When fossil fuels are burned, _____ is released into the atmosphere.A. oxygen
B. nitrogen
C. ammonia
D. carbon dioxide

Answers

Answer 1
Answer:

Carbon dioxide. This is because when fossil fuels are burned, oxygen combines with carbon to form CO2 and with hydrogen to form water (H2O). These reactions release heat that we use for energy. For example, for the same amount of energy produced, burning natural gas produces about half of the amount of CO2 produced by burning coal.

Answer 2
Answer:

Final answer:

The burning of fossil fuels primarily releases carbon dioxide into the atmosphere, contributing to greenhouse gas emissions and global warming.

Explanation:

When fossil fuels are burned, carbon dioxide (CO₂) is predominantly released into the atmosphere. Fossil fuels, such as coal, oil, and natural gas, are composed mainly of carbon. During combustion, this carbon combines with oxygen in the air to form carbon dioxide. This process is a significant source of greenhouse gases, contributing heavily to global warming. It's important to note that other substances like water vapor and minor amounts of sulfur oxides can also be produced in this reaction, but the main product is carbon dioxide.

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Gaseous methane (CH₄) reacts with gaseous oxygen gas (O₂) to produce gaseous carbon dioxide (CO₂) and gaseous water (H₂O) If 0.391 g of carbon dioxide is produced from the reaction of 0.16 g of methane and 0.84 g of oxygen gas, calculate the percent yield of carbon dioxide.
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A gas contains a mixture of NH3(g) and N2H4(g), both of which react with O2(g) to form NO2(g) and H2O(g). The gaseous mixture (with an initial mass of 61.00 g) is reacted with 10.00 moles O2, and after the reaction is complete, 4.062 moles O2 remains. Calculate themass percent of N2H4(g) in the original gaseous mixture.

How many grams of hydrogen peroxide (H2O2) must be added to 1,500 ml of water to produce a concentration of 1.33 m (molal solution)

Answers

I hope it helped you out.

Consider the reaction. mc015-1.jpg How many grams of N2 are required to produce 100.0 L of NH3 at STP?

Answers

The  grams  of N2  that  are   required   to  produce 100.0 l  of  NH3   at  STP

At  stp 1moles = 22.4  l. what  about  100.0 L of NH3

= 100 / 22.4 lx1  moles = 4.46  moles  of NH3

write the reacting  equation

N2+3H2 =2NH3
by use of mole  ratio  between  N2  to NH3  which is  1:2 the moles of N2 =4.46/2 =2.23  moles of N2

mass =  moles  x  molar  mass

=  2.23moles  x 28  g/mol =  62.4 grams

Final answer:

To produce 100.0 L of NH3 at STP, 62.4 grams of N2 are required.

Explanation:

The balanced equation for the reaction is:

N2(g) + 3H2(g) → 2NH3(g)

According to the balanced equation, one mole of N2 reacts with three moles of H2 to produce two moles of NH3. From this information, we can use stoichiometry to determine the mass of N2 required to produce 100.0 L of NH3 at STP.

First, we need to convert liters of NH3 to moles using the ideal gas law and the molar volume of a gas at STP (~22.4 L/mol). Once we have the moles of NH3, we can use the mole ratio from the balanced equation to calculate the moles of N2. Finally, we can use the molar mass of N2 to convert moles to grams.

Let's calculate:

  1. Convert liters of NH3 to moles of NH3: 100.0 L * (1 mol/22.4 L) = 4.46 mol NH3
  2. Calculate moles of N2 using the mole ratio: 4.46 mol NH3 * (1 mol N2/2 mol NH3) = 2.23 mol N2
  3. Convert moles of N2 to grams of N2 using the molar mass of N2 (28 g/mol): 2.23 mol N2 * 28 g/mol = 62.4 g N2

Therefore, 62.4 grams of N2 are required to produce 100.0 liters of NH3 at STP.

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What is the molality of a solution containing 125 grams of iodine (I2) and 750 grams of CCl4? A. 1.2 m. . B. 6.57 m. . C. 0.657 m. . D. 0.12 m.

Answers

The answer is C. 0.657 m.

The molality is the number of moles of solute divided by kilograms of solvent. In a solution, solute the component which is present in lesser amount while solvent is present in greater amount. Thus, I2 is solute, and CCl4 is solvent.

So, first we need to calculate moles of I2:
Atomic mass of iodine: A(I) = 126.9
Molecular mass of iodine: Mr(I2) = 2*A(I) = 2 * 126.9 = 253.8
This means there are 253.8 g of iodine in 1 mole. So, 125 g of iodine will be in how many moles?
253.8 : 1 = 125 : x         ⇒      x = 125/253.8 = 0.493 moles

Now, let's convert amount of CCl4 in kilograms (1 kg = 1000 g):
750 g = 750/1000 kg = 0.75 kg

And now, it's only left to calculate molality of the solution:
numbers of moles of solute/kilograms of solvent = 0.493 moles/0.75 kg = 0.657 m

Which best describes a reaction in a state of equilibrium? A. The rates of the forward and reverse reactions are zero and the concentrations of products

and reactants are equal.

B. The rate of the forward reaction equals the rate of the reverse reaction and the

concentrations of products and reactants are equal.

C. The rates of the forward and reverse reactions are zero and the concentrations of products

and reactants are constant.

D. The rate of the forward reaction equals the rate of the reverse reaction and the

concentrations of products and reactants are constant.

Answers

The best statement which describes a reaction in a state of equilibrium is letter D.  The rate of the forward reaction equals the rate of the reverse reaction and the concentrations of products and reactants are constant. 

>Chemical equilibrium is defined as the state in which both reactants and products are present in concentrations which have no further tendency to change with time. This state results when the forward reaction proceeds at the same rate as the reverse reaction. The reaction rates of the forward and backward reactions are generally not zero, but equal. Thus, there are no net changes in the concentrations of the reactant(s) and product(s).

 

What did Thomson’s model of the atom include that Dalton’s model did not have?

Answers

Thomson's model included Protons and Electrons. His model is referred to as 'Plum Pudding' because of it.

Answer: subatomic particles: negative charges (electrons) distributed in a mass of positive charge.

Explanation:

1) John Dalton's model depicted the matter as the combination of tiny, indivisible particles, called atoms.

According to this model, atoms can not be created, destroyed, or divided into smaller particles.

2) When it was discovered that all forms of matter contained negative particles, by multiple experiments with cathode ray tubes, those particles where named electrons.

3) J.J. Thompson could determine that the mass of those negative charges was much smaller that the mass of the smallest atom (hydrogen). Concluding that existed smaller particles than the atom. Hence, Dalton's model was wrong: atoms was divisible into smaller subatomic particles.

4) Then J.J Thompson proposed the plum pudding model, in which the electrons (plums) are embeded into a uniform positive mass (pudding).

How would you prepare 2.5 L of a 0.800M solution of KNO3?

Answers

First  find the mass of solute:

Molar mass KNO
₃ = 101.1032 g/mol

mass =  Molarity * molar mass * volume

mass = 0.800 * 101.1032 * 2.5

mass = 202.2064 g of KNO


To prepare 2.5 L (0800 M) of KNO3 solution, must weigh 202.2064 g of salt, dissolve in a Beker, transfer with the help of a funnel of transfer to a volumetric flask, complete with water up to the mark, capping the balloon and finally shake the solution to mix.

hope this helps!