1. Which has more energy, an electron close to the nucleus of an atom, or an electron farther away from the nucleus?

Answers

Answer 1

Answer: the atom thats close to the nucleus

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Which condensed structural formula represents an unsaturated compound?(1) CH3CHCHCH3 (3) CH3CH3
(2) CH3CH2CH3 (4) CH4

Answers

(1) CH3CHCHCH3.................

(1) CH3CHCHCH3 because it contains a double bond.

Which compound is classified as a hydrocarbon?(1) butanal (3) 2-butanol
(2) butyne (4) 2-butanone

Answers

Answer: The correct answer is Option 2.

Explanation:

Hydrocarbons are defined as the compounds which have a covalent bond present between hydrogen and carbon atoms. For Example: $CH_4$ is a hydrocarbon. $H_2O,CO_2$ are not considered as hydrocarbons.

For the given options:

Option 1: butanal

The chemical formula for this compound is $CH_3CH_2CH_2CHO$

This is not considered as a hydrocarbon because a covalent bond is present between carbon and oxygen atom.

Option 2: butyne

The chemical formula for this compound is $CH\equiv CCH_2CH_3$

This is considered as a hydrocarbon because covalent bonds are present between carbon and hydrogen atoms only.

Option 3: 2-butanol

The chemical formula for this compound is $CH_3CH(OH)-CH_2CH_3$

This is not considered as a hydrocarbon because a covalent bond is present between carbon and oxygen atom.

Option 4: 2-butanone

The chemical formula for this compound is $CH_3C(O)-CH_2CH_3$

This is not considered as a hydrocarbon because a covalent bond is present between carbon and oxygen atom.

From the above information, the correct answer is Option 2.

(2) butynu........................

How did Rutherford's experimental evidence lead to the development of a new atomic model?

Answers

In his Gold Foil experiment, few particles were deflected strongly, where as he thought all particles will go straight through the foil (some did though, which are called electrons.) J. J. Thompson, Rutherford's former teacher, proposed that if there are negative charge particles (he named them electrons), there must also be a positive charge particles; Rutherford proved his theory right, and he called the positive charge protons. He also found that inside the atom, there must be a positive charge that is clustered in a tiny region in its center, which is called the nucleus.

1. What is the volume of 0.900 moles of an ideal gas at 25.0° C and a pressure of 950.0 mm Hg?1.50 liters
17.6 liters
18.0 liters
34.2 liters

2. What is the pressure, in mm Hg, of 2.50 moles of an ideal gas if it has a volume of 50.0 liters when the temperature is 27.0° C?
84.2 mm Hg
289 mm Hg
617 mm Hg
936 mm Hg

3. When 12.4 grams of KBr are dissolved in enough water to create a 170-gram solution, what is the solution's concentration, expressed as a percent by mass?
6.2% KBr
6.8% KBr
7.3% KBr
7.9% KBr

Answers

1. Using the ideal gas law, which states that PV = nRT, and remembering that absolute temperature must be used:
(950.0 mmHg)(V) = (0.900 moles)(R)(25.0 + 273.15 K)
The most convenient value of R is 0.08206 L-atm/mol-K, so we convert the pressure of 950.0 mmHg to atm by dividing by 760: 1.25 atm
(1.25 atm)(V) = (0.9)(0.08206)(298.15)
V = 17.6 L

2. Again using the ideal gas law, and converting temperature to Kelvin: 27 + 273.15 = 300.15 K
PV = nRT
P(50.0 L) = (2.50 moles)(0.08206 L-atm/mol-K)(300.15 K)
P = 1.23 atm
Then we multiply by 760 mmHg / 1 atm = 936 mmHg. This is the fourth of the choices.

3. If the complete solution has a mass of 170 grams, and 12.4 grams of it is the dissolved KBr, we simply have to divide the mass of solute (KBr) by the total mass of the solution: This gives us 12.4 grams / 170 grams = 0.0729. Multiplying by 100% gives 7.29% or approximately 7.3% KBr, which is the third of the choices.

1. The volume of the ideal gas is $\boxed{{\text{17}}{\text{.6 L}}}$ .

2. The pressure of the ideal gas is $\boxed{{\text{936 mm Hg}}}$ .

3. The concentration of the solution, expressed as mass percent is $\boxed{{\text{7}}{\text{.3 \% }}}$ .

Further Explanation:

An ideal gas is a hypothetical gas that is composed of a large number of randomly moving particles that are supposed to have perfectly elastic collisions among themselves. It is just a theoretical concept and practically no such gas exists. But gases tend to behave almost ideally at a higher temperature and lower pressure.

Ideal gas law is the equation of state for any hypothetical gas. The expression for the ideal gas equation is as follows:

${\text{PV}} = {\text{nRT}}$ .......(1)

Here,

P is the pressure of ideal gas.

V is the volume of ideal gas.

T is the absolute temperature of the ideal gas.

n is the number of moles of the ideal gas.

R is the universal gas constant.

