HELP PLEASE. Predict the new element formed when u-238 undergoes 2 alpha decay, 1 beta decay, and 1 gamma radiation. Write nuclear equation.

Answers

Answer 1

Answer:

This hypothetical process would produce actinium-230.

Explanation

An alpha decay reduces the atomic number of a nucleus by two and its mass number by four.

There are two types of beta decay: beta minus β⁻ and beta plus β⁺.

The mass number of a nucleus stays the same in either process. In β⁻ decay, the atomic number increases by one. An electron e⁻ is produced. In β⁺ decay, the atomic number decreases by one. A positron e⁺ is produced. Positrons are antiparticles of electrons.

β⁻ are more common than β⁺ in decays involving uranium. Assuming that the "beta decay" here refers to β⁻ decay.

Gamma decays do not influence the atomic or mass number of a nucleus.

Uranium has an atomic number of 92. 238 is the mass number of this particular isotope. The hypothetical product would have an atomic number of 92 - 2 ⨯ 2 + 1 = 89. Actinium has atomic number 89. As a result, the product is an isotope of actinium. The mass number of this hypothetical isotope would be 238 - 2 ⨯ 4 = 230. Therefore, actinium-230 is produced.

The overall nuclear reaction would involve five different particles. On the reactant side, there is

one uranium-238 atom.

On the product side, there are

one actinium-230 atom,
two alpha particles (a.k.a. helium-4 nuclei),
one electron, and
one gamma particle (a.k.a. photon).

$\;_{\phantom{2}92}^(238) \text{U} \to \;_{\phantom{2}89}^(230) \text{Ac} + \;_(2)^(4) \text{He} + \;_(2)^(4) \text{He} + \text{e}^(-) + \gamma$

Consider: what would be the products if the nucleus undergoes a β⁺ decay instead?

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Which equation represents a decomposition reaction?(1) CaCO3(s) ==>CaO(s) + CO2(g)
(2) Cu(s) + 2AgNO3(aq) ==>2Ag(s) + Cu(NO3)2(aq)
(3) 2H2(g) + O2(g) ==>2H2O(l)
(4) KOH(aq) + HCl(aq) ==>KCl(aq) + H2O(l)

Answers

Answer : The correct option is, (1)

Explanation :

The option (1) reaction is an example of decomposition reaction because in this reaction the larger compound, calcium carbonate decomposes into smaller molecule, calcium oxide and carbon dioxide.

Decomposition reaction : It is a type of reaction in which a larger compound decomposes into a smaller molecule or elements.

$AB\rightarrow A+B$

The option (2) reaction is an example of single displacement reaction because in this reaction the most reactive metal, copper displace the less reaction metal, silver.

The option (3) reaction is an example of combination reaction because in this reaction two reactants, hydrogen and oxygen react to give a single product as water.

The option (4) reaction is an example of double displacement reaction because in this reaction a positive cation and a negative anion of two reactants exchange their places to give two new products.

Hence, the correct option is, (1)

Answer (1 )

CaCO3(s) ==>CaO(s) + CO2(g)

hope this helps!.

On a mission to a newly discovered planet, an astronaut finds copper abundances of 69.97 % for 63Cu and 31.03 % for 65Cu. What is the atomic mass of copper for this location? The mass of 63Cu is 62.9300 amu . The mass of 65Cu is 64.9200 amu . Express your answer to two decimal places, and include the appropriate units.

Answers

Okay so to find the average atomic mass of copper in this location, you want to take the percentage of abundance of an isotope and multiply (in decimal form) that by it's atomic mass, then you would add that with the product of the % of abundance of the other isotope times it's atomic mass.

(Side Note: Isotopes are atoms of the element that have the SAME number of protons but different number of neutrons, so they have different mass numbers. Also average atomic mass is the average of all the isotopes in an element - this number is the one that is shown on the periodic table of elements, not mass number).

Let me show you how to do this..

For the isoptope 63Cu I will first need to convert it's percentage of abundance into a decimal, because we don't use the percentage to multiply. 69.97% -> 0.6997. Now I am going to take it's atomic mass 62.9300 and multiply that by 0.6997.

62.9300*0.6997=44.0321

Now we still need to find calculate this for the isotope 65Cu. To convert 31.03% to a decimal I will just move the decimal point two places to the left, to get 0.3103.
So I am going to take this and multiply it by 64.9200 the atomic mass of the isotope 65Cu.

64.9200*0.3103=20.1447

Add the two of these to get the average atomic mass..
20.1447 + 44.0321=64.1768

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