a bullet of mass m is fired into a block of mass m that is at rest. the block, with the bullet embedded, slides distance d across a horizontal surface. the coefficient of kinetic friction is μk.

Answers

Answer 1

Answer:

The expression for the bullet's speed vbullet is $v=\sqrt{(2\mu_k (m+M)gd)/(m)}$ and the speed of a 9.0 g bullet is v=16.8 m/s

Explanation:

A bullet of mass m is fired into a block of mass m that is at rest. the block, with the bullet embedded, slides distance d across a horizontal surface. the coefficient of kinetic friction is μk.

The initial kinetic energy of the bullet is given by

$K_i = (1)/(2)mv^2$

where

m is the mass of the bullet

v is the initial speed of the bullet

The expression for the bullet's speed vbullet is

$F=\mu_k (m+M) g$

where

$\mu_k$ is the coefficient of kinetic friction

g is the acceleration of gravity

The work done by the force of friction is

$W=-Fd = -\mu_k (m+M)g d$

where d is the displacement of the block+bullet.

Because the final kinetic energy is zero (the bullet with the block comes at rest), we can write:

$W=K_f - K_i = -K_i$

And so

$-\mu_k (m+M) g d = -(1)/(2)mv^2$

By solving for v, the solution for the bullet speed:

$-\mu_k (m+M) g d = -(1)/(2)mv^2\nv=\sqrt{(2\mu_k (m+M)gd)/(m)}$

The speed of a 9.0 g bullet that, when fired into a 12 kg stationary wood block causes the block to slide 5.4 cm across a wood table. Assume that k=0.20.

We have:

the mass of the bullet, m = 9.0 g = 0.009 kg

the mass of the block, M = 12 kg

the distance covered by the block+bullet, d = 5.4 cm = 0.054 m

the coefficient of friction, $\mu_k = 0.20$

the acceleration of gravity, $g = 9.8 m/s^2$

By substituting, we got

$v=\sqrt{(2 (0.20) (0.009 kg+12 kg)(9.8 m/s^2)(0.054 m))/(0.009 kg)}=16.8 m/s$

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Answer 2

Answer: uk=2m*the normal force
the distance d is needed only if you were asked about work

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How many g in 6 1/2 kg

Answers

there are 6,500 grams in 6 1/2 kilograms

Question 1.1. Using correct biomechanics helps maximize sport performance. True
False

Question 2.2. The "Fosbury Flop" is named because his idea didn't work.
True
False

Question 3.3. Using correct biomechanics will actually decrease your chances of injury.
True
False

Answers

Question 1.1.True Question 2.2.False
Question 3.3.True
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Which shows the correct order of forces, from weakest to strongest?o weak, strong, gravitational, electromagnetic
O electromagnetic, weak, strong, gravitational
O gravitational, weak, electromagnetic, strong
O weak, electromagnetic, gravitational, strong

Answers

Answer: C. gravitational, weak, electromagnetic, strong

Explanation:

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Answer:Helle dudes

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When the sun warms the sidewalk on a hot sunny day, what type of energy conversion occurs?

Answers

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Radiation I believe.

What is the potential energy of a 2-kilogram potted plant that is on a 1 meter-high plant stand?

Answers

Potential energy is the energy stored by an object due to its position or arrangement.

The potential energy of the potted plant is 19.6 joule.

What is the potential energy?

Potential energy is the energy stored by an object due to its position or arrangement.

It can be given as,

$U=mgh$

Here, $m$ is the mass of the object, $g$ is the gravitational force experienced by the object and $h$ is the height.

Given information-

The mass of the potted plant is 2 kilogram.

The height of the plant stand is 1 meter.

The value of the gravity force is 9.81 meter per second squared on the surface of the earth.

To find the potential energy put the values in the above formula as,

$U=2*9.81*1\nU=19.6$

Hence the potential energy of the potted plant is 19.6 joule.

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Final answer:

The potential energy of a 2-kilogram potted plant on a 1 meter-high plant stand is 19.6 J.

Explanation:

The potential energy of a 2-kilogram potted plant on a 1 meter-high plant stand can be calculated using the gravitational potential energy formula:

PE = mgh

Where:

PE is the potential energy
m is the mass (2 kg)
g is the acceleration due to gravity (9.8 m/s²)
h is the height (1 meter)

Substituting the values into the formula:

PE = (2 kg)(9.8 m/s²)(1 meter) = 19.6 J

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Answers

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