A horizontal line on a distance-time graph means the object isa. moving at a constant speed.
b. moving faster.
c. slowing down.
d. at rest.

Answers

Answer 1

Answer: At rest because if the distance is not changing, then it is not moving any further, so it must not be moving! The time keeps going no matter what, so the distance, whether it is 0 m or 10,000 km, if the y is horizontal the distance does not change.

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Solar energy advantages and disadvantages

Answers

large solar panels are expensive

the energy it collects is 100% clean and renewable

doesn't create energy under certain weather conditions

John’s mass is 95.6 kg, and Barbara’s is 55.3 kg. He is standing on the x axis at xJ = +10.9 m, while she is standing on the x axis at xB = +2.50 m. They switch positions. How far and in which direction does their center of mass move as a result of the switch? Distance moved by center of mass =

Answers

Answer:Shifted towards Left by distance of 2.243 m

Explanation:

Given

Mass of john $m_1=95.6 kg$

Mass of barbara $m_2=55.3 kg$

John is standing at $x=10.9 m$

Barbara is standing at $x=2.50 m$

$x_(com)=(m_1x_1+m_2x_2)/(m_1+m_2)$

$x_(com)=(95.6* 10.9+55.3* 2.5)/(95.6+55.3)$

$x_(com)=(1180.29)/(150.9)$

$x_(com)=7.821 m$

Now if they change their Position then

$x'_(com)=(95.6* 2.5+55.3* 10.9)/(95.6+55.3)$

$x'_(com)=(841.77)/(150.9)$

$x'_(com)=5.578$

Thus we can see that center of mass shifted towards left by a distance of $2.243 m$ because heavier is shifted towards left

If the frequencies of two component waves are 24 Hz and 20 Hz, they should produce _______ beats per second. A. 2
B. 8
C. 4
D. 12

Answers

This can be answered using the beat frequency formula, which is simply the difference between 2 frequencies.

Let: fᵇ = beat frequency
f₁ = first frequency
f₂ = second frequency

fᵇ = |f₁ - f₂|

substituting the values:
fᵇ = |24Hz - 20Hz|
fᵇ = 4Hz

The unit Hz also means beats per second, therefore:
fᵇ = 4 beats per second

Therefore, the answer is C. 4

C. 4 beats per second is correct

Sally travels by car from one city to another. She drives for 30.0 min at 80.0 km/hr, 12.0 min at 105.0 km/hr, and 45.0 min at 40.0 km/hr, and she spends 15.0 min eating lunch and buying gas. A. Determine the average speed for the trip.
B. Determine the total distance traveled.

Answers

Answer:

A) The average speed for the trip is $v_(average) =53,53(km)/(h)$ .

B) The total distance traveled is $d_(total)=91\ km$ .

Explanation:

Knowing that 1 hour has 60 minutes, we have that for each part of the trip:

$v_(1)=80(km)/(h)\ t_(1)=0,5\ h$

$v_(2)=105(km)/(h)\ t_(2)=0,2\ h$

$v_(3)=40(km)/(h)\ t_(3)=0,75\ h$

$v_(4)=0(km)/(h)\ t_(4)=0,25\ h$

Total distance traveled

The distance traveled is the speed multiplied by a period of time. The total distance traveled is calculated adding up the speeds multiplied by the given periods of time.

$d_(total)=d_(1)+d_(2)+d_(3)$

$d_(total)=v_(1).t_(1)+v_(2).t_(2)+v_(3).t_(3)$

$d_(total)=80(km)/(h).0,5\ h+105(km)/(h).0,2\ h+40(km)/(h).0,75\ h$

$d_(total)=40\ km+21\ km+30\ km$

$d_(total)=91\ km$

B) The total distance traveled is $d_(total)=91\ km$ .

Average speed

The average speed could be calculated using the total distance traveled $d_(total)$ divided by the total time $t_(total)$ . We need to take into account the time spent eating lunch and buying gas.

$v_(average)=(d_(total))/(t_(total))$

$v_(average)=(v_(1).t_(1)+v_(2).t_(2)+v_(3).t_(3)+v_(4).t_(4))/(t_(1)+t_(2)+t_(3)+t_(4))$ $v_(average)=(91\ km)/(0,5\ h+0,2\ h+0,75\ h+0,25\ h)$

$v_(average)=(91\ km)/(1,70\ h)$

$v_(average)=53,53(km)/(h)$

A) The average speed for the trip is $v_(average) =53,53(km)/(h)$ .

Total distance = (30/60 x 80) + (12/60 x 105) + (45/60 x 40) = 0.5 x 80 + 0.2 x 105 + 0.75 x 40 = 40 + 21 + 30 = 91 km

Average distance = total distance / time taken = 91 / (30/60 + 12/60 + 45/60) = 91/ (0.5 + 0.2 + 0.75) = 91/1.45 = 62.76 km/hr

The energy an object has because of its position is called _____

Answers

Answer:

Gravitational potential energy

Explanation:

The gravitational potential energy is the energy that an object has because of its positive with respect to a certain reference level (generally assumed to be the ground level).

The magnitude of the gravitational potential energy is given by

$U=mgh$