A small child has a wagon with a mass of 10 kilograms. The child pulls on the wagon with a force of 2 newtons. What is the acceleration of the wagon?

Answers

Answer 1
Answer: F=ma
where:
F - force
m - mass
a - acceleration 

We transform this formula to get a:
a= (F)/(m)
a=(2)/(10)(N)/(kg)=0.2(m)/(s^(2))
Answer 2
Answer:

Answer:

the Correct answer is 0.2

Explanation:


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Explain why ventilation is very important if there is a risk of exposure to radon gas in your home or school

Answers

Ventilation is very important if there is a risk of exposure to radon gas in your home or school because ventilation will help you not to inhale all of the radon particles in your body. Radon gas is dangerous because it does not smell and you cannot see it with your own eyes. Also, it is very toxic and radioactive.

The heat capacity of an object depends in part on its _____. A. mass B. enthalpy C. shape D. potential energy

Answers

The correct answer to the question that is being presented above would be letter A. mass. The heat capacity of an object depends in part on its mass. All the other choices do not fit the description that needs to be answered.

You run to your girlfriend's house and announce that you were running at a rate of 15 miles per hour. She knows this is not true because she knows

Answers

Answer:how long it took you to get there and the distance between your house and her house

Explanation:

An upward force is applied to a 6.0–kilogram box. this force displaces the box upward by 10.00 meters. what is the work done by the force on the box?

Answers

Answer:

The work done by the force on the box is W = 588 J

Explanation:

The work done by the force on the box can be expressed as:

W=mg(h_(2)-h_(1))

where m is the mass of the box, g is the gravitational force g=g=9.8(m)/(s^(2)) and h_(2), h_(1) are the heights of the box in at final and initial moment.

Replacing the values, you have:

W=6.0kg*9.8(m)/(s^(2))*(10.00m-0.00m)

W=588(kgm^(2))/(s^(2))

that is W = 588 J

work = fs = mgh [Ep] = 6(10)(10) = 100

A subway train starts from rest at a station and accelerates uniformly at 1.8m/s^2 for 15 sec. then it runs at a constant speed for the next 35 sec. before decelerating at 2.0m/s^2 until it comes to rest at the next station. FIND THE DISTANCE between the stations and the AVERAGE SPEED of the train.(please show step by step and the formula that is used. Thank you!)

Answers

This looks so scary just because there are so many parts to it.
Take them one at a time:

First piece:
From rest, accelerates 1.8 m/s² for 15 sec.
Speed at the end of the 15 sec = 1.8 x 15 = 27 m/s
Distance covered = (average speed) x (time) = (13.5) x (15) = 202.5 meters

Middle piece:
Starts this piece at 27 m/s.
Runs at constant speed for 35 sec.
Covers (27 x 35) = 945 meters
Finishes this piece (15 + 35) = 50 seconds after leaving the first station
Finishes this piece (202.5 + 945) = 1147.5 meters from the first station.

Last piece:
Starts this piece 50 seconds after leaving the first station,
         1147.5 meters from it, still moving at 27 m/s.
Decelerates at 2.0 m/s² .
--> It takes 27/2.0 = 13.5 seconds to come to a stop.
--> Distance covered during this piece = (average speed) x (time)
           = (13.5 m/s) x (13.5 sec) = 182.25 meters
Finishes this piece (50 + 13.5) = 63.5 seconds after leaving the first station
Finishes this piece (1147.5 + 182.25) = 1,329.75 m from the first station  

Distance between the stations (along the track) = 1,329.75 meters.

Average speed = (total distance) / (total time) = 1,329.75 / 63.5 = 20.941 m/s.

I sure hope I didn't make any stupid arithmetic blunders here,
because I really don't feel like going back and checking it.
Let me know, and I'll fix them.


Whats the answer
----------------------------

Answers

Answer:

repel each other

Explanation:

The magnitude of the charge of an electron is called... ... If a positively-charged glass rod is suspended so that it turns easily and another positively-charged glass rod is brought close to it, the two rods will... Repel each other.