PHYSICS HIGH SCHOOL

The expiration date on a product refers to the last date a product should be __________.

Answers

Answer 1

Answer: It refers to the date where a product should no longer be eaten and isn't fresh enough

Answer 2

Answer:

The expiration date on a product refers to the last date a product should be used

or should be costumed by

I hope that's help !

Related Questions

Two equal point charges QQQ are separated by a distance ddd. One of the charges is released and moves away from the other due only to the electrical force between them. When the moving charge is a distance 3ddd from the other charge, what is its kinetic energy?
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A juggler throws a bowling pin straight up with an initial speed of 9.20m/s. How much time elapses before the pin reaches the juggler's hands?

Answers

Answer:

1.87 s

Explanation:

Initial speed of throw = 9.20 m/s

Net vertical displacement = 0

The bowling pin would be in free fall i.e. a = 9.8 m/s²

Use the second equation of motion:

s = ut + 0.5at²

0 = (9.20)t-0.5(9.8)(t²)

9.20 = 4.9 t

⇒t = 1.87 s

Thus, the total time of flight, the time elapses before the bowling pin falls in juggler's hand is 1.87 s.

A juggler throws a bowling pin straight up with an initial speed, the time that elapses before the pin reaches the juggler's hands is 1.88 s.

Given:
Initial speed, u = 9.2 m/s

The time can be calculated from the second equation of motion. The second equation of motion provides a relation between height, initial speed, acceleration, and time respectively.

From the second equation of motion:

h = ut + at²

When the ball reaches the hands, the distance becomes zero. Therefore, the time is:

0 = 9.2t -0.5 × 9.8t²

9.8t = 18.4

t = 18.4÷ 9.8

t = 1.88 s

Hence, the time that elapses before the pin reaches the juggler's hands is 1.88 s.

To learn more about time, here:

brainly.com/question/82806

#SPJ6

Work is being done in which of these situations? all motions are at a constant velocity

Answers

Where the force is not perpendicular to the path of motion

are you missing the the situations ?

Find the total displacement of a mouse that travels 1.0m north and then 0.8m south.

Answers

In this case two vectors are colinear and they have an opposite orientation.
N + ( - S ) = N - S = 1 m - 0.8 m = 0.2 m
Answer:
The total displacement is 0.2 m north.

At the beginning of a basketball game, a referee tosses the ball straight up with a speed of 4.6 m/s. a player cannot touch the ball until after it reaches its maximum height and begins to fall down. what is the minimum time that a player must wait before touching the ball? s

Answers

At the beginning of a basketball game, a referee tosses the ball straight

up with a speed of 4.6 m/s. a player cannot touch the ball until after it reaches its maximum height and begins to fall down. what is the minimum time that a player must wait before touching the ball? s

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kinemaic equation

v=u-at

0=4.6-9.81xt

t=4.6/9.81 ... about half a second

a warrior swings a slingshot in a horizontal circle above his head at a constant speed. The sling is 1.5 m long, and the stone has a mass of 50 g. The tension in the string is 3.3 N. When he releases the sling, what will the stone's speed be?

Answers

The speed of the stone when he releases the sling is equal to 9.95 m/s.

Given the following data:

Length of sling (radius) = 1.5 meter

Mass of stone = 50 grams to kg = 0.05 kg

Tension = 3.3 Newton

To determine the speed of the stone when he releases the sling:

First of all, we would solve for the angular velocity of the stone by applying

the law of conservation of momentum.

Tension in the string = Centrifugal force of the stone

$Tension = mrw^2$

$\omega = \sqrt{(Tension)/(mr) } \n\n\omega = \sqrt{(3.3)/(0.05 * 1.5) }\n\n\omega = √(44)$

Angular velocity = 6.63 rad/s

Now, we can determine the speed of the stone when he releases the sling:

$V = r\omega\n\nV=1.5 * 6.63$

Speed, V = 9.95 m/s

r = 1.5 m , m = 0.05 kg
Tension = Centrifugal force
T= mrw² , w = angular velocity
3.3 N = 0.05 x 1.5 x w²
w = 6.63 rps
Linear Velocity = rw = 1.5 x 6.63 = 9.945 m/s

What are the basics of physics.I want to learn them for an exam?

Answers

If it were possible to give that information over in a few paragraphs or a few mimutes, then you'd see little stores everywhere, where you could drop in for an hour or an afternoon, pay a few bucks, and learn Physics. You don't, because you can't, because it isn't. Here are a few things you definitely need. But I have to tell you: If you don't put time and effort into learning them, they won't do you much good. ==> F=m a. ==> Total mass is conserved. ==> Total energy is conserved. ==> Everything falls at the same rate. ==> Sound needs material to travel through. Light doesn't. ==> Light, radio, heat, X-rays, and ultraviolet radiation are all the same thing. ==> It takes force on an object to make it speed up, slow down, or curve. A moving object with no force acting on it keeps going in a straight line at the same speed forever. ==> Gravity attracts every speck of mass in the universe to every other speck. The forces of attraction are greater when the masses are greater and closer together.

one cannot simply give the basics of physics.

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