MATHEMATICS HIGH SCHOOL

(Need ASP)Divide.

(4x3+2x+1)÷(x+1)

4x2−4x+6+5x+1

4x2+4x−6−5x+1

4x2−4x+6−5x+1

4x2+4x+6−5x+1

Answers

Answer 1

Answer:

4x2+4x−6−5x+1 is the solution for (4x3+2x+1)÷(x+1)

What is Division?

A division is a process of splitting a specific amount into equal parts.

We need to solve,

(4x3+2x+1)÷(x+1)

We use Synthetic division, Synthetic division is a shorthand method for dividing a polynomial by a linear factor such as x + 3, and it's much simpler and faster.

Step 1: Set up the synthetic division.

Step 2: Bring down the leading coefficient to the bottom row.

Step 3: Multiply by the value just written on the bottom row.

Step 4: Add the column created in step 3.

We get 4x2+4x−6−5x+1.

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Answer 2

Answer:

Answer:

Step-by-step explanation:

(4x^3+2x+1)÷(x+1)

Using synthetic division is

4x^2-4x+6- 5/x+1

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⚠️I NEED THE ANSWER RIGHT NOW!! I WILL GIVE BRAINLIST!⚠️Subtract 5/6−(-4/9).

1 5/18

7/18

-7/18

-1 5/18

Answers

Answer:

15/18+8/18

23/18=15/18

Step-by-step explanation:

Hello!

Your answer is A. or 1 5/8!

Hopefully this helps! :D

Which expression is a difference of cubes? 9w^33-y^12 18p^15-q^21 36a^22-b^16 64c^15- a^26

Answers

we know that

A polynomial in the form $a^(3)-b^(3)$ is called adifference of cubes. Both terms must be a perfect cubes

Let's verify each case to determine the solution to the problem

case A) $9w^(33) -y^(12)$

we know that

$9=3^(2)$ ------> the term is not a perfect cube

$w^(33)=(w^(11))^(3)$ ------> the term is a perfect cube

$y^(12)=(y^(4))^(3)$ ------> the term is a perfect cube

therefore

The expression $9w^(33) -y^(12)$ is not a difference of cubes because the term $9$ is not a perfect cube

case B) $18p^(15) -q^(21)$

we know that

$18=2*3^(2)$ ------> the term is not a perfect cube

$p^(15)=(p^(5))^(3)$ ------> the term is a perfect cube

$q^(21)=(q^(7))^(3)$ ------> the term is a perfect cube

therefore

The expression $18p^(15) -q^(21)$ is not a difference of cubes because the term $18$ is not a perfect cube

case C) $36a^(22) -b^(16)$

we know that

$36=2^(2)*3^(2)$ ------> the term is not a perfect cube

$a^(22)$ ------> the term is not a perfect cube

$b^(16)$ ------> the term is not a perfect cube

therefore

The expression $36a^(22) -b^(16)$ is not a difference of cubes because all terms are not perfect cubes

case D) $64c^(15) -a^(26)$

we know that

$64=2^(6)=(2^(2))^(3)$ ------> the term is a perfect cube

$c^(15)=(c^(5))^(3)$ ------> the term is a perfect cube

$a^(26)$ ------> the term is not a perfect cube

therefore

The expression $64c^(15) -a^(26)$ is not a difference of cubes because the term $a^(26)$ is not a perfect cube

I'm adding a new case so I can better explain the problem

case E) $64c^(15) -d^(27)$

we know that

$64=2^(6)=(2^(2))^(3)$ ------> the term is a perfect cube

$c^(15)=(c^(5))^(3)$ ------> the term is a perfect cube

$d^(27)=(d^(9))^(3)$ ------> the term is a perfect cube

Substitute

$64c^(15) -d^(27)=((2^(2))(c^(5)))^(3)-(d^(9))^(3)$

therefore

The expression $64c^(15) -d^(27)$ is a difference of cubes because all terms are perfect cubes

The expression $\boxed{64{c^(15)} - {d^(27)}}$ is a difference of cubes.

Further Explanation:

Given:

The options are as follows,

(a). $9{w^(33)} - {y^(12)}$

(b). $18{p^(15)} - {q^(21)}$

(c). $36{a^(22)} - {b^(16)}$

(d). $64{c^(15)} - {a^(26)}$

(e). $64{c^(15)} - {d^(27)}$

Calculation:

The cubic formula can be expressed as follows,

$\boxed{{a^3} + {b^3} = \left( {a + b} \right)\left( {{a^2} - ab + {b^2}} \right)}$

The expression is $9{w^(33)} - {y^(12)}.$

9 is not a perfect cube of any number, ${w^(33)}$ can be written as ${\left( {{w^(11)}} \right)^3}$ and ${y^(12)}$ can be represents as ${\left( {{y^4}} \right)^3}.$

$9{w^(33)} - {y^(12)}$ cannot be written as the difference of cube. Option (a) is not correct.

The expression is $18{p^(15)} - {q^(21)}.$

18 is not a perfect cube of any number, ${p^(15)}$ can be written as ${\left( {{p^5}} \right)^3}$ and ${q^(21)}$ can be written as ${\left( {{q^7}} \right)^3}.$

$18{p^(15)} - {q^(21)}$ cannot be written as the difference of cube. Option (b) is not correct.

