MATHEMATICS HIGH SCHOOL

The population of a pack of wolves is 88. The population is expected to grow at a rate of 2.5% each year.Which function equation represents the population of the pack of wolves after t years?

f(t)=88(0.025)^t

f(t)=88(1.025)^t

f(t)=88(1.25)^t

f(t)=88(2.5)^t

Answers

Answer 1
Answer:

Answer:

Option B is correct.

f(t) = 88(1.025)^trepresents the population of the pack of wolves after t years

Step-by-step explanation:

The exponential growth function is given by;

f(t) = a(1+r)^t               ......[1]

where

a represented the initial value

r represents the rate(in decimal)

t represents the time in years

As per the given statement: The population of a pack of wolves is 88. Also, the population is expected to grow at a rate of 2.5% each year.

⇒ a = 88 and  r =2.5% = 0.025.

Substituting these values in equation [1], we have;

f(t) = 88(1+0.025)^t

or

f(t) = 88(1.025)^t

Therefore, the population model of the pack of wolves after t years is given by:  f(t) = 88(1.025)^t

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Answers

Answer:

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Step-by-step explanation:

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Answers

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Answer:

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Step-by-step explanation:

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Answers

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Answer:

could have just said b

Step-by-step explanation:

to the guy above who answered

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Answers

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