Among electromagnetic waves, UV rays are most dangerous because exposure to these radiation cause serious problems in living organism. Therefore, waves from lowest frequency to highest frequency are radio waves, infrared rays, ultraviolet rays and gamma rays.
Electromagnetic wave is a wave which contain two component one is electric component and other is magnetic component. The electric and magnetic component are perpendicular to each other. There are so many wave that comes under electromagnetic wave like infrared wave , radio wave.
There is a relation between energy of wave. frequency of wave, and wavelength of wave
Mathematically,
E=hc/λ
where,
E = energy of electromagnetic wave
h is planks constant having value 6.67×10⁻³⁴js
c is speed of light that is 3×10⁸m/s
λ is the wavelength of electromagnetic wave
Waves from lowest frequency to highest frequency are radio waves, infrared rays, ultraviolet rays and gamma rays.
Therefore, waves from lowest frequency to highest frequency are radio waves, infrared rays, ultraviolet rays and gamma rays.
To know more about electromagnetic wave, here:
#SPJ2
When ice is placed in hot water the hot water loses its own heat while the cold water from the ice gets heat.
Answer:when you add ice to hot water, the ice melts while the hot water cools. The exchange of heat energy from the hot water causes the ice to melt.
Explanation:
Hope this helped :)
Blue light is emitted when an electron in a He+ ion falls from the energy level n=4 to n=1. This is because the energy difference between these levels is similar to that in a hydrogen atom when blue light is emitted (from n=5 to n=2).
The energy of the emitted photon when an electron transitions between energy levels in an atom is determined by the difference between the energy levels it transitions between. This is described by the formula: E = hν, where E stands for energy, h stands for Planck's constant, and ν stands for frequency. The color of the emitted light, or the wavelength, is determined by the energy of the photon.
For blue light to be emitted when an excited electron falls from n=4 in a He+ ion, it must fall into n=1. This is because the energy gap between the n=4 and n=1 levels in a He+ ion is similar to that between the n=5 and n=2 levels in a hydrogen atom, which results in the emission of blue light.
#SPJ12
In a helium ion (He+), an electron would need to fall from n=4 to n=1 to emit a photon of blue light, similar to the photon emitted when an electron in a hydrogen atom falls from n=5 to n=2.
According to the Bohr model of atoms, when an electron falls from a higher to a lower energy level, a photon is emitted. The energy (and therefore color) of the photon corresponds to the energy difference between the two energy levels. In the case of your question, an excited electron in a hydrogen atom falls from n=5 to n=2 and emits a photon of blue light.
If an electron in an excited helium ion (He+) falls from the n=4 level, to emit a photon of similar energy (and thus color), it must fall to a level that yields a similar energy difference. Based on the energy levels of helium and hydrogen, the electron in the He+ ion would need to fall to n=1 to emit a photon of similar energy to the blue light from the hydrogen atom, given that the energy difference in He+ ion is larger than in hydrogen atom for the same quantum numbers due to its greater nuclear charge.
#SPJ11
The correct option is C.
An atom can be either in the ground state or in an excited state. An atom is said to be in the ground state, if the total energy of its electron can not be lowered by moving one or more electrons into different orbitals. At the ground state, the electrons in the atom have the lowest energy possible and they are stable. On the other hand, an atom is said to be in an excited state, if the energy of its electrons can be lowered by transferring one or more electrons into different orbitals. An atom in an excited state has more energy and is less stable.