In which direction does a bag at rest move when a force of 20 newtons is applied from the right? A. in the direction of the applied force B. in the direction opposite of the direction of the applied force C. perpendicular to the direction of the applied force D. in a circular motion

Answers

Answer 1
Answer:

The correct answer is A. In the direction of applied force. This is because acceleration occurs n the direction of applied force according to Newtons second law of motion which states that the acceleration of a body is directly proportional to the applied force and takes place in the direction of force.

Answer 2
Answer:

Answer:

A. in the direction of the applied force

Explanation:

As per newton's first law of motion we know that object will not change in its state of motion till some external force is applied on it

So here we can say that when force is applied on an stationary object then the stationary object will move in the direction of applied force so change in the state of motion from rest state to moving state will occur and the direction of motion must be in applied force direction

So correct answer will be

A. in the direction of the applied force


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Answers

It is known as conductivity
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Answers

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Answers

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A person weighing 500 N climbs on a rope. What is the tension on the rope?

Answers


At the times when the person is not moving up or down, the tension in
the rope is 500N.  At those moments, the forces on the person consist
of 500N downward due to gravity and 500N upward due to the tension in
the rope, and with the forces balanced, the person just hangs there and
doesn't accelerate up or down.

At the times when the person is actually climbing, that is, hauling himself
upward, the tension in the rope must be greater than 500N.  At those moments,
the net force on the person is upward, and the person's body accelerates upward.



the tension of a person weighing 500 pounds on a rope will make the rope break little by little,untill it gets to the point the rope snaps.

An..........reaction is the rearrangement of atoms by breaking and reforming chemical bonds

Answers

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1 . A farmer moves along the boundary of his rectangular field of side 10m x 20m . farmer covers 1m in 1sec . what will be the magnitude of displacement at the total distance travelled.2 . Rahul pedals his cycle from rest. Pedals his cycle to get a
velocity of 10 ms-1  in 30 seconds.
then he applies brakes in such that the velocity of the cycle comes does to 6
ms-1  in next 5 seconds . calculate
the acceleration and deceleration .

Answers

1). He's walking the 'perimeter' of his field, meaning 'the distance all the way around'.
If he stays right along the fence all the way, then the total distance he walks is
(10 + 20 + 10 + 20) = 60 meters. (It's a small field ... about 5% of an acre.)
The magnitude of displacement is the distance between the start point and end point,
regardless of the route.  After he finishes one whole trip around, his displacement is
zero, because he ends up at the same place where he started.
Notice the big fat red herring in the question: None of this depends on the speed
at which he walks.

2).  Acceleration = (change in speed) / (time for the change)

While speeding up, acceleration = (10 - 0) / 30 = 1/3 meter per second².

While slowing down, deceleration = (6 - 10) / 5 = -4/5 = -0.8 meter per second²