A substance has a mass of 360 g and a volume of 7.5 cm3. What is its density?a. 2700 g/cm3
c. 480 g/cm3
b. 270 g/cm3
d. 48 g/cm3

Answers

Answer 1

Answer: D = g / cm³

Density = mass / volume

D = 360 g / 7.5 cm³

D = 48 g/cm³

answer D

hope this helps!

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Can you divide II by another factor and still have it be correct? Why or why not?

Answers

Answer:

no, because factors can not be divided

Explanation:

At any given location, the physical properties of a substance do not change. a. True
b. False

Answers

It is true that at any given location, the physical properties of a substance do not change.

When are atoms considered stable?when they have satisfied the law of conservation of mass naturally or through bonding to obtain
full valence shells

when they have satisfied the octet rule naturally or through bonding to obtain full valence shells

when their valence electrons have "fallen" back to ground state through bonding

Answers

Answer:

when they have satisfied the octet rule naturally or through bonding to obtain full valence shells

Explanation:

Generally, most atoms of an element are unstable because they have a void in their electron shell to fill, hence, they need to react with other elements to fulfil this task of octet.

Octet rule states that atoms of elements engage in reactions to form compounds so they can have eight (8) valence electrons in their shell. Noble gases e.g argon, neon etc. are elements that have naturally satisfied this octet rule by possession of 8 valence electrons in their shell. Other elements that do not have this naturally becomes reactive and enter bonding with other atoms to obtain full valence shells.

Why does a heating curve have horizontal plateaus at certain points during the heating process? What is happening at those points?

Answers

A heating curve having horizontal plateaus at certain points during the heating process means that the process occurs at increase heating.

Concentrated hydrogen peroxide solutions are explosively decomposed by traces of transition metal ions (such as Mn or Fe): 2H2O2(aq) ---> 2H2O(l) + O2(g)What volume of pure O2(g), collected at 27C and 746 torr, would be generated by decomposition of 125 g of a 50.0% by mass hydrogen peroxide solution?

Answers

Answer:

23.0733 L

Explanation:

The mass of hydrogen peroxide present in 125 g of 50% of hydrogen peroxide solution:

$Mass=\frac {50}{100}* 125\ g$

Mass = 62.5 g

Molar mass of $H_2O_2$ = 34 g/mol

The formula for the calculation of moles is shown below:

$moles = (Mass\ taken)/(Molar\ mass)$

Thus, moles are:

$moles= (62.5\ g)/(34\ g/mol)$

$moles= 1.8382\ mol$

Consider the given reaction as:

$2H_2O_2_((aq))\rightarrow2H_2O_((l))+O_2_((g))$

2 moles of hydrogen peroxide decomposes to give 1 mole of oxygen gas.

Also,

1 mole of hydrogen peroxide decomposes to give 1/2 mole of oxygen gas.

So,

1.8382 moles of hydrogen peroxide decomposes to give $\frac {1}{2}* 1.8382 mole of oxygen gas. Moles of oxygen gas produced = 0.9191 molGiven: Pressure = 746 torrThe conversion of P(torr) to P(atm) is shown below:[tex]P(torr)=\frac {1}{760}* P(atm)$

So,

Pressure = 746 / 760 atm = 0.9816 atm

Temperature = 27 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (27 + 273.15) K = 300.15 K

Using ideal gas equation as:

PV=nRT

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

0.9816 atm × V = 0.9191 mol × 0.0821 L.atm/K.mol × 300.15 K

⇒V = 23.0733 L

What net ionic equation describes the reaction when these solutions are mixed?Given the equation: Na3PO4 (aq) + CaCl2(aq) →

A. 2PO43–(aq) + Cl– (aq) → Cl2(PO4)3(s)
B. 2Ca2+(aq) + Na+(aq) → NaCa2(s)
C. Na+(aq) + Cl– (aq) → NaCl(s)
D. 2PO43–(aq) + 3Ca2+(aq) → Ca3(PO4)2(s)

Answers

I think the correct answer from the choices listed above is option D. The net ionic equation that will describe the reaction of the reactants when mixed is expressed as:

2PO43–(aq) + 3Ca2+(aq) → Ca3(PO4)2(s)

Hope this answers the question. Have a nice day.

Answer:

$2PO_(4)^(-3) (aq) + 3Ca^(+2)(aq)-->Ca_(3)(PO_(4))_(2)(s)$