Gaseous methane (CH₄) reacts with gaseous oxygen gas (O₂) to produce gaseous carbon dioxide (CO₂) and gaseous water (H₂O) If 0.391 g of carbon dioxide is produced from the reaction of 0.16 g of methane and 0.84 g of oxygen gas, calculate the percent yield of carbon dioxide.

Answers

Answer 1
Answer:

Answer : The percent yield of CO_2 is, 68.4 %

Solution : Given,

Mass of CH_4 = 0.16 g

Mass of O_2 = 0.84 g

Molar mass of CH_4 = 16 g/mole

Molar mass of O_2 = 32 g/mole

Molar mass of CO_2 = 44 g/mole

First we have to calculate the moles of CH_4 and O_2.

\text{ Moles of }CH_4=\frac{\text{ Mass of }CH_4}{\text{ Molar mass of }CH_4}=(0.16g)/(16g/mole)=0.01moles

\text{ Moles of }O_2=\frac{\text{ Mass of }O_2}{\text{ Molar mass of }O_2}=(0.84g)/(32g/mole)=0.026moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

CH_4+2O_2\rightarrow CO_2+2H_2O

From the balanced reaction we conclude that

As, 2 mole of O_2 react with 1 mole of CH_4

So, 0.026 moles of O_2 react with (0.026)/(2)=0.013 moles of CH_4

From this we conclude that, CH_4 is an excess reagent because the given moles are greater than the required moles and O_2 is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of CO_2

From the reaction, we conclude that

As, 2 mole of O_2 react to give 1 mole of CO_2

So, 0.026 moles of O_2 react to give (0.026)/(2)=0.013 moles of CO_2

Now we have to calculate the mass of CO_2

\text{ Mass of }CO_2=\text{ Moles of }CO_2* \text{ Molar mass of }CO_2

\text{ Mass of }CO_2=(0.013moles)* (44g/mole)=0.572g

Theoretical yield of CO_2 = 0.572 g

Experimental yield of CO_2 = 0.391 g

Now we have to calculate the percent yield of CO_2

\% \text{ yield of }CO_2=\frac{\text{ Experimental yield of }CO_2}{\text{ Theretical yield of }CO_2}* 100

\% \text{ yield of }CO_2=(0.391g)/(0.572g)* 100=68.4\%

Therefore, the percent yield of CO_2 is, 68.4 %


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Answers

m = mass of the block of iron = 25 g

Q = heat absorbed by the block of iron = 1200 J

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Answers

If it is assumed that this reaction is taking place at STP (standard temperature and pressure) then one mole of gas occupies 22.4L 

You can then calculate that 3.6L of Hydrogen contains 0.16mol 
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Answers

US participation in world war 1 affect the american civilian population in this following way : women had to get jobs and get more opportunities
Since the majority of the men have to go to the war, the business in the homeland was being taken care of by women

hope this helps

Answer:

explained below.

Explanation:

World war 1  leads to suffer the Americans people a lot .

Young men were forced to go for war which leads to the deplete the financial condition of the house hold. Industry starts to suffer a lot as most of the people who were working has to go for war and man power decreases.

Which leads women to come out of there houses and took job for them so, that they can full fill there needs which starts the new era where woman also start working with men.

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Answers

The class of organic compounds that contains nitrogen is (3) amine.

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Hence, the correct option is an amine option 3.

Learn more about amine here:

brainly.com/question/31391643

#SPJ 6

The answer is (3)amine. The aldehyde structure is -CHO. The alcohol structure is  -OH. The amine structure is -NH2. And the ether structure is R-O-R'. The "R" means other function groups.

Which step would help a student find the molecular formula of a compound from the empirical formula?Multiply the ratio of the actual mass of the compound to the empirical formula mass by the subscripts of the empirical formula.

Subtract the ratio of the actual mass of the compound to the empirical formula mass from the subscripts of the empirical formula.

Divide the ratio of the actual mass of the compound to the empirical formula mass by the subscripts of the empirical formula.

Add the ratio of the actual mass of the compound to the empirical formula mass to the subscripts of the empirical formula.

Answers

Answer : Option A) Multiply the ratio of the actual mass of the compound to the empirical formula mass by the subscripts of the empirical formula.

Explanation : To find molecular formula for a compound one needs to follow the below steps using the emphirical formula of that compound.

Step 1) Calculate the empirical formula mass of that compound

Step 2) Take the ratio of gram molecular mass by the empirical formula mass that was obtained in step 1.

Step 3) Multiply each of the subscripts within the empirical formula by the number that is calculated in step 2.

By following these easy steps one can find the molecular formula.

The step that would help a student finds the molecular formula of a compound from the empirical formula is by ‘Multiply the ratio of the actual mass of the compound to the empirical formula mass by the subscripts of the empirical formula.’

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Answers

Answer:

one more proton

Explanation:

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