Find the volume of box in cm^3 whose dimensions are 0.40meters long, 12.0 cm wide and 50.0mm deep

Answers

Answer 1

Answer: thats a math question and the answer is 240 cm³.

V = l x w x h

0.40 x 12 x 50 = 240.

Related Questions

1. A sample of nitrogen occupies a volume of 250 mLat 298 K. What volume will it occupy at 268 K?
Consider this equilibrium:N2(g) + 3H2(g) 2NH3(g) + energy.Certain conditions provide less than 10% yield of NH3 at equilibrium. Which statement describes this equilibrium?
What happens when Ca(NO3)2 and Na2CO3 combine?
The light intensity of a source is 100 candelas. The illuminance on a surface is 4 lux. How far is the surface from the source?
What are the two categories of observations? a. qualitative and quantitative b. direct and indirect c. sensory and derived d. measured and deduced

Please! Which statement correctly describes glucose (C6H12O6)?
A)It is made of matter and contains twenty-four molecules.
B)It is an element made of three types of atoms.
C)It is an atom made up of carbon, hydrogen, and oxygen.
D)It is a compound made of twenty-four total atoms of three different elements.

Answers

Answer:

The correct answer is D)It is a compound made of twenty-four total atoms of three different elements

Explanation:

Glucose (C₆H₁₂O₆) is a molecule (not an atom neither an element, so the options B and C are not completely correct). It is composed by three different elements (oxygen: O, carbon: C and hydrogen: H), and it has twenty-four atoms in its molecule: (6 x C) + (12 x H) + (6 x O)= 24. So, the option D is the one that best describes glucose.

C) it is made up of carbon, hydrogen, and oxygen

D) it is a compound made of twenty-four total atoms of three different elements

they are both right but I would go with D

The lone pair of electrons in ammonia allows the molecule to: A.assume a planar structure. B.act as an oxidizing agent. C.act as a Lewis acid in water. D.act as a Lewis base in water.

Answers

Answer:

The correct option is: D.act as a Lewis base in water.

Explanation:

Ammonia is a hydride of nitrogen with the chemical formula NH₃. It is a colorless gas with a characteristic pungent smell. According to the VSEPR theory, it has a trigonal pyramidal structure.

In water, ammonia acts as a Lewis base due to the presence of lone pair on the nitrogen atom. Lewis bases are electron pair or lone pair donors.

In the following reaction, how many grams of NaBr will react with 311 grams of Pb(NO3)2?pb(no3)2(aq)+2NaBr(g) -> PbBr2(s) + 2NaNO3(aq)
The molar mass of NaBr is 102.9 grams and that of Pb(NO3)2 is 331.21 grams.

Answers

Answer: 193.4 grams

Explanation: According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number $6.023* 10^(23)$ of particles.

$Pb(NO_3)_2(aq)+2NaBr(g)\rightarrow PbBr_2(s)+2NaNO_3(aq)$

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

${\text{Number of moles} of Pb(NO_3)_2}=(311g)/(331.21gmol)=0.94moles$

According to stoichiometry

1 mole of $Pb(NO_3)_2$ reacts with 2 moles of $NaBr$

0.94 moles of $Pb(NO_3)_2$ will react with= $(2)/(1)* 0.94=1.88moles$ of $NaBr$

Mass of $NaBr=moles* {\text {molar mass}}=1.88* 102.9=193.4g$

Answer:

193.24g

Explanation:

Step 1:

The balanced equation for the reaction. This is illustrated below:

Pb(NO3)2(aq) + 2NaBr(g) -> PbBr2(s) + 2NaNO3(aq)

Step 2:

Determination of the masses of Pb(NO3)2 and NaBr that reacted from the balanced equation. This is illustrated below:

Molar Mass of Pb(NO3)2 = 331.21g/mol

Molar Mass of NaBr = 102.9g/mol

Mass of NaBr from the balanced equation = 2 x 102.9 = 205.8g.

From the balanced equation,

Mass of Pb(NO3)2 that reacted = 331.21g

Mass of NaBr that reacted = 205.8g

Step 3:

Determination of the mass of NaBr that reacted with 311g of Pb(NO3)2. This is illustrated below:

From the balanced equation above,

331.21g of Pb(NO3)2 reacted with 205.8g of NaBr.

Therefore, 311g of Pb(NO3)2 will react with = (311x205.8)/331.21 = 193.24g of NaBr.

From the calculations made above, 193.24g of NaBr will react with 311g of Pb(NO3)2

Which elements can form acidic compounds? Check all that apply. sulfur rubidium arsenic selenium silicon xenon antimony

Answers

The elements that can form acidic compounds are; sulfur, arsenic, selenium, antimony, silicon.

Acidic compounds are formed by nonmetals. Metallic elements form basic compounds. This means that rubidium does not form acidic compounds since it is a metal.

Also, xenon does not form compounds because it is a noble gas. Noble gases do not react with other elements to form compounds.

However; sulfur, arsenic, selenium, antimony, silicon are nonmetals and they form acidic compounds.

Learn more: brainly.com/question/14072179

The correct answer is Sulfur, Arsenic, selenium, silicon, and antimony.

A student adds a tablespoon of sugar to a glass containing tea and ice cubes. The mixture is then stirred until all the sugar dissolves. Which observation is a clue that the student's final mixture is heterogeneous
A. Some ice cubes are floating in the tea
B. The sugar crystals are no longer visible in the tea
C. The mixture looks the same throughout
D. Some water droplets form on the outside of the glass
The subject is science

Answers

Answer:

The correct option is;

A. Some ice cubes are floating in the tea

Explanation:

A heterogenous mixture is one that is made up of more than one clearly identifiable phase of matter (such as solid and liquid, liquid and gas, gas and solid, or solid, liquid and gas combined) and therefore having non-uniform composition, which varies from one section to another within the mixture.

Ice cubes which are solids being observable on the surface of the mixture provides clue that the student has made an heterogenous mixture.

What is the molarity of a solution that contains 0.50 mole of Naoh in 0.5p liter of solution

Answers

The concentration pertains to the molarity of the solution with an equation of mol of solution per liter of solvent.

M (molarity) = moles of solute/L of solvent

M (molarity) = 0.5 mol NaOH / 0.5 L

M (molarity) = 1 M NaOH

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