You are 15.0m from the source of a sound. At that distance, you hear it at a sound level of 20.0dB. How close must you move to the sound to increase the sound level to 60dB?I think its 45.0cm?
15.0cm
45.0cm
55.0cm
60.0cm
85.0cm
Answers
Answer:
Explanation:
its 85 cm because it just is in meters it would be .8m which would be decent distance to hear it
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If you are bombarded with 1.00 mol of photons with a wavelength of 370 nm, you are being subjected to 322 kJ/mol of energy.
The energy of a photon is given by the equation:
E = hc/λ
where:
h = Planck's constant = 6.626 x J s
c = speed of light = 2.998 x m/s
λ = wavelength of the radiation
To find the energy of a mole of photons, we need to multiply the energy of a single photon by Avogadro's number (6.022 x ).
First, we need to convert the wavelength of the radiation from nanometers to meters:
370 nm = 370 x m
Now, we can use the equation to calculate the energy of a single photon:
E = hc/λ
E = (6.626 x J s) x (2.998 x
m/s) / (370 x
m)
E = 5.35 x J
Next, we can calculate the energy of a mole of photons:
(5.35 x J/photon) x (6.022 x
photons/mol) = 3.22 x
J/mol
Finally, we can convert the energy to kilojoules per mole of photons:
3.22 x J/mol = 322 kJ/mol
To know more about wavelength refer here
brainly.com/question/31143857#
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b. 15 days
c. 30 days
d. 60 days
Answers
Answer:
C. 30 years
Explanation:
Half life of a radioactive substance is defined as the time taken by the substance to decay to half of its original value.
The number of days it will take for one half of the original amount of a radioactive substance to decay given the half life of 30 years will be that same 30years according to the half life definition.
According to the formula for half life t1/2 = ln2/¶ where ¶ is the decay constant.
¶ = ln2/t1/2
¶ = ln2/30
¶ = 0.023
Using the radioactivity formula to get the time it will take 1/2 of the original amount to decay, we have;
N/No = e^-¶t where
N/No is the fraction of amount decayed at time t i.e 1/2
Substituting the given values in the equation, we have;
1/2 = e^-0.023t
ln1/2 = lne^-0.023t
ln1/2 = -0.023t
t = ln0.5/-0.023
t = 30years.