If PQ = 21 cm and QR = 5, then what are the possible lengths for PR so that PQ,QR and PR can form a triangle? Explain your reasoning

Answers

Answer 1

Answer: Please see the pic, I'd solved in it.

Answer 2

Answer: So we are given the measurements of two sides of a Triangle:
(write down the given to be clear)
PQ=21 cm
QR=5 cm
But one very important thing:
As Aman said, the length of PR would definitely not be greater than the sum of the other two sides/legs....
Why? Because then it gives a STRAIGHT LINE!
which means: PR will be less than that sum
PR<sum of PQ and QR
PR<21+5
PR<26
Time for Pythagoras Theorem!
We can now split it into Two ways, since we dont know if PR is just a leg or the hypotenuse of the triangle:
And therefore:
Assuming PR is a leg:
(PQ seems to be the larger number)
PQ²=PR²+QR²
21² =PR²+5²
21²-5²=PR²
√21²-5²=PR
20.396 cm=PR
≈20.4 cm
20.4≤PR<26 (which means it can be 20.4 as well, but not any lower as it is very obvious)
Assuming that PR is the hypotenuse:
PR²=PQ²+QR²
PR²=21²+5²
PR=√21²+5²
PR=21.587 cm≈ 21.6 cm
21.6≤PR<26
So basically, the length can be 21.6 itself or higher.

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Decrease 40 by 12.5%

Answers

Answer:

Step-by-step explanation:

Multiply 40 by 0.125 (12.5%) and you get 5

Subtract 5 from 40

Solve for p3(p + q) = p
A. q = -2/3p
B. q = -3/2p
C. p = -2/3q
D. p = -3/2q

Answers

it’s A! hope this helps you out!

4+1=5 2+5=12 3+6=21 8+11=?

Answers

most of these are wrong....?
4+1=5
2+5 is not 12, it is 7
3+6 is not 21, it is 9
8+11= 19

4+1=5+2+5=12+3+6=21+8+11= Total =40

Help me please! Math files attached!

The first file is the questions picture, and the second file is the answer choices. This is a drag-and-drop thing, where you have to tell me what goes where so I can drag the correct choice to the correct box.

Please explain your answer clearly so I can answer the rest of my math problems on my homework.

Thank you! :D

Answers

AB/FG=AE/FG NO
AB/FG=BC/GH YES
AB/FG=GH/BC NO
AB/FG=HI/DC NO
BA/FG=JF/EA NO
BA/GF=CD/IH YES
FG/GH=JF/JI NO
GF/BA=JI/DE YES
HG/CB=GF/BA YES
HI/DC=AB/GF NO
IJ/AB=DE/FG NO
JF/AB=FG/EA NO
JF/EA=BA/GF NO
JF/EA=FG/AB NO

What is a pair of complex numbers called?

Answers

Answer:Complex numbers in the coordinate plane. Each complex number x + yi corresponds to a number pair (x, y) in the plane, so we may say that the complex numbers form a two-dimensional collection. The two coordinates of the pair (x, y) are called the real part and the imaginary part of the complex number.

Step-by-step explanation:

Gcf of 6w square - 14w

Answers

GCF of them is 2w.

Hope this helps :)

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