Forces contribute to the net force on a car rolling down a ramp

Answers

Answer 1
Answer: Well if you're asking for the forces, here ya go.

There are a ton of forces that act upon a car while it rolls down a hill, such as:

     -Gravity pushing down on the mass of the car
     -The ramp (or ground) pushing back up on the car at an angle (making it            move)
     -Friction in the form of the tires on the ramp and air resistance
     -Normal Force perpendicular to gravity on the ramp

Now the question doesn't tell me if the engine is powering the car or not, it only says it is "Rolling"

But if the engine were to be driving the wheels, then Engine Force will be applied at the angle of the ramp.


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Which are the four fundamental forces? the electromagnetic force, the strong nuclear force, the frictional force, and the gravitational force. the electromagnetic force, the strong force, the weak force, and the gravitational force the electromagnetic force, the normal force, the frictional force, and the gravitational force. the electromagnetic force, the strong nuclear force, the weak nuclear force, and the frictional force.

When taking a shower are girls suppose to wipe front to back ?

Answers

Answer:

Explanation:

I don't think it matters while taking a shower, however, while using the restroom, it is especially encourgaed to wipe front to back. The reasoning behind this is to prevent UTI's that are transferred by fecal particles and bacteria from the anus into the vagina. Hope this helps:)

I think you should always wipe front to back to prevent any type of bacteria from getting near you know..

A 10.0 kilogram mass of iron on earth exerts a downward force of 98 Newtons. On the moon this same 10.0 kilograms of iron is weighed and found to exert a downward force 16.3 Newtons. How is this possible ?

Answers

The weight of an object is the force it experience by the gravitational pull of the planet. The gravitational pull by earth is greater than that from moon. This leads to greater weight in earth than in moon.

What is gravitational force ?

Gravitational force is a kind of force by which an object attracts other objects into its center of mass. The force exerted between the objects depends on the mass and distance between them.

Earth exerts a gravitational pull to every objects on its surface and that's why we are standing on the ground. We experience a weight downwards due to this force.

The acceleration due to gravity  in earth = 9.8 m/s²

g in moon = 1.63m/s².

then weight = m g

the weight of a 10 kg iron bar in earth is 98 N and that in moon will be 16.3 N.

Find more on gravitational force:

brainly.com/question/24783651

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Answer:

The decrease in the downward force that a mass of iron can exert on the moon versus the force it exerts on earth is due to:

  • The force of gravity on Earth is greater than the force of gravity on the moon.

Explanation:

To recognize the calculation within the statement, you must know that the Newton unit is equal to:

  • Newton = (Kilogram * meter) / second ^ 2

And that the gravities of the Earth and the Moon are:

  • Earth gravity = 9.807 m / s ^ 2
  • Moon gravity = 1.63 m / s ^ 2

Finally, you must know the force formula (since we are talking about a descending force):

  • Force = mass * acceleration (gravity is a measure of acceleration)

Since the mass in both cases is the same (10 kilograms), the variation in acceleration will provide different values of descending force, as shown below, replacing the values:

  1. Downward force on Earth = 10 Kg * 9,807 m / s ^ 2 = 98.07 Kg * m / s ^ 2 = 98.07 Newtons.
  2. Downward force on the Moon = 10 Kg * 1.63 m / s ^ 2 = 16.3 Kg * m / s ^ 2 = 16.3 Newtons.

As you can see, when it comes to force, the less acceleration (in this case less gravity), the lower the downward force will be with a mass of equal weight.

Describe the motion of particles in a material when this ultrasound wave passes through? Pls help , confused?
Thank you

Answers

Yes, the particles are just moving back and forth, not moving in any particular direction on average. For one, the particles are only moving in response to the sound wave, in perfect synchronization, and they aren't also moving constantly in random directions. If you had some material that would remain a gas at absolute zero, then a sound wave in that absolute-zero gas would look more or less like it. But for an everyday-volume sound wave in room-temperature air, the random thermal motion (which is always happening whether or not there is a sound wave) is much stronger than the motion caused by the sound wave. The only reason we notice a sound wave at all is because it is an ordered motion that carries energy in a particular direction. If you followed the motion of a single air molecule, it would look entirely random and there would be no trace of the sound wave. The sound wave only becomes apparent when you look at the large-scale pattern of density variations.The other weird thing about the animation is that the molecules stop moving and turn around without colliding with anything! It should be obvious that in a real gas made of electrically neutral particles, there is no long-distance force that would cause this to happen, and a moving particle would not change direction unless it actually collided with another particle.To answer your particular questions, yes, the whole medium is "vibrating" in that the density and pressure are increasing and decreasing periodically, as the gas flows back and forth. there doesn't have to be any well-defined cross-sectional shape for the sound wave. In fact, the simplest geometry to consider is a plane wave, which extends infinitely in all directions perpendicular to the direction of propagation. It's actually impossible to make a "beam" of sound that will propagate forever without spreading out. 
So, yea. Hope that helped.

a person pushing a stroller starts from rest, uniformly accelerating at a rate of 0.500 m/s2. What is the velocity of the stroller after it has traveled 4.75 m ?

Answers

Answer:

Approximately 2.18 m\cdot s^(-1).

Explanation:

Consider one of the equations for constant acceleration ("SUVAT" equations)

v^(2) - u^(2) = 2 \; a \cdot x,

where

  • v is the final velocity of the object,
  • u is the initial velocity of the object,
  • a is the acceleration of the object, and
  • x is the distance that the object had traveled while its velocity changed from u to v.

Note that unlike other SUVAT equations, this one does not ask for the time required for the speed of the object to change from u to v. Since in this problem, time isn't given, this time-less equation would particular useful.

Here

  • v the final velocity needs to be found.
  • u = 0 for the stroller started from rest.
  • a =\rm 0.500 \;m \cdot s^(-2) is the acceleration of the stroller, and
  • x = \rm 4.75\; m is the distance that the stroller traveled while its velocity changed from u to v.

Rearrange the equation to isolate the unknown, v:

v^(2) = u^(2) + 2 \; a \cdot x.

Make sure that all units are standard, so that the unit of the output will also be standard. Apply the equation:

v = \sqrt{u^(2) + 2 \; a \cdot x} = √(0^2 + 2 * 0.500 * 4.75 )\approx \rm 2.18\; m\cdot s^(-1).

Hence the final velocity will be approximately \rm 2.18 m\cdot s^(-1).

Velocity-time graph worksheet?

Answers

Answer: yep

Explanation:

Answer:

yes

Explanation:

A skydiver jumps out of a hovering helicopter, so there is no forward velocity. Ignore wind resistance for this exercise. 1. What is the skydiver's acceleration

Answers

Answer:

a = g = 9.81 m/s^2

Explanation:

As we know that there is no wind resistance on the skydiver

so when he jumps out of the helicopter then in that case the net force on the diver will be due to gravity only

so his equation for force is given by

F = mg

now from the Newton's law of motion we will have

F_(net) = ma

from the given options we will have

mg = ma

so the acceleration is

a = g = 9.81 m/s^2

1. What is the skydiver's acceleration?

Initially, like any falling object, a skydiver's downward acceleration is 9.8 meters/seconds^2, or about 28-35 feet per second squared. This acceleration reduces over a few seconds and approaches zero as the skydiver reaches terminal velocity.