How can we determine if energy was released or absorbed during a reaction?a) Measure the mass of the reaction at the beginning and end

b) Measure the temperature of the reaction at the beginning and end

c) Measure the volume of the reaction at the beginning and end

d) Measure the density of the reaction at the beginning and end

Answers

Answer 1
Answer: The answer was is b measure the temp of the reaction at the beginning and end

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What is the name of the giant bubble of charged gas that surrounds the sun?a. heliosphere
b. galaxy
c. Kuiper Belt
d. Oort Cloud

Answers

The correct answer is A. The gin bubble of charged gas around the sun is called the heliosphere. Basically, the heliosphere is a sphere of helium. This is a region where the solar wind is said to have an influence.

Which pair below describes isotopes of the same element? A) an atom with 6 protons and 8 neutrons - an atom with 8 protons and 6 neutrons B) an atom with 6 protons and 6 neutrons - an atom with 6 protons and 7 neutrons C) an atom with 8 protons and 8 neutrons - an atom with 7 protons and 8 neutrons D) an atom with 7 protons and 6 neutrons - an atom with 6 protons and 6 neutrons

Answers

Answer: The atom with 6 protons and 6 neutrons and an atom with 6 protons and 7 neutrons are the isotopes of same element.

Explanation:

Isotopes are defined as the chemical species that belong to the same element but differ in their mass number.

This also means that the chemical species have same number of protons and electrons but different number of neutrons.

Atomic number is defined as the number of protons or electrons that are present in a neutral atom.

Atomic number = number of protons = number of electrons

Mass number is defined as the sum of number of protons and neutrons that are present in an atom.

Mass number = Number of protons + Number of neutrons

From the given options:

The elements having same number of protons will be the isotopes of same element.

Hence, the atom with 6 protons and 6 neutrons and an atom with 6 protons and 7 neutrons are the isotopes of same element.

Which statement best describes gamma radiation?(1) It has a mass of 1 and a charge of 1.
(2) It has a mass of 0 and a charge of –1.
(3) It has a mass of 0 and a charge of 0.
(4) It has a mass of 4 and a charge of +2.

Answers

The correct answer is option 3. Gamma radiation is a type of electromagnetic radiation which is characterized by having the smallest wavelength resulting to having the most energy in the electromagnetic spectrum. Gamma radiation has no mass and no charge.

At standard pressure, CH4 boils at 112 K and H2O boils at 373 K. What accounts for the higher boiling point of H2O at standard pressure?(1) covalent bonding (3) hydrogen bonding(2) ionic bonding (4) metallic bonding

Answers

The answer is (3) hydrogen bonding. This is a question of intermolecular forces. H2O is highly polar (the O—H bond is particularly polar since O is so electronegative), and CH4 is about as nonpolar as it gets. So, while H2O molecules are held together by relatively strong hydrogen bonds (which, keep in mind, are not actually bonds), CH4 molecules are held together by much weaker London dispersion/Van der Waals forces. Thus, it takes more thermal energy to separate H2O molecules, and H2O therefore has a higher boiling point.

Answer:

Hydrogen bonding

Explanation:

Castle learning

a clerk can sort 7 papers/minute. if there are 225 papers in an inch, how many hours will it take her to sort 125 inches of loose apper

Answers

Well if there is 225 lose papers to a single inch in order to find out how many loose papers the clerk has all together we will have to multiply 125 x 225.

125 x225 = 28125

The clerk has to sort 28125 papers in total.

Now she can sort 7 papers in a minute so now we divide 28125 by 7.

28125/7 = a rough estimate of 4018 minutes

The clerk will take about 66 hours and 58 minutes

Or 67 hours if you want to estimate

Calculate the percent by mass of the solute in each of the following aqueous solutions: (a) 5.50 g of NaBr in 78.2 g of solution, (b) 31.0 g of KCl in 152 g of water, (c) 4.5 g of toluene in 29 g of benzene.

Answers

Answer:

For a: The mass percent of NaBr is 7.03 %

For b: The mass percent of KCl is 16.94 %

For c: The mass percent of toluene is 13.43 %

Explanation:

To calculate the mass percentage of solute in solution, we use the equation:

\text{Mass percent of solute}=\frac{\text{Mass of solute}}{\text{Mass of solution}}* 100         .......(1)

  • For a:

We are given:

Mass of NaBr (Solute) = 5.50 g

Mass of solution = 78.2 g

Putting values in equation 1, we get:

\text{Mass percent of NaBr}=(5.50g)/(78.2g)* 100\n\n\text{Mass percent of NaBr}=7.03\%

Hence, the mass percent of NaBr is 7.03 %

  • For b:

We are given:

Mass of KCl (Solute) = 31.0 g

Mass of water (solvent) = 152 g

Mass of solution = (31.0 + 152) g = 183 g

Putting values in equation 1, we get:

\text{Mass percent of KCl}=(31.0g)/(183g)* 100\n\n\text{Mass percent of KCl}=16.94\%

Hence, the mass percent of KCl is 16.94 %

  • For c:

We are given:

Mass of toluene (Solute) = 4.5 g

Mass of benzene (solvent) = 29 g

Mass of solution = (4.5 + 29) g = 33.5 g

Putting values in equation 1, we get:

\text{Mass percent of toluene}=(4.5g)/(33.5g)* 100\n\n\text{Mass percent of toluene}=13.43\%

Hence, the mass percent of toluene is 13.43 %

Final answer:

To calculate the percent by mass of the solute in each aqueous solution, divide the mass of the solute by the mass of the solution and multiply by 100%

Explanation:

To calculate the percent by mass of the solute in each aqueous solution, you'll need to use the formula:

Percent by mass = (mass of solute/mass of solution) x 100%

For example, in solution (a) with 5.50 g of NaBr in 78.2 g of solution, the mass of the solute is 5.50 g and the mass of the solution is 78.2 g. Plugging these values into the formula gives:

Percent by mass = (5.50 g / 78.2 g) x 100% = 7.03%

Similarly, you can calculate the percent by mass for solutions (b) and (c) using the same formula.

Learn more about Calculating the percent by mass of solute in aqueous solutions here:

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