When two gears are mashed, the revolutions per minute (rpm) are inversely proportional to the number of gears

Answers

Answer 1
Answer: Not exactly.  The RPM is inversely proportional
to the number of teeth on the gears.

Note that in order for them to stay meshed, that'salso going to work out
to be the ratio of their radii.  Otherwise they won't stay engaged.

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Generally , people water their plants with 100% H2o--- no solutes added. What sort of environment does this create around the roots of the plant? (Hypotonic, hypertonic or isotonic ) EXPLAIN!!

Answers

This is difficult to explain, but it's hypotonic. HypERtonic is where there is where the cells shrivel up because there is more solute (salt is an example of a solute) on the outside, so the water rushes outward towards it and shrivels the cell. Plants like lots of water so they like to be hypotonic, and since you're adding pure H2O, there is no solute being added, so the solute is in the cell, causing the water to rush in. Isotonic is equal throughout the solution.

When a marble is at rest what happened

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The marble will stay in place until another force pushes it

Answer: the marble will remain in place at a constant velocity of zero

Explanation:

Newton's first law states that a body at rest will remain at rest, and a body in motion will remain in motion in a straight line at a constant velocityunless acted upon by an outside force

If the core of a supernova explosion contains three or more solar masses of matter, the core will most likely become a _____.

Answers

The correct answer to the question you gave above would be a black hole. If the core of a supernova explosion contains three or more solar masses of matter, the core will most likely become a black hole. 

An object with a mass of 1.5 kg changes its velocity from +15 m/s to +22 m/s during a time interval of 3.5 seconds. What impulse was delivered to the object? 3.0 N • s 11 N • s 25 N • s 56 N • s

Answers

Answer: The impulse delivered to the object is 33 N • s.

Explanation: Impulse = Change in momentum

The momentum of an object is calculated by multiplying its mass by its velocity:

Momentum = Mass x Velocity

Given:

Mass of the object = 1.5 kg

Initial velocity = +15 m/s

Final velocity = +22 m/s

Time interval = 3.5 seconds

First, we need to calculate the change in momentum:

Change in momentum = Final momentum - Initial momentum

To find the initial momentum, we multiply the mass by the initial velocity:

Initial momentum = Mass x Initial velocity

Initial momentum = 1.5 kg x 15 m/s

To find the final momentum, we multiply the mass by the final velocity:

Final momentum = Mass x Final velocity

Final momentum = 1.5 kg x 22 m/s

Now, we can calculate the change in momentum:

Change in momentum = Final momentum - Initial momentum

Change in momentum = (1.5 kg x 22 m/s) - (1.5 kg x 15 m/s)

Simplifying the equation:

Change in momentum = 33 kg m/s

Finally, we have found the change in momentum, which is equal to the impulse delivered to the object. Therefore, the impulse delivered to the object is 33 N • s.

Answer:

11 Ns

Explanation:

Impulse = change in momentum

J = Δp

J = mΔv

J = (1.5 kg) (22 m/s − 15 m/s)

J = 10.5 kg m/s

Rounded to two significant figures, the impulse is 11 Ns.

If a 6-kg bowling ball is rolled down the bowling lane with a force of 12 N, what is the acceleration of the ball?

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A= 2M/S squared should b ur answer

A jet plane lands at a speed of 100 m/s and can accelerate at a maximum rate of -5.00 m/s^2 as it comes to a rest.(a from the instant the plane touches the runaway, what is the minimum time needed before it can come to a rest?
(b Can this plane land on a runaway that is only 0.800 km long?
shown work pls will reward alot of points

Answers

Answer:

a)   t = 20 s,  b)  x = 1000 m, As the runway is only 800 m long, the plane cannot land at this distance

Explanation:

This is a kinematics exercise

a) in minimum time to stop,

           v = vo + at

           v = 0

           t = -v0 / a

we calculate

          t = -100 / (5.00)

          t = 20 s

b) Let's find the length you need to stop

          v² = vo² + 2 a x

          x = -v0 ^ 2 / 2a

          x = - 100² / 2 (-5.00)

          x = 1000 m

As the runway is only 800 m long, the plane cannot land at this distance.