A bag contains 4 oranges, 3 grapefruits, and 8 tangerines. A piece of fruit is chosen from the bag at random. What is the probability that a grapefruit is NOT chosen?

Answers

Answer 1

Answer: What you’ll have to do is find the probability of the oranges and the tangerines. There is a total is 15 fruit. 12 of those are not grapefruit. You’ll then have to find the percentage of 12/15.

12 is divided by 15, then multiplied by 100.

12 divided by 15 = 0.08

0.08 x 100 = 80

There is an 80% chance that a grapefruit will not be picked.

Answer 2

Answer:

Answer:

80% converted into a fraction is 4/5

the grapefruit has a probability of not being chosen 4/5 times

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1. Given f(x) = 3x – 4 and g(x)=–2x+7 evaluate:
(fog)(5)

Answers

Answer:

(f o g)(5) = -13

General Formulas and Concepts:

Pre-Alg

Order of Operations: BPEMDAS

Algebra I

Composition of functions

Step-by-step explanation:

Step 1: Define

f(x) = 3x - 4

g(x) = -2x + 7

(f o g)(5) is f(g(5))

Step 2: Find composite function

Substitute: (f o g)(x) = 3(-2x + 7) - 4
Distribute: (f o g)(x) = -6x + 21 - 4
Combine like terms: (f o g)(x) = -6x + 17

Step 3: Solve

Substitute: (f o g)(5) = -6(5) + 17
Multiply: (f o g)(5) = -30 + 17
Add: (f o g)(5) = -13

49 increased by twice a number m

Answers

49+2x
Increase means “go up” which is another way to say addition
Twice means “two times” or “doubled”
A number would be a variable since it’s unknown

Hopefully this helps...

Answer:

49+2m

Step-by-step explanation:

49 is increased by twice a number m

Hope this helps!

Of the flowers on Jill's front lawn,2/5 are tulips. Of the tulips,5/8 are yellow. What fraction of the flowers on Jill's front lawn are yellow tulips. A 18 B 1/4 C 1/2 D 7/13

Answers

2/5 of the flowers are tulips, 5/8 of the tulips are yellow. Yellow tulpis are 5/8 of 2/5 of the flowers.

$(5)/(8) \ of \ (2)/(5)=(5)/(8) * (2)/(5)=(1)/(8) * (2)/(1)=(2)/(8)=\boxed{(1)/(4)} \Leftarrow \hbox{answer B}$

Answer:

1/4

Step-by-step explanation:

Find the roots of... X^2+10X+34

Answers

$x^2+10x+34=0\n\nx^2+2\cdotx\cdot5+5^2+9=0\n\n(x+5)^2=-9\ \ \ \Rightarrow\ \ \ no\ real\ solution\n\n(x+5)^2=9\cdot i^2\ \ \ \Rightarrow\ \ \ ( x+5=3i\ \ \ \ \ \ \ or\ \ \ \ \ \ \ \ x+5=-3i)\n\nx_1=-5+3i,\ \ \ \ \ x_2=-5-3i\ \ \ \rightarrow\ \ \ two\ complex\ numbers\ solution$

$x^(2) +10x+34=0\n \n \Delta=10^2-4.1.34=100-136=-36\n \n \boxed{x=(-10\pm√(-36))/(2)=(-10 \pm6i)/(2)=-5\pm3i}$

Carson has $450 in his bank account and deposits $70 per month out of his babysitting money. Construct a linear function that models Carson’s bank balance for any given month.

Answers

450 + 70x, where x is the number of months that carson works and 450 is the initial amount of money in his bank account

Solve log(2x+3) = 3

Answers

log_a x=z ⇔ a^z=x

In this case:
log (2x+3)=3 ⇔ 10³=2x+3

we have the following equation:
10³=2x+3
1000=2x+3
2x=1000-3
2x=997
x=997/2
x=498.5

Answer: x=498.5

Answer:

997/2

Step-by-step explanation:

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Which year falls in the 13th century BC? a. 1700 b. 7400 BC c. 565 AD d. 4000 BC

A set of equations is given below:Equation E: a = 5b + 1 Equation F: a = 3b + 4 Which statement describes a step that can be used to find the solution to the set of equations? Equation F can be written as 5b + 1 = 3b + 4. Equation F can be written as b + 1 = 3b + 4. Equation F can be written as a = 3(a − 1) + 4. Equation F can be written as a = 5(a − 4) + 1.

Solve for y.-5y - 9 = -(y - 1)Answer choices:a. -1/2b. -2 1/2c. -2d. -2/5I am brain-dead. :|