One component of a magnetic field has a magnitude of 0.0404 T and points along the x axis while the other component has a magnitude of 0.0739 T and points along the y axis A particle carrying a charge of 2.80 10 5 C is moving along the z axis at a speed of 4.46 103 m s a Find the magnitude of the net magnetic force that acts on the particle b Determine the angle that the net force makes with respect to the x axis

Answers

Answer 1

Answer:

Answer:

as we find the resultant of the magnetic field we get in the xy plane. Just perpendicular to this plane i.e. along z-axis the charge is moving. Hence the force acting on the charge will also be in the xy plane.

Net field = ./(0.078^2 +0.070^2) = 0.105 T

Angle with x axis is arc tan 0.070/0.072 = 44.2 deg

So the force acting on the moving charge is got by Bqv

0.105*5.5*10^-5 * 6*10^3 = 0.03465 N

So the angle inclined by this force with x axis will be 90+44.2 = 134.2

Explanation:

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Three 9W -3 V bulbs is to be lighted by a suppy of 12 Volt.For this,a wire is to be connected in series with it.Th resistance of the wire should be:A) 1 B) 2 C) 3 D) 4

A series circuit contains four light bulbs. The switch is opened and one of the bulbs is removed, but not replaced. Then the switch is closed again. What would you expect to see?A) All three remaining light bulbs will be on.
B) None of the remaining light bulbs will be on.
C) Only the bulb closest to the switch will be on.
D) All three remaining light bulbs will be brighter than before.

Answers

The correct answer is option B) None of the remaining light bulbs will be on.

What will happen if one light bulb is removed from a series circuit?

In a series connection when a bulb is removed, it will be creating a open circuit. Since the circuit is series and is open at a point current will not flow and hence the other bulb will not glow.

Why did the series circuit stop working when one of the light bulbs was removed?

That's because the basic requirement for the circuit to operate a continuous, closed-loop path is no longer met. This is the main disadvantage of a series circuit. If any one of the light bulbs or loads burns out or is removed, the entire circuit stops operating.

Learn more about the series circuit here: brainly.com/question/19865219

#SPJ

for series circuit, components are in the same path. removing component, the path is broken. so without replacing the bulb, current could not flow -- open circuit. all bulbs are dead.

Suppose you hit a 0.058-kg tennis ball so that the ball then moves with an acceleration of 10 m/s2. if you were to hit a basketball of mass 0.58 kg with the same force, what would the acceleration a of the basketball be? *graph is 4/x if that helps.

Answers

In this problem, the working equation to be used is the Newton's 2nd law of motion: Force = mass x acceleration.

First situation: mass = 0.058 kg; acceleration = 10 m/s2

Hence, force is 0.058 kg x 10 m/s2, which is 0.58 N. Since same force is to be used, this same value is used for the second situation.

Second situation: mass = 0.58 kg; Force = 0.58 N

Since F = ma, by transposing, the acceleration could be solved by the equation, a = F/m. Thus, 0.58N/0.58 kg, the acceleration is 1 m/s2.

A speeder passes a parked police car at a constant speed of 23.3 m/s. At that instant, the police car starts from rest with a uniform acceleration of 2.75 m/s 2 . How much time passes before the speeder is overtaken by the police car? Answer in units of s.

Answers

Answer:

32s

Explanation:

We must establish that by the time the police car catches up to the speeder, both have travelled a certain distance during the same amount of time. However, the police car experiences accelerated motion whereas the speeder travels at a constant velocity. Therefore we will establish two formulas for distance starting with the speeder's distance:

$x=vt=23.3(m)/(s)t$

and the police car distance:

$x=vt+(at^(2))/(2)=0+(2.75(m)/(s^(2)) t^(2))/(2)=0.73(m)/(s^(2))$

Since they both travel the same distance x, we can equal both formulas and solve for t:

$0 = 0.73(m)/(s^(2))t^(2)-23.3(m)/(s) t\n\n0=t(0.73(m)/(s^(2))t-23.3(m)/(s) )\n\n$

Two solutions exist to the equation; the first one being $t=0$

The second solution will be:

$0.73(m)/(s^(2))t=23.3(m)/(s)\n\nt=(23.3(m)/(s))/(0.73(m)/(s^(2)))=32s$

This result allows us to confirm that the police car will take 32s to catch up to the speeder

Write the different between the fall of a parachute on earth and its fall on the moon?on what condition does a body have free fall?

Answers

Answer:

Shown from explanation

Explanation:

You have heard that expression what ever goes up must come down that's usually used to mean when you throw an object up, it comes down on its accord. This is due to a force on the earth that occurs in nature known as gravity.

So when an object falls under this influence it's said to fall freely.

Note not all heavenly bodies have gravitational pull, from experience by scientists who went to the moon they found out whatever goes up keeps flying endlessly so in that case an external force is needed to keep objects in the moon on ground level.

Hence the parachute falls on earth freely without an external force but on the moon it must fall with an external force inputed on the parachute system.

This means in the earth we have free fall but in the moon no such thing exist. So a body falls freely when there is gravity.

Which of the following areas would most likely have the deepest layer of topsoil?

Answers

Desert

The loss of top soil in very dry areas of the world is known as desertification. Desertification is the phenomenon in which land degradation of a very dry region increases and the water bodies typically dries up. This also results in not only loss of vegetation but also animal life. This phenomenon can be caused not only due to climate changes, but also due to human activities.

Answer:

It's C. Grasslands

Explanation: hope it helps ^w^

What is the equivalent resistance for a parallel circuit that has two resistors: 18.0 ohms and 23.5 ohms?

Answers

With only two resistors in parallel, it's relatively easy
to calculate their combined equivalent resistance.

   R = (their product) / (their sum)

   = (18Ω x 23.5Ω) / (18Ω + 23.5Ω)

   =         (423Ω²) / (41.5Ω)

   =    10.2 Ω

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