What is the shallowest part of the ocean ecosystem?

Answer:The pure substance within chemistry is a very simple concept to grasp. Pure substances are defined as substances that are made of only one type of atom or only one type of molecule (a group of atoms bonded together). ... Purity can also have an important impact on the chemical properties of a substance.

Explanation:

Answer:

848.1 g/mol

Explanation:

Data given:

Standard of atomic mass of Ca = 50 amu

molar mass of Aluminium Acetate = ?

Solution:

Relative atomic mass represented by Ar. It is ratio of actual mass with respect to the 1/12th mass of C-12 but here Ca-50 is standard.

Formula of  Aluminium Acetate = Al(CH₃COO)₃

In order to calculate Ar

first we will calculate 1/50 of Ca

As we know

         mass of 1/12 of C-12 = 1.993 x 10⁻²⁶/12 = 1.661 x 10⁻²⁷ Kg

So, for Ca-50

        mass of 1/50 of Ca-50 = 1.993 x 10⁻²⁶/50 = 3.986 x 10⁻²⁸ Kg

Now

 Relative Atomic mass for element X = rest mass of "X"/ 3.986 x 10⁻²⁸ Kg . . . . . . (1)

First we have to know the relative atomic masses of Aluminium, carbon, hydrogen, oxygen atoms involve in Aluminium Acetate formula with respect to new standard Ca-50

By using equation-1 we can calculate Ar for which we have reported rest masses of atoms as below

Rest mass of Aluminium = 4.48 x 10⁻²⁶ Kg

Rest mass of carbon = 1.993 x 10⁻²⁶ Kg

Rest mass of hydrogen = 1.608 x 10⁻²⁷ Kg

Rest mass of oxygen = 2.657x10⁻²⁶ Kg

Now put values in equation 1 for each atom

• Ar for Aluminium= 4.48 x 10⁻²⁶Kg / 3.986 x 10⁻²⁸ Kg

                     Ar for Aluminium = 112.5  amu

• Ar for Carbon= 1.993 x 10⁻²⁶ Kg / 3.986 x 10⁻²⁸ Kg

                     Ar for Carbon= 50 amu

• Ar for Hydrogen = 1.608 x 10⁻²⁷ Kg / 3.986 x 10⁻²⁸ Kg

                     Ar for hydrogen = 4  amu

• Ar for Oxygen = 2.657x10⁻²⁶ Kg / 3.986 x 10⁻²⁸ Kg

                     Ar for Oxygen = 66.6  amu

Now find the molar mass ofAl(CH₃COO)₃

molar mass of Aluminium Acetate = Al(CH₃COO)₃

Al(CH₃COO)₃ = 112.5 + 3 (50 + 3(4) + 50 + 66.6 +66.6)

Al(CH₃COO)₃ = 112.5 + 3 (50 + 12 + 50 + 66.6 +66.6)

Al(CH₃COO)₃ = 112.5 + 3 (245.2)

Al(CH₃COO)₃ = 112.5 + 735.6

Al(CH₃COO)₃ = 848.1 g/mol

molar mass of Aluminium Acetate = 848.1 g/mol

Explanation:

probably because, X rays are used to ionise the gas molecules, which is loss of electrons, these electrons are absorbed by oil drops