PHYSICS HIGH SCHOOL

What happens to light when it enters a lens? A. It speeds up.

B. It is reflected.

C. It is refracted.

D. It becomes brighter.

Answers

Answer 1
Answer: Good Morning! When the light passes through a lens - whether of increase or withdrawal - it tends to be refracted, that is, to suffer a deviation in its trajectory. Depending on the type of lens, it may be that some of the light is reflected too, but this is not the common parameter. Correct letter is therefore c). Hugs!Hope this helps. Let me know if you need additional help!
Answer 2
Answer:

Answer: i think the answer is c hope this helps

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A man begins pushing a lwan mower across a lawn from a standing start. Which is true? A. The man is decreasing the kinetic energy of the lawn mower B. the man is increasing the kinetic energy of the lawn mower C. the kinetic energy of the lawn mower is not changing D. you cannot tell whether the kinetic energy of hte lawn mower is increasing or decreasing from the info given

Answers

Kinetic energy is energy in motion. With that in mind, at a stand still, an object has almost no kinetic energy. Since he is starting to push it, which is moving it, he is increasing the kinetic energy.

B

A rigid, 2.50 L bottle contains 0.458 mol He. The pressure of the gas inside the bottle is 1.83 atm. If 0.713 mol Ar is added to the bottle and the pressure increases to 2.05 atm, what is the change in temperature of the gas mixture?The initial temperature of the gas is ______ K.

Answers

These are inert gases, so we can assume they don't react with one another. Because the two gases are also subject to all the same conditions, we can pretend there's only "one" gas, of which we have 0.458+0.713=1.171 moles total. Now we can use PV=nRT to solve for what we want.

The initial temperature and the change in temperature. You can find the initial temperature easily using PV=nRT and the information provided in the question (before Ar is added) and solving for T.

You can use PV=nRT again after Ar is added to solve for T, which will give you the final temperature. The difference between the initial and final temperatures is the change. When you're solving just be careful with the units!
 
SIDE NOTE: If you want to solve for change in temperature right away, you can do it in one step. Rearrange both PV=nRT equations to solve for T, then subtract the first (initial, i) from the second (final, f):

PiVi=niRTi --> Ti=(PiVi)/(niR)
 
PfVf=nfRTf --> Tf=(PfVf)/(nfR)

ΔT=Tf-Ti=(PfVf)/(nfR)-(PiVi)/(niR)=(V/R)(Pf/nf-Pi/ni)

In that last step I just made it easier by factoring out the V/R since V and R are the same for the initial and final conditions.

A rigid, 2.50 L bottle contains 0.458 mol He. The pressure of the gas inside the bottle is 1.83 atm. If 0.713 mol Ar is added to the bottle and the pressure increases to 2.05 atm, what is the change in temperature of the gas mixture?

The initial temperature of the gas is

wrong 137

⇒ 122 K.  correct on E.D.G

As more lamps are put into a series circuit, the overall current in the circuit a. Increasesb. Decreasesc. Remains the same

Answers

Answer:

b. Decreases

Explanation:

The total resistance of a series circuit is equal to the sum of the individual resistances:

R_T=R_1+R_2+...+R_n (1)

Therefore, as we add more lamps, the total resistance increases (because we add more positive tems in the sum in eq.(1).

The current in a circuit is given by Ohm's law:

I=(V)/(R_T)

where V is the voltage provided by the power source and R_T is the total resistance. We notice that the current, I, is inversely proportional to the total resistance: therefore, when more lamps are added to the series circuit, the total resistance increases, and therefore the current in the circuit decreases.

A 70.0 kg skier is at rest at the top of a 120m hill. Assuming friction is negligible.A) What is the speed of the skiers at the bottom of the hill?

Answers

Answer:

49 m/s

Explanation:

Initial potential energy = final kinetic energy

PE = KE

mgh = ½ mv²

v = √(2gh)

v = √(2 × 10 m/s² × 120 m)

v = 49 m/s

when the lowest frequency above the fundamental is played, at what height will the particles' displacement be out of phase and have the same amplitude as that of the particles 8.0cm above the surface of the water? give your answer as a distance above the surface of the water.

Answers

Answer:

theg watte wil shajka

Explanation:

bshswu

Please help me! In a collision, Kara Less who was traveling at 11 m/s while texting in her 1300 kg car, is struck by another vehicle and finds herself and her phone suddenly moving 2.5 m/s in the opposite direction. What impulse does she experience? SHOW WORKAnswer Choices

A. -12,000
B. -14,000
C. -16,000
D. -18,000

Answers

Answer:

D. -18,000

Explanation:

Let's define impulse :

  • Impulse is defined as the product of Force ( N ) applied on the body and the time of impact ( s ) or
  • The change in momentum

hence in this question ,

kara is initially moving with the :

  • velocity v_(i) = 11 ms^(-1)
  • finally moving with velocity v_(f) = -2.5 ms^(-1)    (minus as she moves in the opposite direction )

therefore the initial momentum p_(i) = m*v_(i)  = 1300*11 = 14300 kgms^(-1)

and the final momentum p_(f) = m*v_(f) = 1300*-2.5= 3250 kgms^(-1)

thus the change in momentum : p_(f) - p_(i)

= -3250-14300 = -17550 kgms^(-1) ≅ -18000kgms^(-1)
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