A pickup truck and a hatchback car start at the same position. If the truck is moving at a constant 33.2m/s and the hatchback car starts from rest and accelerates at 5m/s/s, how far away do the cars meet up again?

Answers

Answer 1

Answer:

Answer:

The pickup truck and hatchback will meet again at 440.896 m

Explanation:

Let us assume that both vehicles are at origin at the start means initial position is zero i.e. $s_(o)$ = 0. Both the vehicles will cross each other at same time so we will make equations for both and will solve for time.

Truck:

$v_(i)$ = 33.2 m/s, a = 0 (since the velocity is constant), $s_(o)$ = 0

Using $s =s_(o)+v_(i)t+1/2at^(2)$

s = 33.2t .......... eq (1)

Hatchback:

$a=5m/s^(2)$ , $v_(i)$ = 0 m/s (since initial velocity is zero), $s_(o)$ = 0

Using $s =s_(o)+v_(i)t+1/2at^(2)$

putting in the data we will get

$s=(1/2)(5)t^(2)$

now putting 's' value from eq (1)

$2.5t^(2)-33.2t=0$

which will give,

t = 13.28 s

so both vehicles will meet up gain after 13.28 sec.

putting t = 13.28 in eq (1) will give

s = 440.896 m

So, both vehicles will meet up again at 440.896 m.

Answer 2

Answer:

Answer:

440.9 m

Explanation:

initial speed of the pickup truck (Up) = 33.2 m/s

acceleration of the pickup truck (ap) = 0

initial speed of the hatchback = 0

acceleration of the hatchback (ah) = 5 m/s^{2}

how far away (s) do the cars meet up again?

from the equations of motion distance covered (s) = ut + $0.5at^(2)$

distance covered by the pickup = ut + $0.5at^(2)$

where

u = initial speed of the pickup = 33.2 m/s
t = time it takes
a= acceleration of the pickup = 0
the distance covered by the pickup (s) now becomes = 33.2t + $0.5.(0).t^(2)$ = 33.2t ...equation 1

distance covered by the hatchback = ut + $0.5at^(2)$

where

u = initial speed of the hatchback = 0 m/s
t = time it takes
a= acceleration of the hatchback = 5 m/s^{2}
the distance covered by the hatchback (s) now becomes = (0)t + $0.5x5t^(2)$

= $2.5t^(2)$ ......equation 2

when the cars meet, they both would have covered the same distance, therefore

distance covered by the pickup = distance covered by the hatchback
equation 1 = equation 2

33.2t = $2.5t^(2)$
33.2 = 2.5t
t = 13.28 s

now that we have the time it takes for both cars to meet, we can put the value of the time into equation 1 or equation 2 to get the distance at which they meet

from equation 1

distance (s) = 33.2t = 33.2 x 13.28= 440.9 m

from equation 2

distance (s) = $2.5t^(2)$ = $2.5x12.8^(2)$ = 440.9 m

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Convert 0.12 m to km.

Answers

Answer:

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Explanation:

I hope this answers your question.

Wave C has an amplitude of 1 and wave D has an amplitude of 3 as shown below. What will happen when the trough of wave C meets the crest of wave D?They will interfere to create a crest with an amplitude of 4.
They will interfere to create a crest with an amplitude of 2.
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They will bounce off each another.

Answers

Answer:

They will interfere to create a crest with an amplitude of 2.

Explanation:

The two waves will interfere and the resultant amplitude will be given by the principle of superposition, which states that the resultant amplitude is given by the sum (or the difference, if they meet in opposite phase) of the amplitudes of the two waves. In this case, the crest of wave C meets the through of wave D, so they are in opposite phase, therefore the resultant amplitude will be

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When two objects collide the momentum of the system of the system stays constant . This is a statement of ____?Impulse
A change in momentum
Newton's Third Law
The conservation of Momentum

Answers

This is a statement of "The conservation of Momentum" So, Answer would be Option D

Hope this helps!

When two objects collide the momentum of the system of the system stays constant . This is a statement of ____

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All electromagnetic radiation is visible to the human eye. Please select the best answer from the choices provideda. True
b. False

Answers

The correct answer is

b. False

It's actually the opposite: only a very small part of the electromagnetic spectrum is visible to human eye.

The electromagnetic spectrum consists of a huge range of wavelengths, spanning from gamma rays (with very short wavelength, at the order of 1 pm) to radio waves (with very long wavelength, at the order of kilometers). The only portion of this spectrum visible to the human eye is the "visible light", which has wavelengths between 400 and 700 nanometers approximately.

The statement is False. All the electromagnetic radiations are not visible to the human eyes.

Explanation:

The waves are defined as the disturbance produced in the medium particles. The wave is basically the physical phenomena that occurs in a medium and it is characterized by the amplitude, wavelength and the frequency of oscillating particles.

The waves are basically characterized as the transverse and the longitudinal based on the direction of oscillation. The transverse waves are the one in which the direction of oscillation is perpendicular to the propagation whereas in longitudinal waves, the direction of oscillation is along the motion of the wave.

The electromagnetic waves are the transverse waves that are formed by the perpendicular magnetic and electric field present in the medium. The complete electromagnetic spectrum is not considered to be in the visible range for the human eye. Only a small part lying in the wavelength of $4000-7000\,\AA$ .

Thus, The statement is False. All the electromagnetic radiations are not visible to the human eyes.

Learn More:

1. Similarities between transverse and longitudinal waves brainly.com/question/3293068

2. A property is a characteristic of a substance that can be observed and does not change the identity of the substance brainly.com/question/859623

3. The amount of kinetic energy an object has depends on its brainly.com/question/137098

Answer Details:

Grade: High School

Subject: Physics

Chapter: Waves

Keywords:

electromagnetic radiation, human eye, visible, transverse, longitudinal, waves, wavelength, particles, perpendicular.

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