Which of the following statements accurately describes the properties gases

Answers

Answer 1
Answer:

It may be, A change in the pressure of a gas results in a more significant change in volume than would occur in a liquid. I’m not for sure because I’m still studying this, but I think I correct but correct me if I’m wrong so that I can know and figure out what is the correct answer. Thank you


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How far could you speed walk in 10 minutes based on your speed for the 10 meter trial

Answers

Answer:

0.0166 m/s

Explanation:

time taken, t = 10 min = 10 x 60 = 600 second

distance, d = 10 m

Speed of an object is defined as the ratio of distance traveled to the time taken by the object.

Speed = distance / time

its SI unit is m/s and it is a scalar quantity.

So, the speed is given by

Speed = (Distance)/(Time)=(10)/(600)=0.0166 m/s

With a slope of 6.4%A car starts at 0mph, and has a top speed of 203
And has a base acceleration of 2.93ft/s2
How long would it take to reach 12.42 miles

Answers

Answer: 271.4 s

Explanation:

We are told the top speed (maximum speed)V_(max) the car has is:

V_(max)=203 mph=90.74 m/s taking into account 1 mile=1609.34 m

And the car's base acceleration (average acceleration)a_(ave) is:

a_(ave)=2.93 ft/s^(2)=0.89 m/s^(2)

Since:

a_(ave)=(V_(f)-V_(o))/(\Delta t)(1)

Where:

V_(f)=V_(max)=90.74 m/s is the car's final speed (top speed)

V_(o)=0 m/s because it starts from rest

\Delta t is the time it takes to reach the top speed

Finding this time:

\Delta t=(V_(f)-V_(o))/(a_(ave))(2)

\Delta t=(90.74 m/s - 0 m/s)/(0.89 m/s^(2))(3)

\Delta t=t_(1)=101.95 s(4)

Now we have to find the distance d the car traveled at this maximum speed with the following equation:

V_(f)^(2)=V_(o)^(2) + 2a_(ave) d(5)

Isolating d:

d=(V_(f)^(2))/(2a_(ave))(6)

d=((90.74 m/s)^(2))/(2(0.89 m/s^(2)))(7)

d=4625.70 m(8)

On the other hand, we know the total distance D traveled by the car is:

D=12.42 miles = 19988.052 m

Hence the remaining distance is:

d_(remain)=D-d=19988.052 m - 4625.70 m(9)

d_(remain)=15362.35 m(10)

So, we can calculate the time t_(2) it took to this car to travel this remaining distance d_(remain) at its top speed V_(max), with the following equation:

V_(max)=(d_(remain))/(t_(2))(11)

Isolating t_(2):

t_(2)=(d_(remain))/(V_(max))(12)

t_(2)=(15362.35 m)/(90.74 m/s)(13)

t_(2)=169.45 s(14)

With this time t_(2) and the value of t_(1) calculated in (4) we can finally calculate the total time t_(TOTAL):

t_(TOTAL)=t_(1)+ t_(2) (15)

t_(TOTAL)=101.95 s + 169.45 s (16)

t_(TOTAL)=271.4 s s

Plz tell me the answer to this problem!!

Answers

Answer:

B

Explanation:

They are in same group

What characteristics of carbon makes it essential to living organisms

Answers

Carbon is important to living organisms and is considered the organic element because of its ability to form so many bonds. Since carbon has four valence electrons, it has four open bonding spots, allowing it to form a large array of different substances. Because of this, carbon can be found in tons of things that are essential to sustaining life.

Hope this helps!

Compare contrast speed and velocity

Answers


"Speed" is the rate at which distance is being covered .... the ratio
of distance covered to the time it takes.

"Velocity" is the rate at which distance is being covered .... the ratio
of distance covered to the time it takes ... AND the direction in which
it is covered.  'Speed' with the direction of the motion.


Forces contribute to the net force on a car rolling down a ramp

Answers

Well if you're asking for the forces, here ya go.

There are a ton of forces that act upon a car while it rolls down a hill, such as:

     -Gravity pushing down on the mass of the car
     -The ramp (or ground) pushing back up on the car at an angle (making it            move)
     -Friction in the form of the tires on the ramp and air resistance
     -Normal Force perpendicular to gravity on the ramp

Now the question doesn't tell me if the engine is powering the car or not, it only says it is "Rolling"

But if the engine were to be driving the wheels, then Engine Force will be applied at the angle of the ramp.