a person pushing a stroller starts from rest, uniformly accelerating at a rate of 0.500m/s^2. what is the velocity of the stroller after it has traveled 4.75m?

Answers

Answer 1

Answer: You're going to use the constant acceleration motion equation for velocity and displacement:
(V)final²=(V)initial²+2a(Δx)

Given:
a=0.500m/s²
Δx=4.75m
(V)intial=0m
(V)final= UNKNOWN

(V)final= 2.179m/s

Answer 2

Answer:

Hello!

A person pushing a stroller start from rest uniformly accelerating at a rate of 0.500 m/s². What is the velocity of the stroller after it traveled 4.75 m ?

We have the following data:

a (acceleration) = 0.500 m/s²

Vf (final velocity) = ? (in m/s)

Vi (initial velocity) = 0 m/s

Δx (displacement) = 4.75 m

Solving:

Let's apply the Torricelli Equation, to find the velocity of the stroller, let's see:

$V_f^2 = V_i^2 + 2*a*\Delta{x}$

$V_f^2 = 0^2 + 2*0.500*4.75$

$V_f^2 = 0 + 4.75$

$V_f^2 = 4.75$

$V_f = √(4.75)$

$\boxed{\boxed{V_f \approx 2.18\:m/s}}\:\:\:\:\:\:\bf\blue{\checkmark}\bf\green{\checkmark}\bf\red{\checkmark}$

Answer:

The velocity of the stroller is approximately 2.18 m/s

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$\bf\red{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}$

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You're conducting a physics experiment on another planet. You drop a rock from a height of 1 m and it hits the ground 0.4 seconds later. What is the acceleration due to gravity on this planet?

Answers

First, we must assume that the planet has no atmosphere, so there's no air resistance,
and the behavior of the rock is the result of gravity and nothing else.

The formula for the distance covered by anything that accelerates from rest is

D = (1/2) (acceleration) (time)²

In this problem, we're given the distance and the time, and we want to find the acceleration.

1 = (1/2 acceleration) x (0.4)²

0.4² = 0.16

1 = (1/2 times 0.16) (acceleration)

1 = 0.08 acceleration

Acceleration = 1/0.08 = 12.5 meters per second²

That's about 27% greater than Earth's gravity.

Answer:

12.5

Explanation:

Someone please help me

Answers

Answer:

D or 49.7°

Explanation:

You are given the equation and all the information you need, so you simply need to understand what the question asks for and answer appropriately. Notice that the light wave travels from the water to air. This means that water should be labelled with a "1" as it comes prior to air, which should be labeled "2". Thus, all you need to do, is plug and chug:

$\theta_2 = sin^(-1)((n_1sin(\theta_1))/(n_2)) = sin^(-1)(((1.33)sin(35))/(1))$

$\theta_2 = sin^(-1)(0.763) = 49.7^o$

And, therefore, your answer is D, 49.7°.

Which statement best compares potential and kinetic energy?. . A) Objects always have more potential energy than kinetic energy..
B)Only kinetic energy increases when the velocity of an object increases. .
C)Only potential energy decreases when an object’s height increases..
D)Objects always have more kinetic energy than potential energ

Answers

Which statement best compares potential and kinetic energy?

Answer: Out of all the options shown above the one that represents the statement that best compares potential and kinetic energy is answer choice B) Only kinetic energy increases when the velocity of an object increases. The reason being that kinetic energy is the energy of any object in motion while potential energy is the stored energy.

I hope it helps, Regards.

Taking into account the definition of kinetic and potencial energy, only kinetic energy increases when the velocity of an object increases.

Kinetic energy

Kinetic energy is a form of energy. It is defined as the energy associated with bodies that are in motion and this energy depends on the mass and speed of the body.

Kinetic energy is defined as the amount of work necessary to accelerate a body of a given mass and at rest, until it reaches a given speed. Once this point is reached, the amount of accumulated kinetic energy will remain the same unless there is a change in speed or the body returns to its state of rest by applying a force.

Kinetic energy is represented by the following formula:

Ec= ½ mv²

where:

Ec is the kinetic energy, which is measured in Joules (J).
m is the mass measured in kilograms (kg).
v is the speed measured in meters over seconds (m/s).

Potential energy

On the other hand, potential energy is the energy that measures the ability of a system to perform work based on its position. In other words, this is the energy that a body has at a certain height above the ground.

Gravitational potential energy is the energy associated with the gravitational force. This will depend on the relative height of an object to some reference point, the mass, and the force of gravity.

So for an object with mass m, at height h, the expression applied to the gravitational energy of the object is:

Ep= m×g×h

where:

Ep is the potential energy in joules (J).
m is the mass in kilograms (kg).
h is the height in meters (m).
g is the acceleration of fall in m/s² (approximately 9.81 m/s²).

Statement that best compares potential and kinetic energy

In this case, considering all of the above, the correct answer is option B) Only kinetic energy increases when the velocity of an object increases.

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What is the kinetic energy of a 1.40 kg discus with a speed of 22.5 m/s?

Answers

The kinetic energy of a 1.40 kg discus with a speed of 22.5 m/s is 354.375 joule.

What is kinetic energy?

The energy that an object has because it is moving is known as kinetic energy in physics. It is described as the amount of effort required to accelerate a body of a specific mass from rest to its specified velocity. The body keeps its kinetic energy after gaining it during acceleration, barring changes in speed.

Up until a change in speed, the body maintains the kinetic energy it gained during acceleration.

Mass of the discus: M = 1.40 kg.

Speed of the discus: v = 22.5 m/s.

Hence, the kinetic energy of the discus= 1/2×Mv²

= 1/2 × 1.40 × 22.5² joule

= 354.375 joule.

Hence, the kinetic energy of a 1.40 kg discus with a speed of 22.5 m/s is 354.375 joule.

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apply E=(mv^2)/2 . It will give the answer.

Which statement best describes how light waves travel in a uniform medium. A. in straight lines. . B. in extending circles. . C. in bent lines. . D. in shrinking ripples

Answers

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The answer is a. Straight lines

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