The probabilities of a test are represented by I for infected; U, uninfected; D, infection detected; and N, no infection detected. What is the symbolic way to represent the probability of a true positive?

Answers

Answer 1

Answer: A true positive is when a person who is infected receives a positive test (someone whose test comes back positive but who doesn't really have the infection would be called a false positive).

A symbolic way to represent the probability of a true positive would be the infection detected divided by the total of all the options:

D/(I + U + D + N)

Answer 2

Answer:

Answer:

Step-by-step explanation:

PlATO

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9x^2 - 16 = (px+t)(px-t) both p and t are constants. Which of the following could be the value of p

Answers

Answer:

p = 3

Step-by-step explanation:

9x² - 16 ← is a difference of squares and factors in general as

a² - b² = (a + b)(a - b)

Thus

9x² - 16

= (3x)² - 4²

= (3x + 4)(3x - 4)

Compare with (px + t)(px - t)

then p = 3

Given f(x)= √4x and g(x)=1/x-4. which value is the domain of f o g? A. 4 B. 1. C. 5 D. -3

Answers

The domain of f o g is all x-values less than or equal to 1/4. So, the correct answer is B. 1.

What is Function ?

Function can be defined in which it relates an input to output.

To determine the domain of f o g, we need to first find the composition of f and g.

f o g(x) = f(g(x))

= √4(1/x - 4) = √(4/x - 16)

The domain of f o g is the set of all x-values for which the expression √(4/x - 16) is defined.

For the expression under the square root to be defined, we need:

4/x - 16 ≥ 0

4/x ≥ 16

x ≤ 4/16

x ≤ 1/4

Therefore, the domain of f o g is all x-values less than or equal to 1/4. So, the correct answer is B. 1.

To learn more about Function from given link.

brainly.com/question/12431044

#SPJ1

I really need help on geometry

Answers

For example, exc. 15.

x + y = 10 and 6/x = 9/y; You need y!

=> x = 10 -y and 9x = 6y => 9(10-y) = 6y => 90 - 9y = 6y => 15y = 90 => y = 6.

Solve for all possible values of x. square root of the quantity x minus 9 end quantity plus 4 equals 8

a) x = −5
b) x = 7
c) x = 13
d)x = 25

Answers

Answer:

Option d) x = 25

Step-by-step explanation:

we have

$√(x-9)+4=8$

Solve for x

Subtract 4 both sides

$√(x-9)+4-4=8-4$

$√(x-9)=4$

squared both sides

$(x-9)=(+/-)4^2$

$(x-9)=(+/-)16$

Adds 9 both sides

$x=9(+/-)16$

$x1=9(+)16=25$

$x2=9(-)16=-7$

Verify

1) For x=25

$√(25-9)=4$

$√(16)=4$

$4=4$ ----> is true

therefore

x=25 is a solution

2) For x=-7

$√(-7-9)=4$

$√(-16)=4$

The radicand cannot be a negative number

therefore

x=-7 is not a solution

A catering service offers 12 appetizers, 9 main courses, and 7 desserts. A banquet chairperson is to select 8 appetizers, 8 main courses, and 6 desserts for a banquet. In how many ways can this be done?

Answers

$12-appetizers, \ 9- main\ courses, \ 7\ desserts\n \n selection:\ 8\ appetizers,\ 8\ main\ courses, 6\ desserts\n\na=the\ number\ of\ selection\ of\ appetizers:\n \n{12 \choose 8}= (12!)/(8!\cdot (12-8)!) = (12\cdot11\cdot10\cdot9\cdot8!)/(8!\cdot4\cdot3\cdot2) =11\cdot5\cdot9=495\n \nc=the\ number\ of\ selection\ of\ main\ courses:\n \n{9 \choose 8}= (9!)/(8!\cdot (9-8)!) = (9\cdot8!)/(8!\cdot 1) =9$

$d=the\ number\ of\ selection\ of\ desserts:\n \n{7 \choose 6}= (7!)/(6!\cdot (7-6)!) = (7\cdot6!)/(6!\cdot 1) =7\n \nthe\ number\ of\ selection\ sets\ the\ banquet:\n \na\cdot c\cdot d=495\cdot9\cdot7=31185$

[(12! / (8!*4!) ]* [9! / (8!*1!) ] * [ 7!/ (6!*1!)] = ( 12 * 11 * 10 * 9 / 4 * 3 * 2 * 1) * 9 * 7 = 45 * 11 * 9 * 7 = 31185 ways

Answer pls…………………………..

Answers

Answer:

Option 3

Step-by-step explanation:

Brainliest please~

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