CHEMISTRY HIGH SCHOOL

Which are assumed to be constant while using the combined gas law?pressure
number of moles
volume and moles of gas
pressure and temperature

Answers

Answer 1
Answer:

Given from the combined gas law that PV/T = k, there, therefore, the number of moles of the gas is constant.

What is the combined gas law?

According to the combined gas law, the product of the pressure and volume divided by the temperature is a constant. That is; PV/T = k

Looking at this statement we can see that the implied assumption in this law is that the number of moles of the gas is constant.

Learn more about gas law:brainly.com/question/13805601?
Answer 2
Answer:

Answer:

number of moles

Explanation:

I believe this is the right one :)

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'why is a slanted paper tube considered a ramp?'

Answers

The incline could help things go up the incline plane therefore you can say it is an inclined plane. Hope this helped

How many moles are represented by 118g of cobalt? Cobalt had an atomic mass of 58.93amu

Answers

2.0 moles are represented by 118g of cobalt.

What are moles?

A mole is defined as 6.02214076 ×10^(23)of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

Moles = (mass)/(molar \;mass)

Moles = (118g )/(58.93amu)

Moles = 2.0023757 = 2.0moles

Hence, 2.0 moles are represented by 118g of cobalt.

Learn more about moles here:

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n=m/M
n=118/58.93=2
Answer: 2 moles

A box experiences a force of 2 N to the left and 3 N to the right. Which is true of the box's motion?

Answers

Answer:

The box will experience acceleration

Explanation:

The box experiences unbalanced forces and will, therefore, accelerate in other words, the force applied on it from the right is greater than that exerted on it from the left.
the box is expected to go to the right since the 3N is stronger than the 2N and the rightward force will over come the leftward force.

Determime the number of moles in the following compounds; a. 125 g of H2SO4 b. 35 g of CuSO4 × 5H2O

Answers

Mr of H2SO4 = 2+32+64= 98g No. Of moles = 125/98= 1.28 moles. B) Mr of CuSO4 = 64+32+64=160 Mr of 5H2O = 18x5=90 CuSO4.5H2O = 160+ 90 = 250g No. Of moles = 35/250= 0.14 moles

PLS HELP ILL MAKE BRAINLIEST 30 POINTS!!Which parts of the muscular and skeletal system work together to move muscles and bones? nerves esophagus and intestine arteries and vessels tendons and ligaments

Answers

Answer:

tendons and ligaments

Are these answers correct?1. A gas occupies 30 L at 760 mm Hg. What is its volume at 350 mm Hg?

P1*V1 = P2*V2

760 mm Hg *30 L = 350 mm Hg * V2

V2 = 22800 mm Hg*L/350 mm Hg

V2 = about 65.14 L


2. A gas occupies 500 mL at 1 atm. What is its pressure if the volume becomes 1500 mL?

P1*V1 = P2*V2

1 atm*500 mL = P2*1500 mL

500 atm*mL/1500 mL = P2

P2 = 1/3 atm


3. If a gas occupies 250 mL at 25°C, what will its volume be at 57°C?

25°C + 273 = 298°K; 57°C + 273 = 330°K

V1/T1 = V2/T2

250 mL/298°K = V2/330°K

0.84 mL/k*330°K = V2

V2 = about 276.85 mL

4. What was the original temperature of a 2 L sample of gas if it initially had the volume 5 L at 27°C?

27°C + 273 = 298°K

V1/T1 = V2/T2

5 L/298°K = 2 L/T2

2 L/(0.017 L/K)= T2

T2 = 119.2°K = -153.8°C

5. At what pressure would 100 mL of a gas be found if it began at 500 mL at 2.5 atm?

P1*V1 = P2*V2

2.5 atm*500 mL = P2*100 mL

125 atm*mL/100 mL = P2

P2 = 1.25 atm

6. What is the volume of a gas at 275 mm Hg if it occupied 750 mL at 1000 mm Hg?

P1*V1 = P2*V2

1000 mm Hg*750 mL = 275 mm Hg*V2

750000 mm Hg*mL/275 mm Hg = V2

V2 = about 2727. 27 mL

7. A gas occupies 60 L at 250°K and 1 atm. What is its volume at 250°C and 1.5 atm?

250°C + 273 = 523°K

P1*V1/T1 = P2*V2/T2

1 atm*60 L/250°K = 1.5 atm*V2/523°K

0.24 (atm*L/K)*523°K = 1.5 atm*V2

125.52 (atm*L)/1.5 atm = V2

V2 = 83.68 L

8. What is the final temperature in Celsius of a gas occupying 3.25 L at 750 mm Hg if it occupied 2250 mL at 37°C and 600 mm Hg?

37°C + 273 = 310°K; 2250 mL = 2.25 L

P1*V1/T1 = P2*V2/T2

600 mm Hg*2.25 L/310°K = 750 mm Hg*3.25 L/T2

2437.35 mm Hg*L/ (4.35 mm Hg*L/K) = T2

T2 = 559.69°K
T2 = about 286.69°C

Answers

I saw a slight error in number 8. 750*3.25=2437.5 not 2437.35. That threw your final answer off by a little more than half a °C. Other than that, I didn't see anything wrong.
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