How do you label acceleration, momentum, speed, force, and velocity?

Answers

Answer 1

Answer: i have a a work sheet to do and i have choices for the diffrent words,
A:m
B:s
C:m/s
D:m/s2
E:kg
F:kg m/s
G:N
H:m/s north
so can you help me match the words with there answers

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which phenomenon is most directly responsible for earth’s magnetic field? Earth spinning on its axis. The moon's gravitational pull on earth? Earth's revolution around the sun? The moon's revolution around earth?

Answers

Earth spinning on its axis

Heat always flows from a what place to a what place

Answers

Answer:

Heat flows from high temperature to low temperature

Explanation:

the answer also may vary it can also be the heat flows from a warmer to colder place

hope this helped!

Answer:

Heat is always the transfer of energy from an object at a higher temperature to an object at a lower temperature.

Explanation:

Please help fast science homework

Answers

Answer:

The solar cells transfer light energy to thermal energy.

When the battery is being charged up, chemical energy is transferred to electrical energy.

The motor is designed to transfer potential energy to kinetic energy.

What is the final temperature when a 3.0 kg gold bar at 99 0C is dropped into 0.22 kg of water at 25oC?

Answers

Answer:

46.9 C

Explanation:

The heat released by the gold bar is equal to the heat absorbed by the water:

$m_g C_g (T_g-T_f)=m_w C_w (T_f-T_w)$

where:

$m_g = 3.0 kg$ is the mass of the gold bar

$C_g=129 J/kg C$ is the specific heat of gold

$T_g=99 C$ is the initial temperature of the gold bar

$m_w = 0.22 kg$ is the mass of the water

$C_w=4186 J/kg C$ is the specific heat of water

$T_w=25 C$ is the initial temperature of the water

$T_f$ is the final temperature of both gold and water at equilibrium

We can re-arrange the formula and solve for T_f, so we find:

$m_g C_g T_g -m_g C_g T_f = m_w C_w T_f - m_w C_w T_w\nm_g C_g T_g +m_w C_w T_w= m_w C_w T_f +m_g C_g T_f \nT_f=(m_g C_g T_g +m_w C_w T_w)/(m_w C_w + m_g C_g)=\n=((3.0)(129)(99)+(0.22)(4186)(25))/((0.22)(4186)+(3.0)(129))=(38313+23023)/(921+387)=(61336)/(1308)=46.9 C$

Answer:

$T_(f)=46.9C$

Explanation:

Given:

$m_(g) =3.0kg$ $m_(w) =0.22kg$

$T_(g)=99 C$ $T_(w)=25C$

$c_(p,g)=129J/kg.C$ $c_(p,w)=4186J/kg.C$

Unkown:

$T_f=?$

Formula:

$T_f=(m_g.c_(p,g).T_g+m_w.c_(p,w).T_w)/(m_w.c_(p,w)+m_g.c_(p,g))$

Step by step solution:

$T_f=((3)(129)(99)+(0.22)(4186)(25))/((0.22)(4186)+(3)(129))$

$T_f=(61336)/(1308)$

$T_f=46.9C$

94. While you are traveling in a car on a straight, level interstate highway at 90 km/h another car passes you in the same direction, its speedometer reads 120 km/h (a) What is your velocity relative to the other driver? (b) What is the other car's velocity relative to you?

Answers

Answer:

a) $v_{A_(B)}$ = -30 m/s

b) $v_{B_(A)}$ = 30 m/s

Explanation:

Consider the car A travel at a velocity of $v_(A)$ = 90 km/h and the car B travel at the velocity of $v_(B)$ = 120 km/h. As the velocity of the car B is greater than the car A, So it cross the car A. Consider The velocity of car A relative to car B is $v_{A_(B)}$ and it is equal to the velocity of car A minus the velocity of car B.

$v_{A_(B)}$ = $v_(A)$ - $v_(B)$

$v_{A_(B)}$ = 90 - 120

$v_{A_(B)}$ = -30 m/s

Consider The velocity of car B relative to car A is $v_{B_(A)}$ and it is equal to the velocity of car B minus the velocity of car A.

$v_{B_(A)}$ = $v_(B)$ - $v_(A)$

$v_{B_(A)}$ = 120 - 90

$v_{B_(A)}$ = 30 m/s

List the objects found in the universe in order of size

Answers

This is apartial list of Solar System objects by size, arranged in descending order of mean volumetricradius, and subdivided into several size classes. These lists can also be sorted according to an object'smassand, for the largest objects,volume,densityandsurface gravity, insofar as these values are available. This list contains theSun, theplanets,dwarf planets, many of the largersmall Solar System bodies(which includestheasteroids), all namednatural satellites, and a number of smaller objects of historical or scientific interest, such ascometsandnear-Earth objects.The ordering may be different depending on whether one chooses radius ormass, because some objects are denser than others. For instance,Uranusis larger thanNeptunebut less massive, and althoughGanymedeandTitanare larger thanMercury, they have less than half Mercury's mass. This means some objectsin the lower tables, despite their smaller radii, may be more massive than objects inthe upper tables because they have a higher density.Manytrans-Neptunian objects(TNOs) have been discovered, and their approximate locations in this list are shown, even though there can be a large uncertainty in their measurement.Solar Systemobjects more massive than 1021kilograms(oneyottagram [Yg]) are known or expected to be approximately spherical. Astronomical bodies relax into rounded shapes (ellipsoids), achievinghydrostatic equilibrium, when the gravity of their mass is sufficient to overcome the structural strength of their material. Objects made of ice become round more easily than those made of rock, and many icy objects are spheroidal at far lower sizes. The cutoff boundary for roundness is somewhere between 100 km and 200 kmin radius.[1]The larger objects in the mass range between 1018kgto 1021 kg (1 to 1000zettagrams [Zg]), such asTethys,Ceres, andMimas, have relaxed to anoblate-spheroidequilibrium due to their gravity, whereas the less massiverubble piles(e.g.AmaltheaandJanus) are roughly rounded,but not spherical, dubbed "irregular".

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