Can you have 2 vertical asymptotes?

Answers

Answer 1
Answer: YES. you can have 2 vertical asymptotes.

Answer 2
Answer: So I'll set the denominator equal to zero and solve. Since I can't have a zero in the denominator, then I can't have x = –4 or x = 2 in the domain. This tells me that the vertical asymptotes (which tell me where the graph can not go) will be at the values x = –4 or x = 2. hope this helped.:)

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Read the real-world situation and substitute in values for the projectile motion formula. Then solve the resulting quadratic equation by factoring to answer the question. An airplane pilot jumps out of an airplane and has an initial velocity of 60 feet per second downwards. How long does it take to fall from 1000 feet to 900 feet before the parachute opens? The pilot falls for seconds before the parachute opens.

Answers

Solving quadratic equation 16 t² -60t -100=0 formed by Projectile Motion Formula and given conditions it is found that it takes t = 5 seconds to fall from 1000 feet to 900 feet before the parachute opens.

What is a quadratic equation?

Quadratic equation is an equation which contains one unknown variable and the highest power of this unknown variable is 2. Let x be the unknown variable then the standard quadratic equation in x is given by

ax²+bx+c =0, where a, b, c are constants and a≠0

We can solve this equation by factorizing ax²+bx+c and  putting those factors equal to zero to solve for x.

Projectile Motion Formula h = -16 t² + v t + s,

where t = time in seconds

h = height of the projectile

v = initial velocity

s= starting height of fall

Given s = 1000 feet, v= 60 feet per second, h = 900 ft

And t we have to find.

Projectile motion equation becomes:

900 = -16 t² + 60 t + 1000

⇒16 t² -60t + 900-1000=0

⇒16 t² -60t -100=0, which is a quadratic equation in variable t

Factorizing this quadratic equation

⇒ 16t² - 80t + 20t -100 =0

⇒16t(t -5) + 20( t - 5 ) =0

⇒ (16t +20) ( t-5)=0

Putting these factors equal to zero

16t +20 =0 ⇒ t = -20/16, which is neglected as time cannot be negative.

t-5 = 0⇒ t =5

Therefore it takes 5 seconds to fall from 1000 feet to 900 feet before the parachute opens.

Also, Learn more about the quadratic equations from the link below:

brainly.com/question/17177510

#SPJ1

Answer:It will take 5 sec for a parachute to open.I did it on a piece of paper for u to show u more information

Step-by-step explanation:

G(X) = -3/2x
Find g(4)

Answers

substitute 4 as x in both sides of the equation

basically multiply -3/2 by 4


g(x)= -3/2x

x=4

g(4) = - 3/2 * (4) = -(3*4)/(2) = -(12)/(2) =-6

g(4) = - 6

Two lines, C and D, are represented by the equations given below:Line C: y = x + 12
Line D: y = 3x + 2

Which of the following shows the solution to the system of equations and explains why? (5 points)


(4, 14), because one of the lines passes through this point
(4, 14), because the point lies between the two axes
(5, 17), because both lines pass through this point
(5, 17), because the point does not lie on any axis

Answers

Line C: y = x + 12
Line D: y = 3x + 2

(4,14)
C: y = 4 + 12 = 16
D: y = 3(4) + 2 = 12 + 2 = 14

(5,17)
C: y = 5 + 12 = 17
D: y = 3(5) + 2 = 15 + 2 = 17

(5,17) shows the solution to the system of equations, because both lines pass through this point.

A square quilt for a child’s bed has a border made up of 44 pieces with an area of x each, and 4 small squares with an area of 1 square inch each. The main part of the quilt is made of 121 squares with an area of x 2 each. Find an expression for the area of the quilt.

Answers

Answer:

A = ( 11x + 2 )²

Step-by-step explanation:

To find the total area of the quilt, we need to add up all the areas given:

If the border has 44 pieces with an area of x each one, that area is 44x.

The area of 4 squares of 1 in² each is 4×1 in² = 4 in².

The main part is made up of 121 squares with an area of x², which is 121x².

Adding those areas up, we get the expression for the total area:

A = 121x² + 44x + 4

You can easily notice that 121 = 11² and 4 = 2². If you double its product (2·11·2) = 44

So:

A = ( 11x + 2 )²

Scrooge-Oh! But he was a tight-fisted hand at the grindstone! Scrooge! a
squeezing, wrenching, grasping, scraping, clutching, covetous old
sinner! Hard and sharp as flint, from which no steel had ever struck out
generous fire; secret, and self-contained, and solitary as an oyster. The
cold within him froze his old features, nipped his pointed nose, shrivelled
his cheek, stiffened his gait; made his eyes red, his thin lips blue; and
spoke out shrewdly in his grating voice. A frosty rime' was on his head,
and on his eyebrows, and his wiry chin. He carried his own low
temperature always about with him; he iced his office in the dog-days;
and didn't thaw it one degree at Christmas.
a stone for sharpening knives
2-wanting what someone else owns
3- frost
1. How is language used in this extract to describe Scrooge?
2. Write a description of an unusual character-real or
imagined

Answers

Answer:

Step-by-step explanation:

Use the Law of Sines to solve the following triangle. Approximate your answers to the nearest tenths. c = 10.2 in, A = 45.1° B = 75.8°

Answers

law of sines says
a/sinA=b/sinB=c/SinC
where a,b,c are sides of a triangle and A,B,C are angles respectively.
a/sin45.1=c/sin59.1

(we can find angle C by sum of angles of a triangle is 180.)

a=sin(45.1) x 10.2/sin (59.1)

a=0.708 x 10.2/0.85
a=8.496
a=8.5 units

now u can find b and c sides.