Given the balanced equation representing a redox reaction:2Al + 3Cu2+ --> 2Al3+ + 3Cu
Which statement is true about this reaction?
(1) Each Al loses 2e- and each Cu2+ gains 3e-
(2) Each Al loses 3e- and each Cu2+ gains 2e-
(3) Each Al3+ gains 2e- and each Cu loses 3e-
(4) Each Al3+ gains 3e- and each Cu loses 2e-

Answers

Answer 1

Answer: From the given balanced chemical reaction, it can be seen that each aluminum atom gains loses 3 electrons. Also, each copper atoms gains 2 electrons. The choice that would best give us the described scenario above is choice number 2. That is Each Al loses 3e- and each Cu gains 2e-.

Answer 2

Answer: The correct answer is option (2) i.e. Each Al loses 3e- and each Cu^2+ gains 2e-When an atom X, loses an electron, it becomes, X^1+When an atom X, loses two electrons, it becomes, X^2+When an atom X, gains an electron, it becomes, X^1-When an atom X, gains two electrons, it becomes, X^2-So, Here, 2Al + 3Cu^2+ --> 2Al^3+ + 3Cu,When each Al, loses three electrons, it becomes, Al^3+When each Cu^2+, gains two electrons, it becomes, Cu^2+^2- = Cu

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James is preparing three solutions of salt water. Each of the solutions has the same amount of water in the beaker and a different amounts of salt. In the first beaker, there is one scoop of salt in the beaker. The second beaker has two scoops of salt. The third beaker has three scoops of salt. Which of the beakers is the most concentrated solution?

Answers

the third beaker: since it has the most amount of salt and the same amount of water as all the other beakers . So it has the highest concentrated amount :)

Answer: the beaker 3

Explanation: that what it said on usatestprep

Which organic compound is unsaturated?(1) 2-methylbutane (3) 2-hexanol
(2) 2-chloropropane (4) 2-pentene

Answers

The answer is (4) 2-pentene. The pentene belongs to olefin and has double bonds between the carbon atoms. And the other three belongs to alkane which don't have double bonds. So the pentene is unsaturated.

How much heat energy is needed to raise the temperature of 59.7g of cadmium from 25°C to 100°C? The specific heat of cadmium is 0.231 J/g °C.

Answers

Heat energy can be calculated by using the specific heat of a substance multiplying it to the mass of the sample and the change in temperature. It is expressed as:

Energy = mCΔT
Energy = 59.7 (0.231) (100-25)
Energy = 1034.30 J

The amount of heat energy needed to raise the temperature of 59.7g of cadmium from 25°C to 100°C is 1,034.3J.

How to calculate amount of energy?

The amount of heat energy needed to raise a temperature can be calculated using the following expression;

Q = mc∆T

Where;

Q = amount of energy released or absorbed
m = mass of substance
c = specific heat capacity
∆T = change in temperature

According to this question, 59.7g of cadmium is needed to be raised from 25°C to 100°C. The amount of heat needed can be calculated as follows:

Q = 59.7 × 0.231 × (100 - 25)

Q = 1,034.3J

Learn more about energy at: brainly.com/question/33447128

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Boyle’s Law a. q = mcΔT
b. q = Hvm
c. P₁V₁ = P₂V₂
d. D = m/V
e. K = C + 273

Answers

the answer is C! We actually just learned this in chemistry xD

Explain What Conservation Is And Give Two Examples Of How You Can Conserve Water .

Answers

>Conservation is, preservation, protection, or restoration of the natural environment, natural ecosystems, vegetation, and wildlife

>Two examples are;

* turn off the water from the bathroom thing the sink while brushing your teeth or something

* If you don't drink all your water from the water bottle use it to water a plant or something ✌

Answer:

Conservation is using a resource wisely so it will not be used up. Possible examples include: take shorter showers; fill the bathtub only halfway; do not run water while scrubbing vegetables or brushing teeth; water lawns early in the morning or late in the afternoon; and run the washing machine only for a full load.

Explanation:

What happens in a reduction half-reaction?elements gain electrons
elements lose electrons
oxygen is added
oxygen is lost

Answers

Answer: Option (a) is the correct answer.

Explanation:

A reduction-half reaction is defined as the reaction in which there occurs gain of one or more number of electrons by a specie or element.

Or, in a reduction-half reaction there occurs loss of oxygen if it is present in a reaction.

But in a reduction-half reaction loss of electrons will always take place.

For example, $CuO + Mg \rightarrow Cu + MgO$

Reduction-half reaction: $Cu^(2+) + 2e^(-) \rightarrow Cu$

So here, oxidation state of copper is changing from +2 to 0. Also, loss of oxygen is occurring in the reaction equation.

Oxidation-half reaction: $Mg \rightarrow Mg^(2+) + 2e^(-)$

Thus, we can conclude that in a reduction half-reaction elements gain electrons.

The answer is elements gain electrons. Oxidation reduction is elements lose electrons. And oxygen is added/lost can be a type of oxidation/reduction reaction.

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