PHYSICS MIDDLE SCHOOL

A low-pressure sodium vapor lamp whose wavelength is 5.89 x 10^−7 m passes through double-slits that are 2.0 x 10^−4 m apart and produces an interference pattern whose fringes are 3.2 x 10^−3 m apart on the screen. What is the distance to the screen?3 meters

2.7 meters

1.6 meters

1.1 meters

its literally 1.1 meters I got it right

Answers

Answer 1
Answer:

Answer:

Distance of the screen is approx 1.1 m

Explanation:

As we know that fringe width on Young's double slit experiment is given as

\beta = (\lambda L)/(d)

here we know that

\beta = 3.2 * 10^(-3)

\lambda = 5.89 * 10^(-7) m

d = 2.0 * 10^(-4) m

now we have

3.2 * 10^(-3) = ((5.89 * 10^(-7))L)/(2.0 * 10^(-4))

L = 1.1 m
Answer 2
Answer:

Answer:

it is 1.1 meters

Explanation:

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Answers

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