MATHEMATICS HIGH SCHOOL

Factor the following trinomial by grouping

9x^3+30x^2+24x

Answers

Answer 1
Answer: Factor

9x3+30x2+24x
9x3+30x2+24x
=3x(3x+4)(x+2)
Answer 2
Answer: 9x^3+30x^2+24x \n \n gcf = 3x \n \n 3x ( (9x^3)/(3x) + (30x^2)/(3x) + (24x)/(3x) ) \n \n 3x(3x^2 + 10x + 8) \n \n 3x ( 3x^2 + 6x + 4x + 8) \n \n 3x(3x(x + 2) + 4(x + 2)) \n \n 3x(x + 2)(3x + 4) \n \n

The final result is: 3x(x + 2)(3x + 4).

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Match the sequence with the correct indicated term.

1)a1 = -4, d= -9, n=20
2)a1 =20, d=4, n=81
3)a12 for 8,3,-2,...

Answers
A)340
B)-47
C)-175
D)94

*PLEASE EXPLAIN*

Answers

1) an = a1 + d*(n-1) => a20 = -4 + (-9)*19 = -4 - 171 = - 175
1) ---> C)

2) a81 = 20 + 4*80 = 340;
2) ---> A)

3) a12 = ?
3) ---> B) or D).

a traveler has 7 pieces of luggage . how many ways can the traveler select 3 pieces of luggage for a trip

Answers

Answer:

35

Step-by-step explanation:

7-3= 4

7*6*5 = 210

3*2 = 6

210/6 = 35

Took the test this is the correct answer

Well, you could assign a letter to each piece of luggage like so...

A, B, C, D, E, F, G

What you could then do is set it against a table (a configuration table to be precise) with the same letters, and repeat the process again. If the order of these pieces of luggage also has to be taken into account, you'll end up with more configurations.

My answer and workings are below...

35 arrangements without order taken into consideration, because there are 35 ways in which to select 3 objects from the 7 objects.

210 arrangements (35 x 6) when order is taken into consideration.

*There are 6 ways to configure 3 letters.

Alternative way to solve the problem...

Produce Pascal's triangle. If you want to know how many ways in which you can choose 3 objects from 7, select (7 3) in Pascal's triangle which is equal to 35. Now, there are 6 ways in which to configure 3 objects if you are concerned about order.

In 2006, there were 2,573 computer viruses and other security incident. During the next 7 years, the number of incidents increased by about 92% each year.

Answers

Answer:

Total number of virus after 7yrs= 247484.7 virus

Step-by-step explanation:

Total number of virus after 7yrs = 2573(1+0.92)⁷ = 247484.7 virus

There is a 70% chance that your car will get stuck in the snow during the next big snowfall. Given that you are already stuck in the snow with your car, the chance that you will require a tow truck to pull you out is 90%. What is the chance that you will get stuck in the snow with your car and will require a tow truck to pull you out?Hint: cap p left parenthesis cap a vertical line cap b right parenthesis equals start fraction cap p left parenthesis cap a intersection cap b right parenthesis over cap p left parenthesis cap b right parenthesis end fraction

29%
63%
78%
66%

Answers

Given:
Probability that your car will get stuck in the snow: 70%
Probability that you will require a tow truck when stuck in the snow is 90%.

Probability that you're stuck in the snow and need a tow truck.

70% x 90% = 63%  2nd option.

Does someone know how to solve this problem?

Answers

Answer:

Acute scalene triangle.

Step-by-step explanation:

Acute scalene triangle.

Sides: a = 4   b = 7   c = 8

Area: T = 13.998

Perimeter: p = 19

Semiperimeter: s = 9.5

Angle ∠ A = α = 29.995° = 29°59'41″ = 0.524 rad

Angle ∠ B = β = 61.028° = 61°1'42″ = 1.065 rad

Angle ∠ C = γ = 88.977° = 88°58'37″ = 1.553 rad

Height: ha = 6.999

Height: hb = 3.999

Height: hc = 3.499

Median: ma = 7.246

Median: mb = 5.268

Median: mc = 4.062

Inradius: r = 1.473

Circumradius: R = 4.001

Vertex coordinates: A[8; 0] B[0; 0] C[1.938; 3.499]

Centroid: CG[3.313; 1.166]

Coordinates of the circumscribed circle: U[4; 0.071]

Coordinates of the inscribed circle: I[2.5; 1.473]

Exterior (or external, outer) angles of the triangle:

∠ A' = α' = 150.005° = 150°19″ = 0.524 rad

∠ B' = β' = 118.972° = 118°58'18″ = 1.065 rad

∠ C' = γ' = 91.023° = 91°1'23″ = 1.553 rad

If the vertices of triangle bcd are b(-3,3), c(3,5), and d(-1,0), what is the perimeter

Answers

distance formlula
D=\sqrt{(x2-x1)^(2)+(y2-y1)^(2)}

when you want to find the distance between points (x1,y1) and (x2,y2)


we nee
distace from
b to c
c to d
d to b


b to c is (-3,3) to (3,5)
D=\sqrt{(3-(-3))^(2)+(5-3)^(2)}=2√10

c to d is (3,5) to (-1,0)
D=\sqrt{(-1-3)^(2)+(0-5)^(2)}=√41

d to b is (-1,0) to (-3,3)
D=\sqrt{(-3-(-1))^(2)+(3-0)^(2)}=√13

add

b to c+c to d+d to b=2√10+√41+√13

perimiter=2√10+√41+√13 units
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