1. Rearrange equation (1) to calculate the volume of the ideal gas.

${\text{V}}=\frac{{{\text{nRT}}}}{{\text{P}}}$ ......(2)

The pressure of the ideal gas is 950 mm Hg.

The temperature of the ideal gas is ${\text{25}}\;^\circ{\text{C}}$ .

The number of moles of the ideal gas is 0.9 mol.

The universal gas constant is 0.0821 L atm/K mol.

Substitute these values in equation (2).

$\begin{aligned}{\text{V}}&=\frac{{\left( {{\text{0}}{\text{.9 mol}}} \right)\left( {0.0821{\text{ L atm/K mol}}} \right)\left( {25 + 27{\text{3}}{\text{.15}}}\right){\text{K}}}}{{\left( {950{\text{ mm Hg}}}\right)\left( {\frac{{{\text{1 atm}}}}{{760{\text{ mm Hg}}}}}\right)}}\n&= 17.624{\text{ L}}\n&\approx {\text{17}}{\text{.6 L}}\n\end{aligned}$

Therefore the volume of the ideal gas is 17.6 L.

2. Rearrange equation (1) to calculate the pressure of ideal gas.

${\text{P}} =\frac{{{\text{nRT}}}}{{\text{V}}}$ ......(3)

The volume of the ideal gas is 50 L.

The temperature of the ideal gas is ${\text{27}}\;^\circ {\text{C}}$ .

The number of moles of the ideal gas is 2.5 mol.

The universal gas constant is 0.0821 L atm/K mol

Substitute these values in equation (3).

$\begin{aligned}{\text{P}}&= \frac{{\left( {{\text{2}}{\text{.5 mol}}} \right)\left( {0.0821{\text{ L atm/K mol}}} \right)\left( {27 + 27{\text{3}}{\text{.15}}} \right){\text{K}}}}{{{\text{50 L}}}}\n&= 1.2321{\text{ atm}}\n&\approx 1.232{\text{ atm}}\n\end{aligned}$

The pressure is to be converted into mm Hg. The conversion factor for this is,

${\text{1 atm}} = {\text{760 mm Hg}}$

So the pressure of ideal gas can be calculated as follows:

$\begin{aligned}{\text{P}} &= \left({{\text{1}}{\text{.232 atm}}}\right)\left( {\frac{{{\text{760 mm Hg}}}}{{{\text{1 atm}}}}}\right)\n&= 936.3{\text{2 mm Hg}} \n&\approx 93{\text{6 mm Hg}}\n\end{aligned}$

Therefore the pressure of the ideal gas is 936 mm Hg.

3. The formula to calculate the mass percent of KBr is as follows:

${\text{Mass}}\;{\text{percent}}=\left( {\frac{{{\text{Mass of KBr}}}}{{{\text{Mass of solution}}}}}\right)\left( {100} \right)$ ......(4)

The mass of KBr is 12.4 g.

The mass of the solution is 170 g.

Substitute these values in equation (4).

$\begin{aligned}{\text{Mass}}\;{\text{percent}}&= \left( {\frac{{{\text{12}}{\text{.4 g}}}}{{{\text{170 g}}}}} \right)\left( {100} \right)\n&= 7.294\;\% \n&\approx 7.{\text{3 \% }}\n\end{aligned}$

Therefore the concentration of the solution is 7.3 %.

Learn more:

1. Which statement is true for Boyle’s law: brainly.com/question/1158880

2. Calculation of volume of gas: brainly.com/question/3636135

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Mole Concept

Keywords: P, V, n, R, T, ideal gas, pressure, volume, 17.6 L, 936 mm Hg, 7.3 %, 0.9 mol, 950 mm Hg, 50 L, 2.5 mol, 12.4 g, 170 g, KBr

How many liters of 0.760 Molar NaOH are needed to completely neutralize 145 mL of 11.33 Molar HCL

Answers

Answer:

35.00 mL

Explanation:

What is the correct name for the compound CoCl3?a) cobalt(I) chloride

B) cobalt(I) chlorate

C) cobalt(II) chlorate

D) cobalt(III) chloride

Answers

Answer:

D) Cobalt (III) chloride.

Explanation:

It is an unstable compound in which the cobalt atoms have a formal charge of +3.

It could be stable but at very low temperatures, while at high temperatures it is found as a gas.

I hope this answer helps you.

Cobalt(III) chloride, often known as cobaltic chloride, is an elusive and unstable cobalt and chlorine chemical with the formula CoCl₃. The cobalt atoms in this combination have a formal charge of +3. Here the correct option is D.

Due to its special characteristics, cobalt chloride (CoCl₃) is a chemical substance that is frequently utilized in scientific study. It is a crystalline solid that is pinkish-red and soluble in ethanol and water. Cobalt ions, which are necessary for the growth and development of both plants and animals, can be found in cobalt chloride.

Cobalt(III) chloride, often known as cobaltic chloride, is an elusive and brittle cobalt and chlorine chemical with the formula CoCl₃. The cobalt atoms in this combination have a formal charge of +3.

Thus the correct option is D.

To know more about Cobalt(III) chloride, visit;

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