High color saturation produces gray tones.

Answers

Answer 1
Answer: If this is a true of false question, note that it's false. Unsaturating the color, meaning giving it a lower amount up to zero, can cause gray tones - especially when it comes to pictures when editing it. High color saturation can make the color tone very vivid.

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Each type of mineral has a chemical composition that isA. unique to that mineral
B. similar to other minerals
C. variable depending on where its found
D. influenced by heat and light

Answers

Answer: C. variable depending on where its found

The chemical compositions of minerals is very necessary in order to define or describe a certain mineral. Some minerals can be written in simple chemical formula while others are also written in complicated chemical formulas.

What is the approximate mass of one mole of oxygen gas (O2)?a. 8 g
b. 16 g
c. 32 g
d. 1.204 × 1024

Answers

The correct answer is B.

1 mol O2  x  15.999 O2/ 1 mol O2 = 15.999 O2

16 O2 when rounded.

How many grams of NH3 can be produced from 4.54 mol of N2 and excess H2?

Answers

First we make a Balanced Chemical Equation:

N_(2) + 3H_(2) = 2NH_(3)


Now we can solve using the Mole Ratio:

4.54 mol N2 × 2 / 1 × 17.04 g/mol NH3 
= 154.72 g

If you need further clarification, feel free to comment. 

An analysis of an oxide of nitrogen with a molecular weight of 92.02 amu gave 69.57% oxygen and 30.43% nitrogen. What are the empirical and molecular formulas for this nitrogen oxide? Complete and balance the equation for its formation from the elements nitrogen and oxygen.

Answers

The empirical formula is  No2   and molecular formula is N2O4

empirical formula calculation

find the moles of each reactant

=% composition/molar mass

molar mass of oxygen=16 g/mol ,while hat of nitrogen= 14 g/mol from periodic table

moles is therefore=

                           nitrogen=  30.43/14=2.174 moles

                            oxygen=  69.57/1 6=4.348 moles

find the mole ratio by dividing each moles with smallest number of mole( 2.174)

                        nitrogen = 2.174/2.174= 1

                       oxygen = 4.348/2.174=2


The balanced equation  for its formation from the element nitrogen and oxygen is as below

N2 +2 O2 → N2O4

therefore the empirical formula= NO2

molecular  formula  calculation

[NO2] n= 92.02 amu

[(14) + (16x2)]n = 92.02 amu

46n= 92.02

divide both side by 46

n=2

therefore the molecular formula is gotten by multiplying the empirical formula by 2= [NO2]2= N2O4


HELP PLEASE. Predict the new element formed when u-238 undergoes 2 alpha decay, 1 beta decay, and 1 gamma radiation. Write nuclear equation.

Answers

This hypothetical process would produce actinium-230.

Explanation

An alpha decay reduces the atomic number of a nucleus by two and its mass number by four.

There are two types of beta decay: beta minus β⁻ and beta plus β⁺.

The mass number of a nucleus stays the same in either process. In β⁻ decay, the atomic number increases by one. An electron e⁻ is produced. In β⁺ decay, the atomic number decreases by one. A positron e⁺ is produced. Positrons are antiparticles of electrons.

β⁻ are more common than β⁺ in decays involving uranium. Assuming that the "beta decay" here refers to β⁻ decay.

Gamma decays do not influence the atomic or mass number of a nucleus.

Uranium has an atomic number of 92. 238 is the mass number of this particular isotope. The hypothetical product would have an atomic number of 92 - 2 ⨯ 2 + 1 = 89. Actinium has atomic number 89. As a result, the product is an isotope of actinium. The mass number of this hypothetical isotope would be 238 - 2 ⨯ 4 = 230. Therefore, actinium-230 is produced.

The overall nuclear reaction would involve five different particles. On the reactant side, there is

  • one uranium-238 atom.

On the product side, there are

  • one actinium-230 atom,
  • two alpha particles (a.k.a. helium-4 nuclei),
  • one electron, and
  • one gamma particle (a.k.a. photon).

\;_{\phantom{2}92}^(238) \text{U} \to \;_{\phantom{2}89}^(230) \text{Ac} + \;_(2)^(4) \text{He} + \;_(2)^(4) \text{He} + \text{e}^(-) + \gamma

Consider: what would be the products if the nucleus undergoes a β⁺ decay instead?

How many moles of water, H2O, contain 2.0×10^22 molecules of water?

Answers

1 mol H₂O ----------- 6.02x10²³ molecules
  ? mol H₂O --------- 2.0x10²² molecules

Number of moles = Number of molecules / Avogadro's number

moles = 2.0x10²² * 1 / 6.02x10²³

= 2.0x10²² / 6.02x10²³

= 0.3322 moles

hope this helps!