A 2.00 × 103 kg car rounds a circular turn of radius 20.0 m. If the road is flat and the coefficient of static friction between the tires and the road is 0.70, how fast can the car go without skidding?

Answers

Answer 1
Answer:

Answer:

11.7 m/s

Explanation:

In order for the car to remain in circular motion along the road and not to skid, the frictional force between the tires and the road must be equal to the centripetal force.

Therefore, we can write:

\mu mg = m(v^2)/(r)

where:

m = 2000 kg is the mass of the car

\mu=0.70 is the coefficient of friction

g=9.8 m/s^2 is the acceleration due to gravity

v is the speed of the car

r = 20.0 m is the radius of the turn

Substituting and solving for v, we find the speed of the car:

v=√(\mu gr)=√((0.70)(9.8)(20.0))=11.7 m/s


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Explain the right-hand rule as it applies to rotation of winds around a high or low pressure center.

Answers

Explanation:

The right-hand rule, also known as the Buys-Ballot's law, helps explain the rotation of winds around high and low pressure centers in the Northern Hemisphere. According to this rule:

1. In a low pressure center (cyclone) in the Northern Hemisphere, the wind rotates counterclockwise around the low-pressure center. If you extend your right hand with your thumb pointing upwards, your fingers will curl in the counterclockwise direction, representing the direction of the winds.

2. In a high pressure center (anticyclone) in the Northern Hemisphere, the wind rotates clockwise around the high-pressure center. If you extend your right hand with your thumb pointing upwards, your fingers will curl in the clockwise direction, representing the direction of the winds.

This rule is based on the Coriolis effect, which is caused by the Earth's rotation. As air flows from areas of higher pressure to lower pressure, it is deflected by the Coriolis force due to the Earth's rotation. In the Northern Hemisphere, the Coriolis force deflects moving air to the right. This deflection, combined with the pressure gradient force, results in the counterclockwise rotation around low-pressure centers and clockwise rotation around high-pressure centers.

It is important to note that the right-hand rule is specific to the Northern Hemisphere. In the Southern Hemisphere, the opposite is true. The wind rotates counterclockwise around low-pressure centers and clockwise around high-pressure centers.

Understanding the rotation of winds around pressure centers is essential in meteorology for predicting weather patterns and systems. By studying these rotations, meteorologists can make informed forecasts and predictions about the movements and impacts of weather systems.

If the plotted points on a speed-time graph do not form a straight line, what do you know about the object's acceleration?

Answers

Remember, that while sped is constant, acceleration is not. Acceleration is when velicity changes. So the graph which shows the slop of a velocity vs time describes acceleration.
If we have the straight line on the graph it means that the slope is always the same whereas the non-linear graphs has a variable slope that changes depending on your point in the graph.
To conclude - if your graph is not a straight line it has variable acc at many points.

Final answer:

A speed-time graph where the points do not form a straight line indicates that the object is accelerating in a non-uniform way, meaning its acceleration is changing over time.

Explanation:

If the plotted points on a speed-time graph do not form a straight line, this indicates that the object is accelerating in a non-uniform way. Instead of maintaining a constant rate of acceleration (represented by a straight line), the object's acceleration is changing over time. This could mean that the object is speeding up, slowing down, or changing direction. For example, a curved line might represent a car that starts off slowly, then accelerates rapidly before braking.

Learn more about Acceleration here:

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a water skier is pulled behind a boat by a rope the rope has a tension of 290 N and is at an angle of 33 degrees what is the x-component of the tension?

Answers

By analysis of the problem and drawing a mental figure, we can solve this by using trigonometric functions. It is safe to say that the tension in the rope is the hypotenuse. So to find for the x-component:

cos 33 = x/290
x = 290 * cos 33
x = 243.21 units

Therefore, the x-component of tension is equal to 243.21 units

Answer:

243 N

Explanation:

Draw velocity-ime graph for uniform moion of an object , when initially body is at rest.

Answers

When the body is at rest, its speed is zero, and the graph lies on the x-axis.

When the body is in uniform motion, the speed is constant, and the graph is a horizontal line, parallel to the x-axis and some distance above it.

It's impossible to tell, based on the given information, how these two parts of the
graph are connected.  There must be some sloping (accelerated) portion of the graph
that joins the two sections, but it cannot be accounted for in either the statement
that the body is at rest or that it is in uniform motion, since acceleration ... that is,
any change of speed or direction ... is not 'uniform' motion'.

Complete the passage to describe wave interaction of diffracted waves.Diffracted waves of light interact with other waves and interference occurs. When the interference is constructive, this is shown as a

band on the screen. When the interference is destructive, this is shown as a

band on the screen.

Answers

Answer: When the interference is constructive, this is shown as a bright band on the screen. When the interference is destructive, this is shown as a dark band on the screen.

Explanation: edge 2021

Answer:Bright and Dark

Explanation:

Wich is a scalar quantity
(1)velocity (2)speed (3)acceleration (4) displacement

Answers

Speed is the only one on the list
that doesn't have a direction.