Write each sum as a product of the GCF of the two numbers : 75 and 90
Answers
75=3*5*5
90=2*3*3*5
common gropu is 3*5=15
75=15*5
90=15*6
ab+ac=a(b+c)
a is GCF
75+90
5(15)+5(6)=5(15+6)
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Which of the following statements is true about the three quadrilaterals?O M and O are similar and congruent.O O and N are similar and congruent.OM and N are similar but not congruent.OM and O are similar but not congruent.
Ten times the sum of half a number and 6 is 8
How do I Graph f(x)=5x-45.
Archie owns a farm with 60 chickens andhas enough food to feed them for 40 days. After 5 days, Archie sold some chickens. The remaining food will last for another 50 days. How many chickens were sold?
Answers
he then added 1/12 more money
so the amount of money he has is 1 and 1/12 of 100 dolars 1 and 1/12 is equal to 12/12+1/12=13/12
so b. [100+(1/12*100)] makes sense and d.[13/12*100] makes sense
d : 1 and a half of 100. thats right too. hope this helped!
Difference of Cubes
Difference of Squares
Square of Binomial
Sum of Cubes
Answers
Since there is sign +, we expect it to be the sum. Among all choices, only the last one includes summation, and that is sum of cubes.
Let's check it out.
Sum of cubes can be expresses as:
a³ + b³ = (a + b)(a² - ab + b²)
Let's see what are cube roots of 125 and 8:
∛125 = ∛5·5·5 = ∛5³ = 5 ⇒ a = 5
∛8 = ∛2·2·2 = ∛2³ = 2 ⇒ b = 2
Now, let's implement that in the equation of sum of cubes:
5³ + 2³ = (5 + 2)(5² - 5·2 + 2²)
125 + 8 = 7 · (25 - 10 + 4)
133 = 7 · 19
133 = 133
Therefore, sum of cubes is the right answer.
Answers
D. 597
The solution is as following
Determinant of K = 14 *(8*5+ --1*-2) - (-13)*(3*5- (-1)*(-10)) + 0 *( 3*-2 - 8*-10)
= 14 * 38 + 13 * 5 + 0 * 74
= 532 + 65
= 597
The value of x that satisfies the equation if x lies in the third quadrant is what degrees?
Answers
Step-by-step explanation:
sin^2(x)= 3 cos^2(x)
Subtract sin^2(x) on both sides
0=3cos^2(x)-sin^2(x)
By Pythagorean Identity sin^2(x)+cos^2(x)=1, we can replace cos^2(x) with 1-sin^2(x)
0=3(1-sin^2(x))-sin^2(x)
Distribute
0=3-3sin^2(x)-sin^2(x)
Combine like terms
0=3-4sin^2(x)
Add 4sin^2(x) on both sides
4sin^2(x)=3
Divide both sides by 4
sin^2(x)=3/4
Take the square root of both sides
sin(x)=+ or - sqrt(3/4)
sin(x)=+ or - sqrt(3)/sqrt(4)
sin(x)=+ or - sqrt(3)/2
This happens on the unit circle at
60 degrees
120 degrees
240 degrees
300 degrees
If we go around and around again forwards or backwards, we get the infinitely many other solutions including the one's already stated in the following solution sets
(60 +360n) degrees
(120 +360n)degrees
(240 +360n)degrees
(300 +360n)degrees
where n is an integer
x is 120 degrees or (120+360n) degrees in the second quadrant. I didn't know if you were just looking for solutions in the first nonnegative cycle of the unit circle or not.
240 degree one or the (240+360n) degrees terminates in the third.
Answers