What term is used to describe a perfect radiator and absorber of electromagnetic radiation?

Answers

Answer 1

Answer: Blackbody is the term used to describe a perfect radiator and absorber of electromagnetic radiation.

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Copper, silver, and nickel are all classified as
Calculate the final temperature of a sample of argon of mass 12.0 g at 273.15 K that is expanded reversibly and adiabatically from 1.0 dm3 to 3.0 dm3. The isochoric heat capacity for argon is 12.48 J/K.mol.
Elements are composed ofA) many type of atoms. B) the same type of atom. C) many different compounds. D) the same type of compound.
The two factors that affect the magnitude of the force are
Light of a certain energy shines on a metal and causes electrons to be emitted. Based on the research of Albert Einstein, what change would most likely result in stopping the emission of electrons from this metal?

What is the density of a substance with a mass of 1.8 kg and a volume of 0.2 L? Hurry Quick for 10 points
giveaway

Answers

Answer:

The answer is 9.0 kg/L

Explanation:

The density of a substance can be found by using the formula

$density = (mass)/(volume) \n$

From the question

mass = 1.8 kg

volume = 0.2 L

We have

$density = (1.8)/(0.2) \n$

We have the final answer as

9.0 kg/L

Hope this helps you

Answer:

knkjhhg

Explanation:

The total pressure inside a 1.62 cylinder kept at 35°C is 1.15 atm. If the volume of the cylinder drops to 0.74 L and the temperature remains the same, what is the new pressure inside the cylinder?

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By exponential outcome 21934

A weather balloon at Earth’s surface has a volume of 3.9 L at 299 K and 763 mmHg. If the balloon is released and the volume reaches 4.13 L at 720 mmHg, what is the temperature? Answer in units of K.

Answers

Combined Gas Laws

Given: V1= 3.9L V2= 4.13L T1= 299K P1=763mmHg P2=720mmHg

Unknown: T2=?

Formula: T2=T1P2V2 / P1V1

Solution: T2= (299K)(720mmHg)(4.13L) / (763mmHg)(3.9L)
= 889,106.4 / 2975.7

Answer: T2=298.8K

The light intensity of a source is 100 candelas. The illuminance on a surface is 4 lux. How far is the surface from the source?

Answers

The answer is 5 meters.

The illuminance on a surface (E) is equal to the light intensity (I) divided by the square distance from the light source (d):
E = I ÷ d² [=] candela/ square meters = lux.
The unit of the illuminance is lux.

So, it is given:
E = 4 lux
I = 100 candelas
d = ?

If:
E = I ÷ d²
Then
d² = I ÷ E
⇒ d² = 100 ÷ 4
⇒ d² = 25

If we put both sides of the equation under the square root, then:
√d² = √25
⇒ d = 5 meters.

Therefore, the surface is 5 meters far from the light source.

What would most likely be included in the “Analysis” section of a lab report?

Answers

The purpose of the analysis section of a lab report is to detail whathappened in the lab and what the outcome of the project was as a resultof said events.

A(n) ____________ is a substance in which all the exact combinations of elements are always the same.a.synthetic element
b.compound
c.mixtures
d.solution

Answers

A compound is a substance in which all the exact combinations of elements are always the same. The correct option is b.

What is a compound?

Compounds are substances that are made up of two or more substances or elements. A compound is a mixture of two elements, they share bonds with each other, and they form a totally different substance than the above elements.

For example, NaCl is a compound. It is formed by two elements, sodium, and chloride. These elements form a different compound that is common table salt.

Some compounds are pure substances because they are made up of only elements that mix together. They do not contain any impurity or any other substance. They share chemical bonds with each other.

Thus, the correct option is b. compound.

To learn more about compounds, refer to the link:

brainly.com/question/14658388

#SPJ2

b. compound
source is Glencoe Science book grade 7.
Also I just happening to be learning about this at school

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