The earth's four main spheres continuously interact to support life and balance Earth's materials. When plants absorb carbon dioxide for photosynthesis, it is an example of _____ and _____ sphere interaction.biosphere, lithosphere; biosphere, atmosphere; hydrosphere, lithosphere; or cryosphere, lithosphere biosphere, lithosphere biosphere, atmosphere hydrosphere, lithosphere cryosphere, lithosphere

Answers

Answer 1
Answer: The correct answer for the question that is being presented above is this one: "biosphere, atmosphere." The earth's four main spheres continuously interact to support life and balance Earth's materials. When plants absorb carbon dioxide for photosynthesis, it is an example of biosphere and atmosphere sphere interaction.
Answer 2
Answer:

Its "biosphere and atmosphere" because photosynthesis comes from the plants and the atmosphere then consumes the carbon.


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What is the Sun's right ascension on the vernal equinox?a. 0 hours
b. 6 hours
c. 12 hours
d. 18 hours

Answers

the suns right ascension on the vernal equinox is (a) 0 hours



An electromagnetic am band radio wave could have a wavelength of?1) .005m
2) 5m
3) 500m
3) 5,000,000m

Answers

An electromagnetic am band radio wave could have a wavelength of 500m, i.e., 500 meters(Option 3).

What is wavelength?

A wavelength is a disturbance that travels into space with a given frequency and amplitude.

  • Electromagnetic wavelengths can be classified depending on their type of frequency.

In conclusion, an electromagnetic am band radio wave could have a wavelength of 500m (Option 3).

Learn more about electromagnetic wavelengths here:

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The frequency of choice-3 is

         (3 x 10⁸ m/s) / (500 m)  =  600,000 Hz.

That number is the 600 near the bottom of the AM radio dial.

Sign of the charge???A glass marble is rubbed against a piece of silk. As a result the piece of fabric acquires extra electrons. What happens to the glass marble? (a)The marble has lost the same number of electrons acquired by the piece of silk. (b)The marble has acquired the same number of electrons acquired by the piece of silk. (c)The marble acquires a positive charge and repels the piece of silk. (d)The marble acquires a positive charge and attracts the piece of silk. (e)The marble acquires a negative charge and attracts the piece of silk. (f)The marble acquires a negative charge and repels the piece of silk. There may be more than one answer.

Answers

The right answer for the question that is being asked and shown above is that: "(b)The marble has acquired the same number of electrons acquired by the piece of silk; (f)The marble acquires a negative charge and repels the piece of silk."

When an object is placed 8 millimeters from a concave spherical mirror, a clear image can be projected on a screen 16 millimeters in front of the mirror. If the object has a height of 4 millimeters, the height of the image is A. 2 millimeters.
B. 4 millimeters.
C. 8 millimeters.
D. 12 millimeters.

Answers

The question can be answered by ratio and proportion by similar triangles u/v=Hi/Ho

8 : 16 = x : 4
8 / 16 = x / 4
16x = 32
x = 2

So the correct answer is letter A. 2 millimeters. 

The circuit you should use to find the open-circuit voltage is

Answers

Answer:

Incomplete questions check attachment for circuit diagram.

Explanation:

We are going to use superposition

So, we will first open circuit the current source and find the voltage Voc.

So, check attachment for open circuit diagram.

From the diagram

We notice that R3 is in series with R4, so its equivalent is given below

Req(3-4) = R3 + R4

R(34) = 20+40 = 60 kΩ

Notice that R2 is parallel to the equivalent of R3 and R4, then, the equivalent of all this three resistor is

Req(2-3-4) = R2•R(34)/(R2+R(34))

R(234) = (100×60)/(100+60)

R(234) = 37.5 kΩ

We notice that R1 and R(234) are in series, then, we can apply voltage divider rule to find voltage in R(234)

Therefore

V(234) = R(234) / [R1 + R(234)] × V

V(234) = 37.5/(25+37.5) × 100

V(234) = 37.5/62.5 × 100

V(234) = 60V.

Note, this is the voltage in resistor R2, R3 and R4.

Note that, R2 is parallel to R3 and R4. Parallel resistor have the same voltage, then voltage across R2 equals voltage across R34

V(34) = 60V.

Now, we also know that R3 and R4 are in series,

So we can know the voltage across R4 which is the Voc we are looking for.

Using voltage divider

V4 = Voc = R4/(R4 + R(34)) × V(34)

Voc = 40/(40+60) × 60

Voc = 24V

This is the open circuit Voltage

Now, finding the short circuit voltage when we short circuit the voltage source

Check attachment for circuit diagram.

From the circuit we notice that R1 and R2 are in parallel, so it's equivalent becomes

Req(1-2) = R1•R2/(R1+R2)

R(12) = 25×100/(25+100)

R(12) = 20 kΩ

We also notice that the equivalent of Resistor R1 and R2 is in series to R3. Then, the equivalent resistance of the three resistor is

Req(1-2-3) = R(12) + R(3)

R(123) = 20 + 20

R(123) = 40 kΩ

We notice that, the equivalent resistance of the resistor R1, R2, and R3 is in series to resistor R4.

So using current divider rule to find the current in resistor R4.

I(4) = R(123) / [R4+R(123)] × I

I(4) = 40/(40+40) × 8

I(4) = 4mA

Then, using ohms law, we can find the voltage across the resistor 4 and the voltage is the required Voc

V = IR

V4 = Voc = I4 × R4

Voc = 4×10^-3 × 40×10^3

Voc = 160V

Then, the sum of the short circuit voltage and the open circuit voltage will give the required Voc

Voc = Voc(open circuit) + Voc(short circuit)

Voc = 24 + 160

Voc = 184V.

A jet plane lands at a speed of 100 m/s and can accelerate at a maximum rate of -5.00 m/s^2 as it comes to a rest.(a from the instant the plane touches the runaway, what is the minimum time needed before it can come to a rest?
(b Can this plane land on a runaway that is only 0.800 km long?
shown work pls will reward alot of points

Answers

Answer:

a)   t = 20 s,  b)  x = 1000 m, As the runway is only 800 m long, the plane cannot land at this distance

Explanation:

This is a kinematics exercise

a) in minimum time to stop,

           v = vo + at

           v = 0

           t = -v0 / a

we calculate

          t = -100 / (5.00)

          t = 20 s

b) Let's find the length you need to stop

          v² = vo² + 2 a x

          x = -v0 ^ 2 / 2a

          x = - 100² / 2 (-5.00)

          x = 1000 m

As the runway is only 800 m long, the plane cannot land at this distance.