The reaction Ba(NO3)2(aq) + Na2SO4(aq) → 2NaNO3(aq) + BaSO4(s) goes to completion because a

Answers

Answer 1
Answer:

Answer:

This reaction is completed by a double displacement

A double displacement occurs when two different salts are mixed in an aqueous state, since when they dissolve a salt their ions are dissociated and when mixed with another salt in an aqueous state they combine and form two new compounds

Double displacement reactions

AB + CD\longrightarrow AC+ BD

Ba(NO_3)_2+Na_2SO_4 \longrightarrow 2NaNO_3 +BaSO_4

Answer 2
Answer: Ba(NO₃)₂ + Na₂SO₄ → 2NaNO₃ + BaSO₄

The reaction goes to completion because it has the same amount of elements in the reactants and products.

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Based on the equation below, which of the following statements best describes what should be observed as the reaction takes place?Zn(s) + 2HCl(aq) = ZnCl2(aq) + H2(g) Select one or more: a. Chlorine forming a solid precipitate b. Bubbles forming from hydrogen gas production c. Solid zinc dissolving d. Bubbles forming from chlorine gas production

Which substance will combine with oxygen gas to produce a greenhouse gas? a. Na
b. S
c. H₂
d. Ne
e. C

Answers

The substance that combined with the oxygen to form a greenhouse gas has been carbon (C). Thus, option E is correct.

The greenhouse gases have been responsible for the entrapment of the sun's energy in the atmosphere, leading to the increase in the temperature of earth and making earth an appropriate place to live.

The greenhouse gases have been the carbon dioxide, methane, sulfur etc. that are able to entrap the energy.

The reaction of carbon with oxygen has been resulted in the formation of carbon dioxide. It has been a green house gas.

Thus, the substance that combined with the oxygen to form a greenhouse gas has been carbon (C). Thus, option E is correct.

For more information about greenhouse gas, refer to the link:

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Carbon (C) will react with oxygen (O2) to produce CO2 (carbon dioxide) which is a greenhouse gas

A compound contains only carbon, hydrogen, nitrogen, and oxygen. Combustion of a 2.18 g sample burns in excess oxygen yields 3.94 g of CO2 and 1.89 g of H2O. A separate experiment shows that a 1.23 g sample contains 0.235 g of N. Calculate the moles of C in the sample.1. Calculate the moles of N for a 2.18 g sample (the sample size for the other analyses).
2. Calculate the moles of O in the sample.

Answers

Answer:

The answers are

C = 0.0895 moles

1. 0.02975 moles of N

2. 0.0299 moles O

Explanation:

Mass of sample = 2.18 g

Combustion yields 3.94 g of CO₂ and 1.89 g of H₂O

1.23 g of sample contains 0.235 g of N

3.94 g of CO₂ which contains one mole of C and two moles of O

Molar mass of CO₂ = 44 mass fraction of C = 12/44 = 0.273, Therefore mass of  carbon in 2.18 g = 0.273×3.94 = 1.075 g

number of moles of C in sample = mass/(molar mass) = 1.075 g/(12.01 g/mol) = 0.0895 moles of C

(1) Mass of nitrogen, in 1.23 g of sample = 0.235

therefore mass in 2.18 g =0.235×2.18/1.23 = 0.4165 g

= 0.02975 moles of N

(2) To find the number of moles of oxygen in the sample we note that total mass of sample  = 2.18 g containing only nitrogen, hydrogen, oxygen and carbon

Mass of hydrogen can be fround from 2/18×1.89 = 0.21 g

Mass of oxygen therefore = 2.18 -(0.21+0.4165+1.075) = 0.4785  

number of moles = 0.475/16 = 0.0299 moles

Determine the new temperature when the volume a gas at 1.56L and 20.0 ˚C changes to 2.02L. Please show work

Answers

Answer:

T₂ = 379.4 K

Explanation:

Given data:

Initial volume = 1.56 L

Initial temperature = 20°C (20+273 = 293 K)

Final volume = 2.02 L

Final temperature = ?

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

T₂  = V₂T₁ /V₁

T₂ = 2.02 L × 293 K / 1.56 L

T₂ = 591.86 L.K /  1.56 L

T₂ = 379.4 K

8 Which quantity is equal to one mole of Au?(1) the atomic mass in grams(2) the atomic number in grams
(3) the mass of neutrons in grams
(4) the number of neutrons in grams

Answers

Answer is (1) the atomic mass in grams since One mole of any element is equal to the atomic mass in grams.

Answer: option (1) the atomic mass in grams.

Explanation:

1) The atomic mass is the mass in grams of one mole of atoms.

2) Hence, it is always the atomic mass of an element equal to the mass of one mole of atoms of such element. Therefore, the atomic mass of Au is the mass of one moles of atoms of Au.

3) Here are some examples:

i) Atomic mass of gold: 196.67 g/atoms, means that 196.97 grams of Au is one mole of Au.

ii) Atomic mass of hydrogen: 1.008 g/mol, means that 1.008 grams of H is one mole of H.

iii) Atomic mass of oxygen: 15.999 g/mol, means that 15.999 grams of O is one mole of O.

iv) Atomic mass of lead: 207.2 g/mol, means that 207.2 grams of Pb is one mole of Pb.

Now you see it, the atomic mass in grams of an element is equal to one mole of the element.

The nucleus of an atom of K-42 contains(1) 19 protons and 23 neutrons
(2) 19 protons and 42 neutrons
(3) 20 protons and 19 neutrons
(4) 23 protons and 19 neutrons

Answers

The atomic number is the number of protons, while the atomic mass is the number of protons added to the number of neutrons. By definition, potassium (K) has atomic number 19, so it should have 19 protons. If it has a mass of 42, then the number of neutrons is 42 - 19 = 23 neutrons. This is choice (1).
Number of proton K => 19 
therefore, 42 - 19 = 23.

So the answer is 19 protons and 23 neutrons. 

A helium balloon has a volume of 2.30 L at 23.5 ​o​C and a pressure of 1.00 atm at sea level. The Balloon is released and floats upward. At a certain height the atmospheric pressure is 0.810 atm and the temperature is 12.0 ​o​C. Calculate the volume of the balloon.

Answers

Answer:

27.3 L

Explanation:

Final answer:

To calculate the volume of the balloon at a certain height, we can use the combined gas law. The volume of the balloon at the new height is approximately 1.13 L.

Explanation:

To solve this problem, we can use the combined gas law, which states that the ratio of the initial pressure, volume, and temperature will be equal to the ratio of the final pressure, volume, and temperature.

Using the formula PV/T = constant, we can set up the equation (1.00 atm * 2.30 L) / (23.5 + 273.15 K) = (0.810 atm * V) / (12.0 + 273.15 K), where V is the volume of the balloon at the new height.

Simplifying the equation and solving for V, we find that the volume of the balloon at the new height is approximately 1.13 L.

Learn more about volume of a balloon here:

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