A cylindrical pop can us 12.5 cenimeters tall and 5.5 centimeters wide. what is the volume of the pop can

Answers

Answer 1

Answer: The width is basically the diameter:
Given
Diameter = 5.5 cm
So Radius = $(d)/(2)$ = $(5.5)/(2)$ = 2.75 cm
Height of cylinder = 12.5 cm

Formula of the volume of a cylinder
V = Area of base × height of prism
= $\pi$ r² × h
=(2.75)² ( $\pi$ ) × 12.5
=7.5625 $\pi$ × 12.5
≈ 296.83 cm³

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Divide 2 1/2 by 1 5/8=

Answers

1) Convert the mixed numbers into improper fractions (ex. 2 1/3 ÷ 4 1/2= 7/3 ÷9/2)
2) Find the reciprocal of the SECOND number. Then change the division sign to a multiplication sign. (ex. 7/3 ÷ 9/2=7/3×2/9)
3)Multiply and you've got your answer! (ex. 7/3×2/9=14/27)
Hope this helped!

Convert 2 1/2 into an improper fraction, that should be 5/2.
Now converg 1 5/8 into an improper fraction and and its 13/8

Then set up the divsion problem and flip 13/8 into 8/13 and cross reduce to give you 5/1 times 13/4 qnd multiply qnd then tuen it back into a mixed number and the anwser is 1 17/13

How does one solve this question, any help would be appreciated! I feel this has a really easy solution and I've decided to significantly over-complicate it.13. a) Write down the equation of the line with gradient 3 passing through (0, -2)

b) Write down the equation of the line which is parallel to the line y=4-5x passing through (0,-1)

Answers

Hello,

a)
the gradient is the slope:

y+2=3(x-0) or y=3x-2

b) slope is -5 (parallele to y=-5x+4)

y+1=-5(x-0) or y=-5x-1

If one honeybee makes 1/12 teaspoon of honey during its lifetime, how many honeybees are needed to make 1/2 teaspoon of honey

Answers

In this case we have to have a common denominator in order to compare to the two fractions.
$(1)/(2) = (x)/(12)$ We know that 2 × 6= 12
So multiply the numerator and denominator by 6
$(1)/(2)$ × $(6)/(6) = (6)/(12)$
Therefore, the amount of honey needed is $(6)/(12)$ teaspoons
So in total 6 bees are needed to make $(1)/(2)$ teaspoons of honey because we know that $(6)/(12)$ is the same as half

One highlighter has a mass of 11 grams. Another highlighterhas a mass of 10,800 milligrams. Which highlighter has the
greater mass?

Answers

10,800 milligrams equals 10.8 grams so that the first highlighter has the greater mass

The highlighter that had a mass of 11 grams has a greater mass. 11 grams = 11000.

I don’t understand
I'm stupid, I don't understand mathematics :(

Answers

(1,-2) Don’t really know how I can explain it to you but this is the answer...

anthony made 6 bouquets.if he used 3/4 of a bunch of flowers for each bouquet how many flower bunches did he need

Answers

So first you have to times 6 and 3/4
to do that you have to make a equation like 6/1*3/4=?
So next you multiply six and three to get 6/1*3/4=18/?
then multiply the bottom one and four to get 6/1*3/4=18/4
then simplfy to get 4 2/4 but you can't have half a bouquet of flowers so you round up to five

He needed 4 1/2 bunches So 5 bunches

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