The expression is $36{a^(22)} - {b^(16)}.$

36 is not a perfect cube of any number, ${a^(22)}$ is not perfect cube and ${b^(16)}$ is not a perfect cube.

$36{a^(22)} - {b^(16)}$ cannot be written as the difference of cube. Option (c) is not correct.

The expression is $64{c^(15)} - {a^(26)}.$

64 can be written as ${\left( {{2^2}} \right)^3}, {a^(26)}$ is not perfect cube and ${c^(15)}$ can be written as ${\left( {{c^5}} \right)^3}.$

$64{c^(15)} - {a^(26)}$ cannot be written as the difference of cube. Option (d) is not correct.

The expression is $64{c^(15)} - {d^(27)}.$

64 can be written as ${\left( {{2^2}} \right)^3}, {d^(27)}$ can be written as ${\left( {{d^9}} \right)^3}$ and ${c^(15)}$ can be written as ${\left( {{c^5}} \right)^3}.$

$\boxed{64{c^(15)} - {d^(27)} = {{\left( {{2^2}{c^5}} \right)}^3} - {{\left( {{d^9}} \right)}^3}}$

$64{c^(15)} - {d^(27)}$ can be written as the difference of cube. Option (e) is correct.

The expression $\boxed{64{c^(15)} - {d^(27)}}$ is a difference of cubes.

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Answer details:

Grade: High School

Subject: Mathematics

Chapter: Exponents and Powers

Keywords: Solution, factorized form, expression, difference of cubes, exponents, power, equation, power rule, exponent rule.

Point E is located at (−2,4) and point F is located at (5,10) . What are the coordinates of the point that partitions the directed line segment EF⎯⎯⎯⎯⎯ in a 7:3 ratio? Enter your answer, as decimals, in the boxes.

Answers

Solution:

Coordinates of Point E and F are (-2,4) and (5,10).

Suppose the Point M(x,y), divides the Line Segment Joining E (-2,4) and F (5,10) in the 7:3 ratio.

So, EM: MF= 7:3

Formula for internal Division

$x=(mx_(2)+nx_(1))/(m+n), y=(my_(2)+ny_(1))/(m+n)$

$x=(3 * (-2) +7 * 5)/(3 +7),\n\n x=(-6 +35)/(10)\n\nx=(29)/(10)\n\n y =(3 * 4 +7 * 10)/(3+7)\n\n y=(12+70)/(10)\n\n y=(82)/(10)$

So,we get

x= 2.9

and , y= 8.2

He then unpacked 192 packs of frozen peas from 8 boxes.How many packs of frozen peas were in each box?

Answers

The question involves dividing the total number of packs (192) by the total number of boxes (8). The answer is 24 packs per box.

The subject of this question is Mathematics, and it's about the Division concept.

If a total of 192 packs of frozen peas were taken out from 8 boxes, we need to find out how many packs were in each box originally.

This can be done by dividing the total number of packs by the total number of boxes.

Therefore, you would do the calculation: 192 ÷ 8, which equals 24. So, there were 24 packs of frozen peas in each box.

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All we have to do is divide 192 by 8

192 ÷ 8
$(192)/(8)$ = 24

there were 24 packs of frozen peas in each box

Find the GCF of the following monomials. -50m 4 n 7 and 40m 2 n 10

Answers

Answer:

$10m^2n^7$

Step-by-step explanation:

$-50m^4n^7 \ and \ 40m^2n^(10)$

WE need to find GCf for both monomials. GCF is the greatest common factor

$-50 ->-1 \cdot 5 \cdot 5 \cdot 2$

$40 ->2 \cdot 2 \cdot 5 \cdot 2$

GCF is 2 times 5 =10

GCF of exponent is the lowest exponent

GCF of m^4 and m^2 is m^2

GCF of n^7 and n^10 is n^7

$-50m^4n^7 \ and \ 40m^2n^(10)$

GCF is $10m^2n^7$

2 , 1, , 2 if it helps <3

PLEASE HELP ME!!!!!!!!! I'LL MARK YOU BRAINLIEST IF YOU ANSWER THESE CORRECTLY!Find the value of x

Answers

Answer:

question 4 ... x = -11

question 5.... x = -7

question 6... x = 12

question 7.... x = 10

Step-by-step explanation:

number 4

note : the total angle of a triangle is 180 degrees

hence solve this by creating an equation

x + 51 + 60 + 80 = 180

x = 180 - 80 -60-51

x = -11

number 5

note : the total angle of a triangle is 180 degrees

hence solve this by creating an equation

remember that a right angle is 90 degrees

45 + 52+x + 90 = 180

x = 180 - 90 -52 -45

x = -7

number 6

note : the total angle of a triangle is 180 degrees

hence you can solve this by creating an equation

53 + 39+ 4+7x = 180

now make x the subject of the equation

7x = 180 - 53 - 39 - 4

7x = 84

x = 84/7

x = 12

number 7

note : the total angle of a triangle is 180 degrees

hence solve this by creating an equation

6x - 5 + 5x + 75 = 180

now make x the subject of the equation

6x +5x = 180 - 75 + 5

11x = 110

x = 110/11

x= 10

As the angles of the triangle are equal to 180
Therefore,
180=53+39+4+7x
180-96=7x
84=7x
X=12
Part 2
180=5x+6x-5+75
180-70=11x
110=11x
X=10
This is for page 1 questions

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