Find the least common denominator for these two rational expressions
Find the least common denominator for these two rational expressions - 1

Answers

Answer 1
Answer:

Answer: The LCD is 5y.


I hope this helps!




Related Questions

A nutritionist planning a diet for a runner wants him to consume 3,800 Calories and 650 grams of food daily. Calories from carbohydrates and fat will be 60% of the total Calories. There are 4, 4, and 9 Calories per gram for protein, carbohydrates, and fat, respectively. How many daily grams of fat will the diet include?
The first three steps for solving the quadratic equation by completing the square are shown. Fill in the missing number in the last step.9x2 +54x = 7 9(x2 + 6x) = 7 9(x2 + 6x + 9) = 7 + ?
The triangular prism belowhas a base area of 9 cm anda height of 23 cm. What isthe volume of the prism?
sophies math class has 6 fewer boys than girls , and there are g girls. write an expression for the number of boys
3 is what percent of 5

It is given that -3 is one of the roots of the quadratic equation x square -4x-h=0.find the value of h

Answers

Since -3 is one of the roots, that means it would satisfy the equation.

x^2 - 4x - h = 0,    substitute x = -3.

(-3)^2 -4(-3) - h = 0
9  +  12  -  h      = 0
21 - h = 0
21 =  h.
h  = 21.
That's the value of h.  Cheers.

How do you factorise 14x -21xy

Answers

Simplifying 14x + -21xy
 
Factor out the Greatest Common Factor (GCF), '7x'. 7x(2 + -3y)

Final result:
7x(2 + -3y)
 
that is the answer on how to do it
You need to find the common number/letter in order to factorise and it should be like this:
x(14-21y)
Hope it helped...

How to find exact value of tan 75°

Answers

tan \alpha = (sin \alpha )/(cos \alpha ) \n--------\n\ntan75^0= \frac{\big{sin75^0}}{\big{cos75^0}} \n\nsin75^0=sin(45^0+30^0)=sin45^0\cdot cos30^0+sin30^0\cdot cos45^0=\n\n.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = ( √(2) )/(2) \cdot ( √(3) )/(2) + (1)/(2) \cdot( √(2) )/(2) = ( √(6)+ √(2) )/(4)

Help please !! It is due tomorrow

Answers

Just substitute..

y=3x for X

y=3(-1)

y=3(0)

y=3(1)

y=3(2)

y=3(3)

then what you get for y just plot it

X^2+5x-104=0 solve quadratic equations

Answers

x^2+5x-104=0\n\na=1;\ b=5;\ c=-104\n\n\Delta=b^2-4ac;\ if\ \Delta > 0\ then\ x_1=(-b-\sqrt\Delta)/(2a);\ x_2=(-b+\sqrt\Delta)/(2a)\n\n\Delta=5^2-4\cdot1\cdot(-104)=25+416=441;\ \sqrt\Delta=√(441)=21\n\nx_1=(-5-21)/(2\cdot1)=(-26)/(2)=-13;\ x_2=(-5+21)/(2\cdot1)=(16)/(2)=8\n\nAnswer:x=-13\ or\ x=8.
You first have to factor and get (x-8)(x+13)=o and set them equal to zero x-8=0 x=8 x+13=0 x=-13

A bookstore charges a standard rate for paperback or hardback books. The cost of a paperback book is 11 dollars less than the cost of a hardback book. Recently one day of sales totaled $784.10. That day the bookstore sold 53 paperback books and 45 hardback book. Write a system representing the situation. Use the graph test made the solution of the system. What does the solution mean to the situation? How much does each type of book cost? You substitution to verify your solution.

Answers

The required price of the paperback book and hardback book is $2.95 and $13.95 respectively.

Given that,
The cost of a paperback book is 11 dollars less than the cost of a hardback book. Recently one day of sales totaled $784.10. That day the bookstore sold 53 paperback books and 45 hardback book.

What are simultaneous linear equations?

Simultaneous linear equations are two- or three-variable linear equations that can be solved together to arrive at a common solution.

Here,
Let the price of paperback be x and price of hardback books be y,
According to the question,
x = y - 11 - - - (1)
53x + 45y = 784.10 - - - (2)
From equation 1
53 [y - 11] + 45y = 784.10
y = $13.95

Now,
y = 13.95 - 11
y = $2.95

Thus, the required price of the paperback book and hardback book is $2.95 and $13.95 respectively.

Learn more about simultaneous equations here:

brainly.com/question/16763389

#SPJ5

p = h - 11
53p + 45h = 784.10

just a matter of subbing and solving...
53(h - 11) + 45h = 784.10
53h - 583 + 45h = 784.10
98h = 784.10 + 583
98h = 1367.10
h = 1367.10/98
h = 13.95

p = h - 11
p = 13.95 - 11
p = 2.95

so paperbacks (p) are 2.95 a piece and hardbacks (h) are 13.95 a piece