Mass of solution}}* 100$ .......(1)

For a:

We are given:

Mass of NaBr (Solute) = 5.50 g

Mass of solution = 78.2 g

Putting values in equation 1, we get:

$\text{Mass percent of NaBr}=(5.50g)/(78.2g)* 100\n\n\text{Mass percent of NaBr}=7.03\%$

Hence, the mass percent of NaBr is 7.03 %

For b:

We are given:

Mass of KCl (Solute) = 31.0 g

Mass of water (solvent) = 152 g

Mass of solution = (31.0 + 152) g = 183 g

Putting values in equation 1, we get:

$\text{Mass percent of KCl}=(31.0g)/(183g)* 100\n\n\text{Mass percent of KCl}=16.94\%$

Hence, the mass percent of KCl is 16.94 %

For c:

We are given:

Mass of toluene (Solute) = 4.5 g

Mass of benzene (solvent) = 29 g

Mass of solution = (4.5 + 29) g = 33.5 g

Putting values in equation 1, we get:

$\text{Mass percent of toluene}=(4.5g)/(33.5g)* 100\n\n\text{Mass percent of toluene}=13.43\%$

Hence, the mass percent of toluene is 13.43 %

Final answer:

To calculate the percent by mass of the solute in each aqueous solution, divide the mass of the solute by the mass of the solution and multiply by 100%

Explanation:

To calculate the percent by mass of the solute in each aqueous solution, you'll need to use the formula:

Percent by mass = (mass of solute/mass of solution) x 100%

For example, in solution (a) with 5.50 g of NaBr in 78.2 g of solution, the mass of the solute is 5.50 g and the mass of the solution is 78.2 g. Plugging these values into the formula gives:

Percent by mass = (5.50 g / 78.2 g) x 100% = 7.03%

Similarly, you can calculate the percent by mass for solutions (b) and (c) using the same formula.

Learn more about Calculating the percent by mass of solute in aqueous solutions here:

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Which of these does not describe the wright brothers first attempts at flight

Answers

Are there options for answers

As planned and went well. ( something positive most likely) but would need further info from the question to be sure

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