Keiko is mixing 4 cups of concrete to make a stepping stone. She needs 1.5 cups of sand and 2.5 cups of cement mix. Which statement best describes how much of each ingredient Keiko needs to measure? A. Keiko should make it easy and just measure about 1 cup of sand and 3 cups of cement mix since she needs a total of 4 cups. B. Keiko should measure exactly 1.5 cups of sand and 2.5 cups of cement mix to be sure the concrete will set properly. C. Keiko should make it easy and just measure about 2 cups of each since she needs a total of 4 cups.
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Step 2: x = 30 – 5
Step 3: x = 25
Part A: Is Charlie's solution correct or incorrect? If the solution is incorrect, explain why it is incorrect and show the correct steps to solve the equation. (6 points)
Part B: How many solutions will this equation have? (4 points)
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Answer: A) Yes, his solution is incorrect.
B) The given equation has 1 solution.
Step-by-step explanation:
A) Here, the given expression is,
Thus, the steps of solving the given expression are as follow,
Step 1:
Ste 2 :
Step 3 :
Hence, by the above explanation,
It is clear that the given steps of the solution are incorrect.
B) Since, x has only one value which is 6,
Hence, the given expression has only one solution.
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5x + 2y = 15
(–40, 19)
(–19, 55)
(19, –40)
(55, –19)
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Replacing y in the second equation gives;
5x+2(-3x-2)=15
5x-6x-4=15
-x-4=15
-x=19
x=-19
y=-3(-19)-2
y=57-2
y=55
(-19, 55)
4 / 9/10
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Answer:
4 × 10/9 = 40/9 is the solution
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Here we go
More than one way possible :
b) (y-1)^2 = 20(x-3)
c) (y-1)^2 = -20(x-3)
d) (x-3)^2 = 20(y-1)
Answers
Answer with Step-by-step explanation:
We have to find:
the standard form of the equation of the parabola that has a vertex of (3, 1) and a directrix of x = –2
General form of Parabola that opens left or right:
(y−k)²=4p(x−h)
Vertex =(h,k)
Directrix: x=h−p
Here, h=3,k=1 and h-p=-2 i.e. p=h+2=5
Hence, equation of parabola in this case equals
(y-1)²=4×5(x-3)
i.e. (y-1)²=20(x-3)
Hence, correct option is:
b) (y-1)²=20(x-3)
Remenber:
if S=(0,0) y²=2px then F=(p/2,0 and d:x=-p/2
Let's pose
x'=x-3
y'=y-1 axes passing by the point (3,0) in base (x,y) and (0,0) in base (x',y')
y'²=2p'x'
d': x'=-5=-p'/2 ==> p'=10 and y²=20x'
Returning in base (x,y) : (y-1)²=20(x-3)
Answer B