Answer : Option C) Lithosphere.
Explanation : Lithosphere is a layer which includes the crust and the uppermost mantle, which constitutes the hard and rigid outer layer of the Earth. The lithosphere is subdivided into tectonic plates. In these tectonic plates large amount of phosphorus is found. Whereas carbon and nitrogen in found in atmosphere not in the layers of the earth.
The availability of phosphorus is different that that of carbon and nitrogen because it is found mostly in the Lithosphere, whereas, carbon and nitrogen are found in atmosphere.
Answer: Titration
Explanation: Titration is defined as the process where a solution of known concentration is used to determine the concentration of an unknown solution.
Volumetric titrations are usually used for neutralization reactions where an indicator is used to know the acidic or basic nature of solution.
The normality equation used at a point where neutralization occurs during the titration is:
= Normality of acid solution
= volume of acid solution
= Normality of basic solution
= Volume of basic solution
b. a double bond.
c. ionic.
d. polyatomic.
A covalent bond where electrons are shared unequally is known as a polar bond. This unequal sharing occurs due to differences in electronegativity between the two atoms involved in the bond.
A covalent bond in which electrons are shared unequally is defined as a polar bond. This corresponds to option a) polar. This occurs because one atom is more electronegative and pulls the shared electron pair towards its nucleus making the bond polar, having a partial positive and partial negative end. Option b) a double bond, refers to a covalent bond where two pairs of electrons are shared between atoms. Option c) ionic refers to a bond where electrons are completely transferred from one atom to another and option d) polyatomic refers to a molecule that consists of more than two atoms.
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Answer:Density
Explanation: The students should compute the density of the cube. Density is a physical property that can be used to identify most pure substances. The students know the length of a side so they can compute the volume. They also know the mass. Using the density formula, density =
mass
volume
, they can compute the density and identify the metal.
(fixed composition) or_____
(variable composition)
Mixtures can be either fixed composition or variable composition.
A fixed composition mixture is a mixture that has a constant and unchanging composition, meaning that the proportions of the components remain the same throughout the mixture. Examples of fixed-composition mixtures include solutions, suspensions, and colloids. In a solution, for example, the solute is dissolved in the solvent in a specific ratio, and the composition of the solution remains constant. In a suspension, the particles of one substance are suspended in another substance, but the composition of the suspension remains constant. In a colloid, the particles of one substance are dispersed throughout another substance, but the composition of the colloid remains constant.
On the other hand, a variable composition mixture is a mixture that can change its composition over time. Examples of variable composition mixtures include gases and solutions that are not in equilibrium. In a gas, the molecules are free to move and interact with each other, so the composition of the gas can change over time. In a solution that is not in equilibrium, the components can separate or mix over time, leading to changes in the composition of the solution.
It's important to note that the composition of a mixture can be influenced by a variety of factors, including temperature, pressure, and the presence of other substances. For example, the composition of a solution can be affected by changes in temperature, as the solute and solvent can interact differently at different temperatures. Similarly, the composition of a gas can be affected by changes in pressure, as the molecules can move more or less freely at different pressures.
In conclusion, mixtures can be either fixed composition or variable composition, and the composition of a mixture can be influenced by a variety of factors. It's important to understand the composition of a mixture in order to understand its properties and behavior.
A rate equation can be written based on the rate constant k, concentration of reactants and half life time t1/2 of reactant if given. [A⁰] is the initial concentration of reactant A and [A]t be the final concentration.
Rate of a reaction is the rate of decrease in concentration of reactants or rate of increase in concentration of products. Rate of the reaction written in terms of molar concentration of reactants is called the rate law.
Consider the simplest reaction A gives B. Here the only one reactant is A. The molar concentration of A is written as [A]. The rate constant k is then,
k = [B] / [A]
If any coefficients attached with them it is written as power of the concentration term. Now, the rate of the above reaction is written as follows:
rate r = k [A]
Sometimes the initial and final concentrations of A can be considered. Where, [A⁰] is the initial concentration and [A]t be the final concentration.
The half life t1/2 is the time taken to consume half of the reactants concentration.
To find more about rate law, refer the link below:
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