PHYSICS HIGH SCHOOL

A 111 ‑turn circular coil of radius 2.11 cm and negligible resistance is immersed in a uniform magnetic field that is perpendicular to the plane of the coil. The coil is connected to a 14.1 Ω resistor to create a closed circuit. During a time interval of 0.125 s, the magnetic field strength decreases uniformly from 0.669 T to zero. Find the energy, in millijoules, that is dissipated in the resistor during this time interval.

Answers

Answer 1

Answer:

0.0061 J

Explanation:

Parameters given:

Number of turns, N = 111

Radius of turn, r = 2.11 cm = 0.0211 m

Resistance, R = 14.1 ohms

Time taken, t = 0.125 s

Initial magnetic field, Bin = 0.669 T

Final magnetic field, Bfin = 0 T

The energy dissipated in the resistor is given as:

E = P * t

Where P = Power dissipated in the resistor

Power, P, is given as:

P = V² / R

Hence, energy will be:

E = (V² * t) / R

To find the induced voltage (EMF), V:

EMF = [-(Bfin - Bin) * N * A] / t

A is Area of coil

EMF = [-(0 - 0.669) * 111 * pi * 0.0211²] / 0.125

EMF = 0.83 V

Hence, the energy dissipated will be:

E = (0.83² * 0.125) / 14.1

E = 0.0061 J

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A sewing machine needle moves up and down in simple harmonic motion with an amplitude of 1.27 cm and freuency of 2.55 Hz.(a) what's the maximum speed of the needle ?
(b) what's the maximum acceleration of the needle ?

Answers

Answer:

The tip of the needle to move from the highest point to the lowest point in 0.4 sec and the needle tip to travel a total distance in 0.9 sec.

Explanation:

Given that,

Frequency = 2.5 Hz

Amplitude = 1.27 cm

(a). We need to calculate the time

The frequency is the reciprocal of the time.

The time taken from highest point to lowest point

(b). We need to calculate the time

The time taken in one cycle = 0.4 sec

The distance covered in one sec= 4 times x amplitude

We need to calculate the speed

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Just after a motorcycle rides off the end of a ramp and launches into the air, its engine is turning counterclockwise at 8325 rev/min. The motorcycle rider forgets to throttle back, so the engine's angular speed increases to 12125 rev/min. As a result, the rest of the motorcycle (including the rider) begins to rotate clockwise about the engine at 4.2 rev/min. Calculate the ratio IE/IM of the moment of inertia of the engine to the moment of inertia of the rest of the motorcycle (and the rider). Ignore torques due to gravity and air resistance.

Answers

Answer:

$(Ie)/(lm) = 1.10*10^(-3)$

Explanation:

GIVEN DATA:

Engine operating speed nf = 8325 rev/min

engine angular speed ni= 12125 rev/min

motorcycle angular speed N_m= - 4.2 rev/min

ratio of moment of inertia of engine to motorcycle is given as

$(Ie)/(lm) = (-N)/((nf-ni))$

$(Ie)/(lm) = (-(-4.2))/((12125 - (8325)))$

$(Ie)/(lm) = 1.10*10^(-3)$

Answer: $1.105* 10^(-3)$

Explanation:

Given

Initial angular speed of engine( $\omega _E$ )=8325 rpm

Final angular speed of engine( $\omega _E_f$ )=12125 rpm

Initial angular speed of Motorcycle( $\omega _M$ )=0 rpm

Final angular speed of engine( $\omega _M_f$ )=4.2 rpm

as there is no external torque therefore angular momentum remains conserved

$I_E\omega _E+I_M\omega _M=I_E\omega _E_f+I_M\omega _M_f$

$I_E\omega _E+=I_E\omega _E_f+I_M\omega _M_f$

$I_E\left ( \omega _E-\omega _E_f\right )=I_M\omega _M_f$

$(I_E)/(I_M)=(\omega _M_f)/(\omega _E-\omega _E_f)$

$(I_E)/(I_M)=(-4.2)/(8325-12125)=0.0011052\approx 1.105* 10^(-3)$

Recompose the displacement vector, d, with the following X and Y components. Dy = 9.04 m down and Dx =6.68 m left

Answers

The displacement vector, d, can be recomposed as follows: d = (Dx, Dy) and the magnitude of the displacement vector is approximately 11.24 meters.

To recompose the displacement vector, d, using the given X and Y components, you can use vector addition. The X and Y components represent the horizontal and vertical displacements, respectively.

Given:

Dx = 6.68 m (left)

Dy = 9.04 m (down)

The displacement vector, d, can be recomposed as follows:

d = (Dx, Dy)

So, the displacement vector is (6.68 m left, 9.04 m down). This means that the object moved 6.68 meters to the left (in the negative X direction) and 9.04 meters downward (in the negative Y direction) from its starting point.

The magnitude of the displacement can be found using the Pythagorean theorem:

|d| = √((Dx)^2 + (Dy)^2)

|d| = √((6.68 m)^2 + (9.04 m)^2)

|d| ≈ √(44.49 m^2 + 81.72 m^2)

|d| ≈ √(126.21 m^2)

|d| ≈ 11.24 meters

So, the magnitude of the displacement vector is approximately 11.24 meters.

Learn more about displacement vector here:

brainly.com/question/30615410

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What is the leading cause for change between states of matter?

Answers

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Which of the following best describes a plane? A. The edge of a desk
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Answers

The only item on that list that's a plane is the surface of a flat table. The edge of a desk is a rectangle, square, circle, etc. The intersection of two walls is a part of a straight line. A curve in a road is a part of a circle.

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Answers

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It's greatest at the positive terminal of the battery or power supply.

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